/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 How close is the approximation \... [FREE SOLUTION] | 91Ó°ÊÓ

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How close is the approximation \(\sin x=x\) when \(|x|<10^{-3} ?\) For which of these values of \(x\) is \(x<\sin x ?\)

Short Answer

Expert verified
\(x < \sin x\) for \(x < 0\) within \(|x| < 10^{-3}\).

Step by step solution

01

Understand the problem

We need to analyze the approximation \(\sin x = x\) within the condition \(|x| < 10^{-3}\) and determine when \(x < \sin x\).
02

Analyze the Taylor series of sin x

Recall that the Taylor series expansion for \(\sin x\) around \(x=0\) is \(\sin x = x - \frac{x^3}{6} + \text{higher order terms}\). Since we're interested in small \(|x|\), the higher order terms are negligible.
03

Simplify the approximation

Within \(|x| < 10^{-3}\), we can approximate \(\sin x \approx x - \frac{x^3}{6}\). This allows us to compare \(x\) to \(\sin x\) without directly calculating the sine function.
04

Set the inequality x < sin x

We need to find when \(x < x - \frac{x^3}{6}\). Simplifying this, we find that \(0 < -\frac{x^3}{6}\), which implies that \(\frac{x^3}{6} < 0\).
05

Solve the inequality

The inequality \(\frac{x^3}{6} < 0\) holds when \(x^3 < 0\). Therefore, \(x < 0\) must hold for \(x < \sin x\).
06

Conclusion

Within the bounds \(|x| < 10^{-3}\), \(x < \sin x\) when \(x\) is negative.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sin x Approximation
The approximation of \( \sin x = x\) is a common method used in calculus to simplify problems involving small angles. This method is accurate when the value of \(x\) is close to zero, which is often referred to as the linear approximation.
By neglecting higher-order terms in the Taylor series, the approximation becomes much simpler and manageable, allowing us to solve problems more efficiently.
When you need to perform quick calculations or make estimates in real-world applications such as physics or engineering, this approximation is very helpful.
For very small angles - specifically when \(|x| < 10^{-3} \) \-the value of \(\sin x\) and \(x\) are nearly the same, which is why this approximation is so effective.
Small Angle Approximation
When examining very small values of \(x\), the small angle approximation becomes a powerful tool. Specifically, it allows us to assume \(\sin x \) behaves almost like \(x\), without having to calculate it explicitly. This comes from the Taylor series expansion of \(\sin x\) around zero: \(\sin x = x - \frac{x^3}{6} + \text{higher order terms}\).
  • The higher order terms diminish quickly as \(x\) becomes smaller, which means that \(x\) is typically a very close estimate of \(\sin x\) for small values.
  • This approximation is particularly advantageous when calculating things in physics and engineering, where computations need to be simplified as much as possible.

In many cases, the small angle approximation can significantly reduce the complexity of a problem without significantly compromising the accuracy of the result.
Inequality Analysis
In the exercise, we need to determine when \(x < \sin x\) given that \(\sin x \) is approximated as \(x - \frac{x^3}{6}\) and \(x\) is a small value (i.e., \(|x| < 10^{-3}\)). This involves examining the inequality \(x < x - \frac{x^3}{6}\).
Through simplifying, we find that \(0 < -\frac{x^3}{6}\), which boils down to solving \(\frac{x^3}{6} < 0\).
From this inequality, the consistent solution is \(x < 0\).
  • This implies that when \(x\) is negative and within our specified small range, \(x \)is less than \(\sin x\).
  • The analysis not only shows the conditions when \(x < \sin x\), but also illustrates how such analysis can reveal meaningful insights into the behavior of functions and their approximations.
Calculus Problem Solving
When solving calculus problems like those involving \(\sin x\), integrating approaches such as Taylor series, approximations, and inequalities is vital. The solution given for this problem methodically involves breaking down the specific conditions of the problem.
  • First, it identifies the scope of the approximation, understanding the \(|x| < 10^{-3}\) range.
  • Then, by using the Taylor series expansion, it identifies the necessary components to simplify the function and subsequently derive conclusions from it.
  • Finally, analyzing inequalities derived from these simplifications allows us to precisely determine when alternative approximations outperform or demonstrate more prominent characteristics than the original function.

The utility of calculus in solving these problems is in its systematic approach, which iteratively refines estimations and ensures all possible conditions have been adequately tested, providing both rigorous and intuitive insight into mathematical phenomena.

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Most popular questions from this chapter

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