Chapter 10: Problem 78
Which of the sequences \(\left\\{a_{n}\right\\}\) in Exercises \(27-90\) converge, and which diverge? Find the limit of each convergent sequence. $$ a_{n}=n\left(1-\cos \frac{1}{n}\right) $$
Short Answer
Expert verified
The sequence converges to 0.
Step by step solution
01
Understand the Sequence
The sequence given is \( a_n = n \left( 1 - \cos \frac{1}{n} \right) \). We need to determine whether this sequence converges or diverges, and if it converges, find its limit.
02
Analyze the Inner Expression
The function \( \cos x \) can be expanded using the Taylor series around 0: \( \cos x \approx 1 - \frac{x^2}{2} + \frac{x^4}{24} - \cdots \). For small \( x \), we can approximate \( \cos \frac{1}{n} \approx 1 - \frac{1}{2n^2} \) because higher order terms are negligible as \( n \to \infty \).
03
Simplify the Expression
Now, substitute the approximation back into the sequence: \[ a_n = n \left( 1 - \left( 1 - \frac{1}{2n^2} \right) \right) = n \cdot \frac{1}{2n^2} = \frac{1}{2n} \].
04
Determine Convergence
The expression \( \frac{1}{2n} \) as \( n \to \infty \) obviously tends to \( 0 \). Therefore, the sequence \( a_n = \frac{1}{2n} \) converges to 0.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limits of Sequences
Sequences often play a vital role in mathematical analysis and calculus. A sequence can be understood as a list of numbers that follow a particular rule. Evaluating the limit of a sequence involves identifying the value that the sequence approaches as the number of terms increases indefinitely. In this exercise, our focus is on determining the behavior of the sequence \( a_n = n \left( 1 - \cos \frac{1}{n} \right) \). To explore whether a sequence converges, we must ascertain if its terms approach a fixed, finite number as \( n \to \infty \). If they do, the sequence is said to converge to that number, known as the limit. If not, it is divergent.
- A sequence \( \{a_n\} \) converges to a limit \( L \) if for every \( \epsilon > 0 \), there exists a natural number \( N \) such that for all \( n > N \), \( |a_n - L| < \epsilon \).
Taylor Series Expansion
The Taylor series is an essential concept for approximating functions that are too complex for straightforward calculation. It breaks a function into an infinite sum of polynomials, which makes complex functions easier to simplify and analyze. In the context of the sequence \( a_n = n \left( 1 - \cos \frac{1}{n} \right) \), the Taylor series allows us to approximate \( \cos \frac{1}{n} \) when \( n \) is large.The Taylor series expansion for the cosine function around 0 is given by:
- \( \cos x = 1 - \frac{x^2}{2} + \frac{x^4}{24} - \cdots \)
Trigonometric Sequences
Trigonometric sequences, like the one in our exercise, often involve sequences whose behavior is dictated by a trigonometric function such as sine, cosine, or tangent. They are quite common in both pure and applied mathematics, especially when dealing with oscillatory or wave-like phenomena.The sequence in question, \( a_n = n \left( 1 - \cos \frac{1}{n} \right) \), makes use of the cosine function, a fundamental trigonometric function. Analyzing such sequences often starts with transforming them using known mathematical tools, such as the Taylor series, to approximate or simplify.
- Trigonometric functions like cosines can be quite complex and their behavior at extremes can be counterintuitive without approximations.
- The cosine function, when expanded using Taylor series, simplifies the investigation of limits or convergence properties of related sequences.