/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 Find the Maclaurin series for th... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the Maclaurin series for the functions \(\frac{x^{2}}{x+1}\)

Short Answer

Expert verified
The Maclaurin series is \( \sum_{n=0}^{\infty} (-1)^n x^{n+2} = x^2 - x^3 + x^4 - x^5 + \ldots \).

Step by step solution

01

Understanding the Function

The function given is \( \frac{x^2}{x+1} \). Our task is to express this function as a Maclaurin series, which is essentially a Taylor series expansion of the function around \( x = 0 \).
02

Express Function for Series Expansion

To express the function as a series, we start by manipulating \( \frac{x^2}{x+1} \). Recognize that \( \frac{x^2}{x+1} = x^2 \cdot \frac{1}{x+1} \). We can express \( \frac{1}{x+1} \) as a geometric series since \( \frac{1}{x+1} = \frac{1}{1-(-x)} \).
03

Find the Geometric Series

The geometric series \( \frac{1}{1-(-x)} \) can be expanded as \( 1 + (-x) + (-x)^2 + (-x)^3 + \ldots = \sum_{n=0}^{\infty} (-1)^n x^n \).
04

Multiply the Series by \( x^2 \)

Substitute the series we found into \( x^2 \cdot \frac{1}{x+1} \):\( x^2 \cdot (1 - x + x^2 - x^3 + \ldots) = x^2 - x^3 + x^4 - x^5 + \ldots\)This means the series is: \( \sum_{n=0}^{\infty} (-1)^n x^{n+2} \).
05

Write the Final Series

Therefore, the Maclaurin series for \( \frac{x^2}{x+1} \) is\[ \sum_{n=0}^{\infty} (-1)^n x^{n+2} = x^2 - x^3 + x^4 - x^5 + \ldots\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Taylor Series
A Taylor series is a representation of a function as an infinite sum of terms calculated from the values of its derivatives at a single point. The series gives us a polynomial approximation of the function, which becomes exact as we include more terms. The general form of a Taylor series for a function \( f(x) \) about a point \( a \) is:
  • \( f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \ldots \)
  • Or in summation form: \( \sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!}(x-a)^n \)
For a Maclaurin series, which is a specific case of the Taylor series, the expansion is around \( x = 0 \). Thus, it becomes:
  • \( f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \ldots \)
  • Or \( \sum_{n=0}^{\infty} \frac{f^{(n)}(0)}{n!}x^n \)
Maclaurin series helps us approximate complex functions using simpler polynomial expressions, which are easier to compute and analyze.
Series Expansion
Series expansion is a method used to express functions as sums of terms of sequences. This is especially useful in approximating functions that might otherwise be complex to work with directly. The goal is to represent a function using an infinite series, which can often give powerful insights into the function's behavior and properties.The series expansion of a function allows us to approximate it by adding terms sequentially. As the number of terms increases, the approximation becomes more accurate. For example, the series expansion for the exponential function \( e^x \) is given by:
  • \( 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \ldots \)
  • This can also be written as \( \sum_{n=0}^{\infty} \frac{x^n}{n!} \)
Series expansions like Taylor, Maclaurin, and Fourier expansions are key tools in analysis and provide vital ways to express functions in a form that is often more manageable. They form the backbone of many numerical techniques and provide a fundamental approach in calculus to solve different problems.
Geometric Series
A geometric series is one of the simplest kinds of series in mathematics. It is a series with a constant ratio between successive terms. The general form of a geometric series is given by:
  • \( a + ar + ar^2 + ar^3 + \ldots \)
  • Where \( a \) is the first term and \( r \) is the common ratio.
A geometric series can be finite or infinite. The sum of a finite geometric series is:
  • \( S_n = a \frac{1-r^n}{1-r} \), where \( n \) is the number of terms
For infinite geometric series, the sum is calculated only when \(|r| < 1\):
  • \( S = \frac{a}{1-r} \)
In the context of calculus, geometric series are useful for series expansion, such as in the solution of the function \( \frac{x^2}{x+1} \), by expressing \( \frac{1}{x+1} \) as a geometric series. This approach simplifies expressing complex functions in terms of a series, making them easier to manipulate and compute.

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Most popular questions from this chapter

Logarithmic \(p\) -series a. Show that the improper integral $$\int_{2}^{\infty} \frac{d x}{x(\ln x)^{p}} \quad(p \text { a positive constant })$$ converges if and only if \(p>1\) b. What implications does the fact in part (a) have for the convergence of the series $$ \sum_{n=2}^{\infty} \frac{1}{n(\ln n)^{p}} ? $$ Give reasons for your answer.

How many terms of the convergent series \(\sum_{n=4}^{\infty}\left(1 / n(\ln n)^{3}\right)\) should be used to estimate its value with error at most 0.01\(?\)

Is it true that if \(\sum_{n=1}^{\infty} a_{n}\) is a divergent series of positive numbers, then there is also a divergent series \(\sum_{n=1}^{\infty} b_{n}\) of positive numbers with \(b_{n}<\) \(a_{n}\) for every \(n ?\) Is there a smallest divergent series of positive numbers? Give reasons for your answers.

Use series to evaluate the limits. \begin{equation} \lim _{y \rightarrow 0} \frac{\tan ^{-1} y-\sin y}{y^{3} \cos y} \end{equation}

Computer Explorations Taylor's formula with \(n=1\) and \(a=0\) gives the linearization of a function at \(x=0 .\) With \(n=2\) and \(n=3\) we obtain the standard quadratic and cubic approximations. In these exercises we explore the errors associated with these approximations. We seek answers to two questions: \begin{equation} \begin{array}{l}{\text { a. For what values of } x \text { can the function be replaced by each }} \\ {\text { approximation with an error less than } 10^{-2} \text { ? }} \\ {\text { b. What is the maximum error we could expect if we replace the }} \\ {\text { function by each approximation over the specified interval? }}\end{array} \end{equation} Using a CAS, perform the following steps to aid in answering questions (a) and (b) for the functions and intervals in Exercises \(53-58 .\) \begin{equation} \begin{array}{l}{\text { Step } 1 : \text { Plot the function over the specified interval. }} \\ {\text { Step } 2 : \text { Find the Taylor polynomials } P_{1}(x), P_{2}(x), \text { and } P_{3}(x) \text { at }} \\\ {x=0 .}\\\\{\text { Step } 3 : \text { Calculate the }(n+1) \text { st derivative } f^{(n+1)}(c) \text { associated }} \\ {\text { with the remainder term for each Taylor polynomial. }} \\ {\text { Plot the derivative as a function of } c \text { over the specified interval }} \\ {\text { and estimate its maximum absolute value, } M .}\\\\{\text { Step } 4 : \text { Calculate the remainder } R_{n}(x) \text { for each polynomial. }} \\ {\text { Using the estimate } M \text { from Step } 3 \text { in place of } f^{(n+1)}(c), \text { plot }} \\ {R_{n}(x) \text { over the specified interval. Then estimate the values of }} \\ {x \text { that answer question (a). }}\\\\{\text { Step } 5 : \text { Compare your estimated error with the actual error }} \\ {E_{n}(x)=\left|f(x)-P_{n}(x)\right| \text { by plotting } E_{n}(x) \text { over the specified }} \\ {\text { interval. This will help answer question (b). }} \\ {\text { Step } 6 : \text { Graph the function and its three Taylor approximations }} \\ {\text { together. Discuss the graphs in relation to the information }} \\ {\text { discovered in Steps } 4 \text { and } 5 .}\end{array} \end{equation} $$f(x)=e^{-x} \cos 2 x, \quad|x| \leq 1$$

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