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Find a parametrization for the circle \(x^{2}+y^{2}=1\) starting at \((1,0)\) and moving counterclockwise to the terminal point \((0,1),\) using the angle \(\theta\) in the accompanying figure as the parameter.

Short Answer

Expert verified
Parametrize the circle as \(x(\theta) = \cos \theta, y(\theta) = \sin \theta\) for \(\theta \in [0, \pi/2]\).

Step by step solution

01

Understand the Circle Equation

The circle given by the equation \(x^2 + y^2 = 1\) is a unit circle centered at the origin (0,0) with radius 1. We want to express the points on this circle using a parameter, \(\theta\), representing an angle.
02

Parametrization Using Trigonometry

To express the circle in terms of \(\theta\), we use the fact that any point \((x, y)\) on the unit circle can be represented as \((\cos \theta, \sin \theta)\). This is because, by the unit circle definition, \(\cos^2 \theta + \sin^2 \theta = 1\). So for the circle \(x^2 + y^2 = 1\), a parametrization of the circle is \(x(\theta) = \cos \theta\) and \(y(\theta) = \sin \theta\).
03

Verify the Starting and Ending Points

The problem states that the curve should begin at \((1, 0)\) and end at \((0, 1)\). That's satisfied if the parameter \(\theta\) starts at \(0\) and ends at \(\pi/2\), because:\- \(\theta = 0\), \(x = \cos 0 = 1\), \(y = \sin 0 = 0\) corresponds to the point \((1, 0)\), and\- \(\theta = \pi / 2\), \(x = \cos(\pi/2) = 0\), \(y = \sin(\pi/2) = 1\) corresponds to the point \((0, 1)\).
04

Validating the Direction

To confirm counterclockwise movement from \((1, 0)\) to \((0, 1)\), notice that as \(\theta\) increases from 0 to \(\pi/2\), the sine value increases from 0 to 1 while the cosine decreases from 1 to 0. This reflects a movement along the unit circle in the positive (counterclockwise) direction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Functions
Trigonometric functions, namely sine and cosine, are crucial in understanding the parametrization of circles. These functions arise from the relationships in a right-angled triangle inscribed within a unit circle. The unit circle is a circle with a radius of 1, centered at the origin (0,0) in a Cartesian coordinate system. For any angle \( \theta \), the coordinates of the point on the unit circle are given by \( (\cos \theta, \sin \theta) \). This means:
  • \( \cos \theta \) represents the horizontal distance from the origin.
  • \( \sin \theta \) represents the vertical distance from the origin.
These relations hold true because, in a unit circle, the length of the hypotenuse (or the radius) is always 1, hence simplifying the trigonometric relationships.Understanding these core trigonometric functions is essential when working through equations involving rotational or circular movement, as they allow us to translate angular movement into Cartesian coordinates. This ability to move between different forms of expression is invaluable in both mathematics and its applications across physics and engineering.
Parametric Equations
Parametric equations are a powerful way to represent curves and paths in a plane. Instead of expressing \( y \) directly as a function of \( x \), we use a third variable, a parameter \( \theta \), to express both \( x \) and \( y \). This method is particularly useful in cases where describing the path of an object or drawing complex shapes involves movements that are not easily captured by traditional functions.For a circle, as seen with the unit circle equation \( x^2 + y^2 = 1 \), the parameter \( \theta \) can represent an angle measure that allows us to describe movement around the circle:
  • \( x(\theta) = \cos \theta \)
  • \( y(\theta) = \sin \theta \)
Using these parametric equations, we can easily visualize continuous motion from point to point along a circle, such as moving from \( (1, 0) \) to \( (0, 1) \), by simply varying \( \theta \) from 0 to \( \pi/2 \).Parametric equations offer a flexible way to model many physical systems and are extensively used in fields like physics, engineering, and computer graphics, where complex paths and motions are regularly encountered.
Circle Equation
A circle equation provides a concise mathematical representation of all the points lying at a specific distance, known as the radius, from a common center. For any circle with center at \((h, k)\) and radius \(r\), the general equation is:\[ (x - h)^2 + (y - k)^2 = r^2 \]In the particular case of a unit circle centered at the origin \((0,0)\), this simplifies to the equation \( x^2 + y^2 = 1 \). Here, every point \((x, y)\) satisfying the equation lies exactly one unit from the center, forming a perfect circle.The elegance of the circle equation allows us to explore several mathematical properties concerning symmetry and distance. This is foundational to understanding more complex geometrical shapes and systems. It is also essential to solving problems in coordinate geometry where understanding the spatial relationships is key.These equations are integral to various mathematical tasks, such as calculating areas, determining intersection points with other curves, or exploring tangents and normal lines relative to the circle.

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Most popular questions from this chapter

A nice curve $$x=3 \cos t+\cos 3 t, \quad y=3 \sin t-\sin 3 t ; \quad 0 \leq t \leq 2 \pi$$ What happens if you replace 3 with \(-3\) in the equations for \(x\) and \(y ?\) Graph the new equations and find out.

If you have a parametric equation grapher, graph the equations over the given intervals. Ellipse \(\quad x=4 \cos t, \quad y=2 \sin t, \quad\) over $$\begin{array}{l}{\text { a. } 0 \leq t \leq 2 \pi} \\ {\text { b. } 0 \leq t \leq \pi} \\ {\text { c. }-\pi / 2 \leq t \leq \pi / 2}\end{array}$$

The witch of Maria Agnesi The bell-shaped witch of Maria Agnesi can be constructed in the following way. Start with a circle of radius \(1,\) centered at the point \((0,1),\) as shown in the accompanying figure. Choose a point \(A\) on the line \(y=2\) and connect it to the origin with a line segment. Call the point where the segment crosses the circle \(B\) . Let \(P\) be the point where the vertical line through \(A\) crosses the horizontal line through \(B\) . The witch is the curve traced by \(P\) as \(A\) moves along the line \(y=2\) . Find parametric equations and a parameter interval for the witch by expressing the coordinates of \(P\) in terms of \(t\) the radian measure of the angle that segment \(O A\) makes with the positive \(x\) -axis. The following equalities (which you may assume) will help. $$\begin{array}{ll}{\text { a. } x=A Q} & {\text { b. } y=2-A B \sin t} \\\ {\text { c. } A B \cdot O A=(A Q)^{2}}\end{array}$$

Replace the Cartesian equations in Exercises \(53-66\) with equivalent polar equations. $$(x-3)^{2}+(y+1)^{2}=4$$

Hypocycloid When a circle rolls on the inside of a fixed circle, any point \(P\) on the circumference of the rolling circle describes a hypocycloid. Let the fixed circle be \(x^{2}+y^{2}=a^{2},\) let the radius of the rolling circle be \(b,\) and let the initial position of the tracing point \(P\) be \(A(a, 0) .\) Find parametric equations for the hypocycloid, using as the parameter the angle \(\theta\) from the positive \(x\) -axis to the line joining the circles' centers. In particular, if \(b=a / 4\) as in the accompanying figure, show that the hypocycloid is the astroid $$x=a \cos ^{3} \theta, \quad y=a \sin ^{3} \theta$$

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