Chapter 10: Problem 27
Which of the series in Exercises \(11-40\) converge, and which diverge? Give reasons for your answers. (When you check an answer, remember that there may be more than one way to determine the series' convergence or divergence.) $$ \sum_{n=2}^{\infty} \frac{\sqrt{n}}{\ln n} $$
Short Answer
Expert verified
The series diverges by the Limit Comparison Test with \( \sum \frac{1}{n^{1/2}} \).
Step by step solution
01
Identify the Series
The given series is \( \sum_{n=2}^{\infty} \frac{\sqrt{n}}{\ln n} \). We need to determine whether this series converges or diverges.
02
Apply the Limit Comparison Test
To use the Limit Comparison Test, choose a comparison series that closely resembles the given series but has a known behavior. Compare \( \frac{\sqrt{n}}{\ln n} \) to \( \frac{1}{n^{1/2}} \), which is the harmonic series raised to the power 1/2 and is known to diverge.
03
Calculate the Limit for Comparison
Calculate \( \lim_{n \to \infty} \frac{\frac{\sqrt{n}}{\ln n}}{\frac{1}{n^{1/2}}} = \lim_{n \to \infty} \frac{n}{\ln n} \). As \( n \to \infty \), \( \frac{n}{\ln n} \to \infty \), implying that both series grow at the same rate.
04
Determine Convergence or Divergence
Since \( \lim_{n \to \infty} \frac{n}{\ln n} \to \infty \) and this ratio is positive, the given series \( \sum_{n=2}^{\infty} \frac{\sqrt{n}}{\ln n} \) has the same divergence behavior as the divergent series \( \sum_{n=2}^{\infty} \frac{1}{n^{1/2}} \). Thus, by the Limit Comparison Test, the original series diverges.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limit Comparison Test
The Limit Comparison Test is a powerful tool that helps us answer a crucial question: does a given series converge or diverge? It's especially handy when direct examination of a series doesn't make the convergence behavior obvious. The test works by comparing the series in question with another series, whose convergence properties are already known.
**How it works:**
By humanizing this process with a step-by-step approach, the Limit Comparison Test becomes an extremely practical method, especially for students working through challenging series on their own.
**How it works:**
- Select a comparison series. This series should be similar to the original series in terms of its general form but should have a known convergence or divergence status.
- Compute the limit as follows: For a given series \( \sum a_n \) and a comparison series \( \sum b_n \), calculate \( \lim_{n \to \infty} \frac{a_n}{b_n} \).
By humanizing this process with a step-by-step approach, the Limit Comparison Test becomes an extremely practical method, especially for students working through challenging series on their own.
Divergent Series
A series is considered divergent when the sequence of partial sums doesn't settle towards a fixed value. In other words, the sum grows indefinitely. Divergent series appear quite frequently in mathematical analysis, and recognizing them is vital for understanding the behavior of infinite sums.
**Key Characteristics of a Divergent Series:**
**Key Characteristics of a Divergent Series:**
- The partial sums do not approach a specific numerical limit.
- When tested, phenomena like the harmonic series show that their positive sequence terms continue to add increasingly without bound.
Convergence Tests
Convergence tests are methods used to determine whether a series converges or diverges. Different series require different tests, depending on their structure and form. These tests are indispensable tools in mathematical analysis and calculus.
**Popular Convergence Tests:**
**Popular Convergence Tests:**
- Ratio Test: useful for series whose terms involve factorials or power functions. It examines the limit of the ratio of successive terms.
- Root Test: similar to the Ratio Test but uses the \( n \)-th root of terms, often handy when terms involve exponents.
- Integral Test: applicable when terms are positive and decreasing, integrating terms as if they were part of a function.
- Limit Comparison Test: as described, this contrasts terms with a benchmark series.