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Evaluate each integral in Exercises \(1-36\) by using a substitution to reduce it to standard form. $$ \int_{0}^{1} \frac{16 x d x}{8 x^{2}+2} $$

Short Answer

Expert verified
The value of the integral is \( \ln 5 \).

Step by step solution

01

Identify the Substitution

To simplify the integral, look for a substitution that will make the expression inside the integral more manageable. Here, notice that the expression in the denominator is a function of \(x^2\). We can use the substitution: \( u = 8x^2 + 2 \). This choice is often done to simplify a quadratic expression.
02

Differentiate the Substitution

To use the substitution, differentiate \( u = 8x^2 + 2 \) with respect to \( x \):\[ \frac{du}{dx} = 16x \].Thus, \( du = 16x \, dx \). This matches exactly the numerator \( 16x \, dx \) in the integral.
03

Rewrite the Integral in Terms of \( u \)

Replace \( 16x \, dx \) with \( du \), and \( 8x^2 + 2 \) with \( u \):\[ \int_{x=0}^{x=1} \frac{16 x \, dx}{8 x^2+2} = \int_{u=8\cdot0^2+2}^{u=8\cdot1^2+2} \frac{du}{u} = \int_{2}^{10} \frac{du}{u} \].
04

Integrate the Function

Recognize that the integral \( \int \frac{du}{u} \) is a standard logarithmic form:\[ \int \frac{du}{u} = \ln |u| + C \].Since the limits of integration are present, calculate the definite integral.
05

Evaluate the Definite Integral

Substitute the limits of integration into the antiderivative:\[ \left[ \ln |u| \right]_{2}^{10} = \ln |10| - \ln |2| \].This simplifies to:\[ \ln \left( \frac{10}{2} \right) = \ln 5 \].
06

Confirm the Result

Check to make sure all steps are done correctly, and the change of variables aligns with the original integral's limits. The result of \( \ln 5 \) confirms that everything has been done correctly mathematically.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Substitution Method
The Substitution Method is a technique in Integral Calculus used to simplify an integral, making it easier to evaluate. It involves replacing a complex part of the integrand with a simpler variable, usually denoted as \( u \). This allows you to work with a simpler integral in terms of \( u \) instead of the original variable.

Steps to apply the substitution method:
  • Identify a portion of the integrand that can be substituted. Look for expressions that form the derivative of another part of the integrand.
  • Substitute the identified part with a new variable \( u \), and find the differential \( du \) in terms of the original variable.
  • Rewrite the entire integral in terms of \( u \). This often transforms the integral into a standard or known form.
  • Integrate with respect to \( u \), find the antiderivative, and substitute back to the original variable if necessary.
In the given exercise, by using \( u = 8x^2 + 2 \), we simplify the expression under the integration, transforming it into a recognizable logarithmic form.
Definite Integral
A Definite Integral calculates the accumulated area under a curve from one point to another. Unlike indefinite integrals, definite integrals provide a specific number as an answer because they include upper and lower limits of integration.

To evaluate a definite integral:
  • Find the antiderivative of the integrand function.
  • Apply the limits of integration by substituting them into the antiderivative.
  • Calculate the definite value by subtracting the value at the lower limit from the value at the upper limit.
The definite integral of the exercise takes the expression \( \int_{0}^{1} \ rac{16x \, dx}{8x^2+2} \) and calculates it between the limits \( x=0 \) and \( x=1 \). Converting it into a function of \( u \) allows the straightforward computation of the integral from \( u = 2 \) to \( u = 10 \).
Logarithmic Integration
Logarithmic Integration occurs when the antiderivative of an expression is a logarithm, usually in the form of \( \int \frac{1}{u} \, du = \ln |u| + C \). It is particularly useful when dealing with integrands that result in a natural logarithm once integrated.

The standard form of logarithmic integration:
  • Recognize the integrand as a derivative of a logarithmic function.
  • Find the antiderivative, which is the logarithm of the absolute value of \( u \), \( \ln |u| \).
  • If evaluating a definite integral, substitute the upper and lower limits into the antiderivative to find the result.
In the exercise, after substituting and simplifying, the integral \( \int \frac{du}{u} \) results in \( \ln |u| \). By plugging in the limits \( u=2 \) and \( u=10 \), the definite integral is solved as \( \ln 5 \).
Change of Variables
Change of Variables is a fundamental concept in integration, assisting in transforming complex integrals into simpler forms. It involves substituting a part of the integrand with a new variable to reduce complexity and find a more straightforward path to the solution.

With a successful change of variables:
  • One can often turn a complicated integration problem into a standard form that is easier to evaluate.
  • This technique is widely applicable in solving both definite and indefinite integrals.
  • Choosing the correct substitution is key, as it directly influences the simplicity of the transformed integral.
In our example, the change of variables from \( x \) to \( u = 8x^2 + 2 \) transformed a complex rational integrand into a simple logarithmic integral form, \( \int \frac{du}{u} \), which was then easy to integrate.

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