/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 Which of the sequences \(\left\\... [FREE SOLUTION] | 91Ó°ÊÓ

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Which of the sequences \(\left\\{a_{n}\right\\}\) in Exercises \(27-90\) converge, and which diverge? Find the limit of each convergent sequence. $$ a_{n}=\frac{1-5 n^{4}}{n^{4}+8 n^{3}} $$

Short Answer

Expert verified
The sequence converges to -5.

Step by step solution

01

Recognize the Dominant Terms

In the expression \(a_n = \frac{1-5n^4}{n^4+8n^3}\), the highest power of \(n\) in both the numerator and the denominator is \(n^4\). Analyzing this will help us understand the behavior of the sequence as \(n\) approaches infinity.
02

Simplify the Fraction by Dominant Terms

Since \(n^4\) is the highest power, divide both the numerator and the denominator by \(n^4\) to simplify: \[a_n = \frac{\frac{1}{n^4} - 5}{1 + \frac{8}{n}}\].
03

Evaluate the Limits of Each Term

As \(n\) approaches infinity, \(\frac{1}{n^4} \rightarrow 0\) and \(\frac{8}{n} \rightarrow 0\). Substitute these limits into the simplified fraction: \[a_n = \frac{0 - 5}{1 + 0} = -5\].
04

Conclusion on Convergence and Limit

The sequence \(a_n = \frac{1-5n^4}{n^4+8n^3}\) converges to \(-5\) as \(n\) approaches infinity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limits
In the context of sequences, a limit refers to the value that a sequence approaches as the index becomes indefinitely large. Understanding limits is crucial for analyzing if sequences converge or diverge. For any sequence \(a_n\), you want to determine \(L\) such that, for every positive number \(\epsilon\), there exists a positive integer \(N\) where if \(n > N\), then \(|a_n - L| < \epsilon\). This formal definition shows how close the terms of the sequence get to \(L\) as \(n\) increases.

When handling limits in rational expressions like \(\frac{1-5n^4}{n^4+8n^3}\), scrutinize the behavior of each component as \(n\) approaches infinity. Often, simplification via dominant terms assists in recognizing the limit, making it simpler to see if a sequence converges. In our example, the limit \(-5\) is discerned by realizing that non-dominant parts become negligible.
Dominant Terms
Dominant terms in a sequence or expression are those which significantly affect the behavior, especially when variables are large. In the expression \(a_n = \frac{1 - 5n^4}{n^4 + 8n^3}\), the dominant term in the numerator is \(-5n^4\) and in the denominator is \(n^4\). These terms "dominate" because they will have the most considerable impact on the expression's value as n becomes very large.

To analyze such sequences, factor out the dominant terms. Here, you divide both the numerator and the denominator by \(n^4\), yielding \(a_n = \frac{\frac{1}{n^4} - 5}{1 + \frac{8}{n}}\). As \(n\) increases, terms like \(\frac{1}{n^4}\) and \(\frac{8}{n}\) tend to zero, highlighting the dominance of what remains. This process simplifies the evaluation of limits and clarifies the sequence's behavior without unnecessary complexity.
Infinity Behavior
Analyzing the infinity behavior of a sequence involves understanding how the terms behave as \(n\) becomes extremely large or tends toward infinity. Knowing this helps distinguish between convergent and divergent sequences. For the sequence \(a_n = \frac{1-5n^4}{n^4+8n^3}\), by observing infinity behavior, you simplify and conclude that most terms vanish against the dominant ones as \(n\) grows.

In the case of \(\frac{1-5n^4}{n^4+8n^3}\), the dominant terms are \(n^4\) for both the numerator and the denominator. As n approaches infinity:
  • \(\frac{1}{n^4}\) approaches 0
  • \(\frac{8}{n}\) approaches 0
This allows the sequence to be approximated as \(a_n = \frac{-5}{1} = -5\), meaning it converges to \(-5\). Understanding infinity behavior thus helps in determining the fate of sequences.

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Most popular questions from this chapter

Use series to estimate the integrals' values with an error of magnitude less than \(10^{-5}\) . (The answer section gives the integrals' values rounded to seven decimal places.) \begin{equation} \int_{0}^{0.4} \frac{e^{-x}-1}{x} d x \end{equation}

Show by example that \(\sum_{n=1}^{\infty} a_{n} b_{n}\) may diverge even if \(\sum_{n=1}^{\infty} a_{n}\) and \(\sum_{n=1}^{\infty} b_{n}\) both converge.

It is not yet known whether the series \begin{equation}\sum_{n=1}^{\infty} \frac{1}{n^{3} \sin ^{2} n}\end{equation} converges or diverges. Use a CAS to explore the behavior of the series by performing the following steps. \begin{equation} \begin{array}{l}{\text { a. Define the sequence of partial sums }}\end{array} \end{equation} \begin{equation} s_{k}=\sum_{n=1}^{k} \frac{1}{n^{3} \sin ^{2} n}. \end{equation} \begin{equation} \begin{array}{l}{\text { What happens when you try to find the limit of } s_{k} \text { as } k \rightarrow \infty ?} \\ {\text { Does your CAS find a closed form answer for this limit? }}\end{array} \end{equation} \begin{equation} \begin{array}{l}{\text { b. Plot the first } 100 \text { points }\left(k, s_{k}\right) \text { for the sequence of partial }} \\ \quad {\text { sums. Do they appear to converge? What would you estimate }} \\ \quad {\text { the limit to be? }} \\ {\text { c. Next plot the first } 200 \text { points }\left(k, s_{k}\right) . \text { Discuss the behavior in }} \\ \quad {\text { your own words. }} \\ {\text { d. Plot the first } 400 \text { points }\left(k, s_{k}\right) \text { . What happens when } k=355 \text { ? }} \\\ \quad {\text { Calculate the number } 355 / 113 . \text { Explain from you calculation }} \\ \quad {\text { what happened at } k=355 . \text { For what values of } k \text { would you }} \\ \quad {\text { guess this behavior might occur again? }} \end{array} \end{equation}

Which of the series converge, and which diverge? Use any method, and give reasons for your answers. \begin{equation}\sum_{n=1}^{\infty} \frac{\sqrt[n]{n}}{n^{2}}\end{equation}

In Exercises \(17-44\) , use any method to determine if the series converges or diverges. Give reasons for your answer. $$\sum_{n=1}^{\infty} \frac{n !}{10^{n}}$$

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