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Exercises \(17-24\) give equations for ellipses. Put each equation in standard form. Then sketch the ellipse. Include the foci in your sketch. $$ 6 x^{2}+9 y^{2}=54 $$

Short Answer

Expert verified
Equation in standard form: \( \frac{x^2}{9} + \frac{y^2}{6} = 1 \) with foci at \((\pm \sqrt{3}, 0)\).

Step by step solution

01

Write the Equation

The given equation for the ellipse is \(6x^2 + 9y^2 = 54\).
02

Divide by the Constant

To start bringing the equation into standard form, divide every term by 54: \(\frac{6x^2}{54} + \frac{9y^2}{54} = 1\).
03

Simplify the Fractions

Simplifying the fractions in the equation, we get \(\frac{x^2}{9} + \frac{y^2}{6} = 1\).
04

Identify the Standard Form

The equation is now in the standard form of an ellipse: \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\) where \(a^2 = 9\) and \(b^2 = 6\). Thus, \(a = 3\) and \(b = \sqrt{6}\).
05

Determine the Orientation

Since \(a > b\), the ellipse is horizontal. The major axis is along the x-axis.
06

Calculate the Foci

For a horizontal ellipse, the formula for the c-value, which determines the location of the foci, is \(c^2 = a^2 - b^2\). Calculating, we get \(c^2 = 9 - 6 = 3\), so \(c = \sqrt{3}\).
07

Determine the Foci Locations

The foci are located at \((\pm c, 0) = (\pm \sqrt{3}, 0)\).
08

Sketch the Ellipse

The center of the ellipse is at \((0, 0)\). The vertices along the x-axis are at \((\pm 3, 0)\) and along the y-axis are at \((0, \pm \sqrt{6})\). Include foci at \((\pm \sqrt{3}, 0)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ellipses
An ellipse is a type of conic section that you can think of as a stretched-out circle. Unlike a circle, which has a single radius, an ellipse has two axes of symmetry: the major axis and the minor axis. The major axis is the longest diameter, and the minor axis is the shortest. Ellipses have a characteristic shape that's often seen in things like planetary orbits and lenses. The standard equation for an ellipse can look like this:\[ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \]Here, \(a\) and \(b\) are the lengths of the semi-major and semi-minor axes, respectively. The center of the ellipse is at the origin point (0,0) unless shifted otherwise. What's fascinating about ellipses is the concept of foci. These are two special points situated along the major axis. The total distance from any point on the ellipse to these two foci remains constant. It is this property that helps define the unique shape of an ellipse.
Conic Sections
Conic sections are curves that you obtain by slicing a cone with a plane. Depending on the angle and position of this cut, you can get different shapes: circles, ellipses, parabolas, and hyperbolas. Each type has unique properties that make them useful in mathematics and real-world applications. - **Circle**: A special case of an ellipse where the major and minor axes are equal. - **Ellipse**: Formed when the cutting plane is at an angle, but not steep enough to intersect both nappes of the cone. - **Parabola**: Created when the plane is parallel to the slope of the cone. - **Hyperbola**: Occurs when the plane cuts through both nappes of the cone. Ellipses are incredibly important and practical; they have applications in fields as varied as physics, engineering, and astronomy.
Algebraic Manipulation
Algebraic manipulation in equations involves reconfiguring or simplifying expressions using mathematical operations. In the context of converting an ellipse equation to its standard form, algebraic manipulations are key:
  • Division: Initially, you divide each term by the coefficient of the constant to simplify the equation to equal 1.
  • Simplification: Simplify the fractions in the equation to make it less complex and to reveal the essential form.
  • Identifying parameters: Recognize and assign values to \(a^2\) and \(b^2\), helping to determine the orientation and size of the ellipse.
Through these steps, you can systematically transform any ellipse equation from a general form into its standard form, making it simpler to analyze and graph on a coordinate plane. These skills are crucial for solving various mathematical problems that involve ellipses and other conic sections.

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Most popular questions from this chapter

If lines are drawn parallel to the coordinate axes through a point \(P\) on the parabola \(y^{2}=k x, k>0,\) the parabola partitions the rectangular region bounded by these lines and the coordinate axes into two smaller regions, \(A\) and \(B .\) $$ \begin{array}{l}{\text { a. If the two smaller regions are revolved about the } y \text { -axis, show }} \\ {\text { that they generate solids whose volumes have the ratio } 4 : 1 .} \\ {\text { b. What is the ratio of the volumes generated by revolving the }} \\ {\text { regions about the } x \text { -axis? }}\end{array} $$

Find the point on the parabola \(x=t, y=t^{2},-\infty< t <\infty\) closest to the point \((2,1 / 2) .\) (Hint: Minimize the square of the distance as a function of \(t\). )

Trochoids \(A\) wheel of radius \(a\) rolls along a horizontal straight line without slipping. Find parametric equations for the curve traced out by a point \(P\) on a spoke of the wheel \(b\) units from its center. As parameter, use the angle \(\theta\) through which the wheel turns. The curve is called a trochoid, which is a cycloid when \(b=a\) .

Exercises \(53-56\) give equations for hyperbolas and tell how many units up or down and to the right or left each hyperbola is to be shifted. Find an equation for the new hyperbola, and find the new center, foci, vertices, and asymptotes. $$ \frac{y^{2}}{3}-x^{2}=1, \quad \text { right } 1, \text { up } 3 $$

Exercises \(29-36\) give the eccentricities of conic sections with one focus at the origin along with the directrix corresponding to that focus. Find a polar equation for each conic section. $$e=1 / 3, \quad y=6$$

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