Chapter 10: Problem 74
In Exercises \(73-78,\) find the values of \(x\) for which the given geometric series converges. Also, find the sum of the series (as a function of \(x )\) for those values of \(x .\) $$ \sum_{n=0}^{\infty}(-1)^{n} x^{-2 n} $$
Short Answer
Expert verified
The series converges for \(-1 < x < 1\) and the sum is \(S(x) = \frac{1}{1 + x^{-2}}\).
Step by step solution
01
Identify the Series Type
The series is geometric, given by \( \sum_{n=0}^{\infty} (-1)^n x^{-2n} \). In a geometric series \( \sum_{n=0}^{\infty} ar^n \), \( a \) is the first term and \( r \) is the common ratio.
02
Define the First Term and Common Ratio
In the given series, the first term \( a \) when \( n=0 \) is \( 1 \). The common ratio \( r \) is \( -x^{-2} \) as every consecutive term is multiplied by \( -x^{-2} \).
03
Apply Convergence Condition for Geometric Series
A geometric series converges if and only if the absolute value of the common ratio is less than 1: \( |r| < 1 \). For this series, that means \( |-x^{-2}| < 1 \) or \( |x^{-2}| < 1 \).
04
Solve the Inequality for \( x \)
From \( |x^{-2}| < 1 \), we deduce \( 0 < |x| < 1 \). Thus, \( x \) must be between \(-1\) and \(1\) exclusive to ensure convergence.
05
Find the Sum of the Series
When the series converges, the sum is given by \( S = \frac{a}{1 - r} \). Here, \( a = 1 \) and \( r = -x^{-2} \). Therefore, the sum \( S(x) = \frac{1}{1 - (-x^{-2})} = \frac{1}{1 + x^{-2}} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Convergence of Series
The convergence of a series is a central concept in mathematical analysis. A series converges when the sum of its infinite sequence of terms approaches a finite limit. In the context of geometric series, convergence occurs if the absolute value of the common ratio, denoted as \(|r|\), is less than 1.
This ensures that as more terms are added, they become progressively smaller, allowing the series sum to stabilize at a certain value.
For our specific problem, we evaluated the series \(\sum_{n=0}^{\infty} (-1)^n x^{-2n}\). Because it is a geometric series, we applied the convergence criteria \(|r| < 1\) to find where the series would sum to a finite value. This led us to the conclusion that \(0 < |x| < 1\) for the series to converge, meaning \(x\) must lie between \(-1\) and \(1\), exclusive.
This ensures that as more terms are added, they become progressively smaller, allowing the series sum to stabilize at a certain value.
For our specific problem, we evaluated the series \(\sum_{n=0}^{\infty} (-1)^n x^{-2n}\). Because it is a geometric series, we applied the convergence criteria \(|r| < 1\) to find where the series would sum to a finite value. This led us to the conclusion that \(0 < |x| < 1\) for the series to converge, meaning \(x\) must lie between \(-1\) and \(1\), exclusive.
Common Ratio
In a geometric series, the common ratio is the factor by which we multiply each term to get the next term. It is represented by \(r\) in the series \(\sum_{n=0}^{\infty} ar^n\).
The common ratio is crucial for determining whether the series converges and for finding the sum of the series.
In our exercise, by identifying the common ratio \(r\) as \(-x^{-2}\), we established the condition for convergence. Calculating the common ratio involved examining how each term in the sequence related to the previous one. For the series \(\sum_{n=0}^{\infty} (-1)^n x^{-2n}\), each successive term was found by multiplying the previous one by \(-x^{-2}\), giving us a straightforward path to solving the convergence condition \(|x^{-2}| < 1\).
The common ratio is crucial for determining whether the series converges and for finding the sum of the series.
In our exercise, by identifying the common ratio \(r\) as \(-x^{-2}\), we established the condition for convergence. Calculating the common ratio involved examining how each term in the sequence related to the previous one. For the series \(\sum_{n=0}^{\infty} (-1)^n x^{-2n}\), each successive term was found by multiplying the previous one by \(-x^{-2}\), giving us a straightforward path to solving the convergence condition \(|x^{-2}| < 1\).
Series Summation
The sum of a convergent geometric series can be easily calculated using the formula \(S = \frac{a}{1 - r}\), where \(a\) is the first term and \(r\) is the common ratio.
This formula only applies if the series converges, which as noted earlier, happens when \(|r| < 1\).
In the provided problem, with the first term \(a = 1\) and the common ratio \(r = -x^{-2}\), we substituted these values into the summation formula, yielding the result:
This formula only applies if the series converges, which as noted earlier, happens when \(|r| < 1\).
In the provided problem, with the first term \(a = 1\) and the common ratio \(r = -x^{-2}\), we substituted these values into the summation formula, yielding the result:
- For the series \(\sum_{n=0}^{\infty} (-1)^n x^{-2n}\), the sum is expressed as a function of \(x\):
- \(S(x) = \frac{1}{1 + x^{-2}}\)
Inequality Solving
Solving inequalities is a critical skill in many areas of mathematics. In this context, it helps us determine where a series will converge. Inequalities are special statements about the relative size or order of two values or expressions.
The original exercise required us to solve the inequality \(|x^{-2}| < 1\), which required unpacking a few steps.
Solving such inequalities helps specify the domain where series-related functions behave as expected, which is crucial when calculating series sums.
The original exercise required us to solve the inequality \(|x^{-2}| < 1\), which required unpacking a few steps.
- First, recognize \(|x^{-2}| < 1\) as implying \(0 < |x| < 1\).
- This suggests that the values of \(x\) must remain strictly between \(-1\) and \(1\) for convergence.
Solving such inequalities helps specify the domain where series-related functions behave as expected, which is crucial when calculating series sums.