Chapter 1: Problem 36
Graph the functions in Exercises \(35-54\) $$ y=\sqrt{9-x} $$
Short Answer
Expert verified
The graph is a downward slope from \((0, 3)\) to \((9, 0)\) confined to \(x \leq 9\).
Step by step solution
01
Understanding the function
The function given is \( y = \sqrt{9-x} \). This is a radical function, which takes a square root. The function is only defined for values of \( x \) where the expression under the square root is non-negative, i.e., \( 9-x \geq 0 \). This occurs when \( x \leq 9 \).
02
Determine the domain of the function
From \( 9-x \geq 0 \), it follows that \( x \leq 9 \). The domain of \( y = \sqrt{9-x} \) is all real numbers \( x \) such that \( x \leq 9 \). Thus, the domain is \([ -finity, 9 ]\).
03
Find the range of the function
Since \( y = \sqrt{9-x} \), the outputs are real and non-negative for any allowed value of \( x \). Therefore, the range is \([0, +finity)\).
04
Identify key points
Calculate a few key points to help graph the function:- At \( x = 0 \), \( y = \sqrt{9-0} = 3 \).- At \( x = 9 \), \( y = \sqrt{9-9} = 0 \).- Choose another point, such as \( x = 4.5 \): \( y = \sqrt{9-4.5} = \sqrt{4.5} \approx 2.12 \).
05
Sketch the graph
Plot the key points: \((0, 3)\), \((4.5, 2.12)\), and \((9, 0)\). The graph will start from the point \((9, 0)\) and increase as \( x \) decreases, approaching \((0, 3)\). The curve is a decreasing function that slopes downward to the right, confined to the first and second quadrants due to the domain restriction \( x \leq 9 \) and non-negative range.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Domain and Range
When analyzing radical functions like \( y = \sqrt{9-x} \), the domain is crucial as it tells us the set of allowable \( x \) values. For this function, the expression under the square root, \( 9-x \), must be non-negative because the square root of a negative number is not defined in the set of real numbers. This requirement gives us the inequality \( 9-x \geq 0 \), which simplifies to \( x \leq 9 \). Therefore, the domain of this function is all real numbers less than or equal to 9, or symbolically, \( (-\infty, 9] \).
The range of a radical function like this one is determined by the possible \( y \) values when \( x \) is in the domain. Since the square root function only produces non-negative outputs, the minimum value of \( y \) is 0. So, as \( x \) varies across the domain, \( y \) will also vary, producing values from 0 upward. Thus, the range of \( y = \sqrt{9-x} \) is \([0, +\infty)\). Understanding the domain and range helps us know where the graph starts, stops, and the possible values it can take.
The range of a radical function like this one is determined by the possible \( y \) values when \( x \) is in the domain. Since the square root function only produces non-negative outputs, the minimum value of \( y \) is 0. So, as \( x \) varies across the domain, \( y \) will also vary, producing values from 0 upward. Thus, the range of \( y = \sqrt{9-x} \) is \([0, +\infty)\). Understanding the domain and range helps us know where the graph starts, stops, and the possible values it can take.
Graphing Functions
Graphing the function \( y = \sqrt{9-x} \) helps visualize its behavior. Start by identifying key information about the function:
- The function is a square root function, typically starting higher on the axis and decreasing towards the right.
- The graph only exists for \( x \leq 9 \), as determined by the domain.
- Find where the function meets the axes. On the graph of \( y = \sqrt{9-x} \), the x-intercept is (9,0) since at \( x = 9 \), \( y \) becomes 0. Meanwhile, the graph meets the y-axis at \((0, 3)\).
Key Points in Graphing
Identifying key points is a smart first step in successfully graphing \( y = \sqrt{9-x} \). These points provide a backbone that guides the sketch of the curve. Let's consider why these are essential:
- Starting Point: The function starts at \( (9, 0) \). It's a critical point as it marks where the function's value begins, suggesting the graph's smallest x-value.
- Ending Point: At \((0, 3)\), the function peaks before turning downward. Knowing this helps determine the graph's general direction.
- Mid-Points: Evaluate the function at midpoints, such as \( x = 4.5 \), where the function yields approximately 2.12. These points "anchor" the graph between the start and endpoints, ensuring the precise curve shape.