Chapter 10: Problem 4
In Exercises \(1-36\) , (a) find the series' radius and interval of convergence. For what values of \(x\) does the series converge (b) absolutely, (c) conditionally? $$ \sum_{n=1}^{\infty} \frac{(3 x-2)^{n}}{n} $$
Short Answer
Expert verified
The radius is 1/3, absolutely convergent on \( (1/3, 1) \), conditionally at \( x = 1/3 \).
Step by step solution
01
Identify the Series
The given series is \( \sum_{n=1}^{\infty} \frac{(3x-2)^n}{n} \). This is a power series in terms of \((3x-2)\).
02
Use the Ratio Test
To find the radius of convergence, we use the Ratio Test. Calculate \[ \lim_{n \to \infty} \left| \frac{(3x-2)^{n+1}/(n+1)}{(3x-2)^n/n} \right| = \lim_{n \to \infty} \left| (3x-2) \right| \cdot \frac{n}{n+1} = |3x-2|.\] The series converges if \( |3x-2| < 1 \).
03
Find the Radius of Convergence
From the inequality \(|3x-2| < 1\), it follows that the radius of convergence is \(\frac{1}{3}\).
04
Determine the Interval of Convergence
Solve \( |3x-2| < 1 \) to find the interval. This gives \[-1 < 3x-2 < 1.\]Adding 2 to each part results in: \[1 < 3x < 3.\] Dividing by 3 gives: \[\frac{1}{3} < x < 1.\]
05
Check Convergence at Endpoints
Calculate the series at the endpoints \( x = \frac{1}{3} \) and \( x = 1 \):1. For \( x = \frac{1}{3} \), the series becomes \( \sum_{n=1}^{\infty} \frac{(-1)^n}{n} \), which is the alternating harmonic series and converges conditionally.2. For \( x = 1 \), the series becomes \( \sum_{n=1}^{\infty} \frac{1}{n} \), which diverges.
06
Determine Absolute and Conditional Convergence
For absolute convergence, the series needs to converge with all positive terms. The interval for absolute convergence here is \( \left( \frac{1}{3}, 1 \right) \). For conditional convergence, check at \( x = \frac{1}{3} \), since this is where the alternating harmonic series converges.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Series
A power series is a special kind of series in mathematics. It is of the form \( \sum_{n=0}^{\infty} c_n (x-a)^n \), where \( c_n \) are coefficients and \( a \) is the center of the series. In the given problem, the series is \( \sum_{n=1}^{\infty} \frac{(3x-2)^n}{n} \). Here, \( (3x-2) \) is like the \( (x-a) \) part of the general form of a power series.
Power series are incredibly useful because they allow complex functions to be expressed as a simple sum of terms. This can be very handy for calculations and for understanding the behavior of functions around a certain point.
Power series are incredibly useful because they allow complex functions to be expressed as a simple sum of terms. This can be very handy for calculations and for understanding the behavior of functions around a certain point.
- The radius of convergence is a crucial concept when dealing with power series, as it tells us how far from the center \( a \) we can go and still have the series converge.
- The interval of convergence extends this idea to include specific endpoint behavior.
Absolute Convergence
Absolute convergence is a helpful and strong condition in series analysis. A series \( \sum a_n \) is said to converge absolutely if the series \( \sum |a_n| \) converges. This means that even if all the terms were made positive, the series would still converge.
In the context of the problem, within the interval \( \left( \frac{1}{3}, 1 \right) \), the terms \( \frac{|(3x-2)^n|}{n} \) lead to a series that converges absolutely.
In the context of the problem, within the interval \( \left( \frac{1}{3}, 1 \right) \), the terms \( \frac{|(3x-2)^n|}{n} \) lead to a series that converges absolutely.
- This implies that if a series converges absolutely, it is stable under rearrangements of terms.
- Identifying absolute convergence allows us to apply various mathematical tools and theorems with confidence.
Conditional Convergence
Conditional convergence occurs when a series converges, but it does not converge absolutely. This means that the series \( \sum a_n \) converges while \( \sum |a_n| \) diverges. In the problem at hand, the series at the endpoint \( x = \frac{1}{3} \) becomes \( \sum_{n=1}^{\infty} \frac{(-1)^n}{n} \), known as the alternating harmonic series, which converges conditionally.
- Conditional convergence often arises in alternating series, such as the alternating harmonic series.
- It indicates a delicate balance between positive and negative terms that leads to convergence.
Ratio Test
The ratio test is a powerful tool for determining the convergence of series, particularly useful for power series like the one given in the problem. It involves examining the limit \( \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| \). If this limit is less than 1, the series converges absolutely.
For the series \( \sum_{n=1}^{\infty} \frac{(3x-2)^n}{n} \), applying the ratio test results in the inequality \(|3x-2| < 1\), which provides the radius of convergence.
For the series \( \sum_{n=1}^{\infty} \frac{(3x-2)^n}{n} \), applying the ratio test results in the inequality \(|3x-2| < 1\), which provides the radius of convergence.
- Advantages of the ratio test include simplicity and strong results for a wide class of series.
- Once you compute the limit, you can easily establish convergence, divergence, or draw no conclusive result.