Chapter 10: Problem 52
Estimate the magnitude of the error involved in using the sum of the first four terms to approximate the sum of the entire series. $$ \frac{1}{1+t}=\sum_{n=0}^{\infty}(-1)^{n} t^{n}, \quad 0 < t < 1 $$
Short Answer
Expert verified
The error magnitude is \( t^4 \).
Step by step solution
01
Identify the Series
The expression given is a geometric series: \( \sum_{n=0}^{\infty} (-1)^{n} t^{n} = \frac{1}{1+t} \). This type of series is characterized by a common ratio. The terms given are appropriate for small values of \( t \).
02
Compute the First Four Terms
Calculate the first four terms of the series: \(\begin{align*}&\text{First term (n=0): } (-1)^0 t^0 = 1 ewline&\text{Second term (n=1): } (-1)^1 t^1 = -t ewline&\text{Third term (n=2): } (-1)^2 t^2 = t^2 ewline&\text{Fourth term (n=3): } (-1)^3 t^3 = -t^3 ewline\end{align*}\)
03
Approximate Partial Sum
The sum of the first four terms is: \( 1 - t + t^2 - t^3 \). This is the approximation of the series using the first four terms alone.
04
Calculate the Error Term
In a geometric series, the error when truncating after the nth term is the magnitude of the next term. Here, the next term (n=4) is \((-1)^4 t^4\), or simply \(t^4\). Thus, the error is \(|t^4|\).
05
Express the Magnitude of the Error
The magnitude of the error is determined by the size of only the fifth term, which is \(t^4\). Hence, the magnitude of the error in using the first four terms to approximate the infinite series is \(t^4\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Series Approximation
In mathematics, approximating a series means estimating the sum of an infinite number of terms using only a finite number of those terms. This is particularly useful when we deal with geometric series, like the one in the given exercise: \[ \sum_{n=0}^{\infty} (-1)^{n} t^{n} = \frac{1}{1+t} \] This formula provides an exact representation for the infinite series, but in practical applications, it's often sufficient to use only the first few terms to get a very close approximation of the sum. In the exercise, the first four terms are used, specifically:
- 1 (for n=0)
- -t (for n=1)
- t^2 (for n=2)
- -t^3 (for n=3)
Error Estimation
Error estimation is the process of quantifying how accurate or close our approximation is to the actual infinite series. In geometric series, the error when using a finite number of terms is often expressed by the magnitude of the next unused term.In the exercise concerning the function \( \frac{1}{1+t} \), after computing the sum of the first four terms, the next term is \((-1)^4 t^4\), simplifying to \(t^4\). This term represents the error because it is the first term not included in our approximation. The formula looks like this:\[ \text{Error magnitude} = | t^4 | \]Taking the absolute value ensures that we only consider the size of the error, not its sign. In practical terms, if \( t \) is small, then \( t^4 \) will also be small, making our approximation highly accurate.
Partial Sum
A partial sum of an infinite series, like the geometric series we're dealing with, is when we add together only a certain number of initial terms. This gives us a simplified version of the full series which can be used to estimate the entire sum. For the series \( \sum_{n=0}^{\infty} (-1)^{n} t^{n} \), the partial sum using the first four terms is: \[ 1 - t + t^2 - t^3 \] This expression acts as an approximation to the infinite sum \( \frac{1}{1+t} \), offering a balance between computational simplicity and precision. It captures the essence of the series over the range of \( t \) values of interest, making complex calculations quicker and easier to manage. As a result, working with partial sums is a basic yet powerful technique in dealing with series in real-world applications.