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Solve the initial value problems in Exercises \(41-44\) for \(x\) as a function of \(t .\) $$ (t+1) \frac{d x}{d t}=x^{2}+1 \quad(t>-1), \quad x(0)=\pi / 4 $$

Short Answer

Expert verified
The solution is \( x = \tan(\ln|t+1| + 0.665) \).

Step by step solution

01

Separate Variables

To solve the differential equation \((t+1) \frac{dx}{dt} = x^2 + 1\), first separate variables. Rewrite it as \( \frac{dx}{x^2 + 1} = \frac{dt}{t+1} \). This separates the variables \(x\) and \(t\) to different sides of the equation.
02

Integrate Both Sides

Integrate both sides to solve for \(x\) in terms of \(t\). Integrating the left side, \( \int \frac{dx}{x^2 + 1} = \tan^{-1}(x) + C_1 \). Integrating the right side, \( \int \frac{dt}{t+1} = \ln|t+1| + C_2 \). Combine constants: \( C = C_2 - C_1 \).
03

Set Up General Solution

Combine the integrations to set up the general solution: \( \tan^{-1}(x) = \ln|t+1| + C \). Isolate \(x\) by applying the tangent function: \( x = \tan(\ln|t+1| + C) \).
04

Apply Initial Condition

Apply the initial condition \(x(0) = \pi/4\) to find the constant \(C\). Substituting, \( \frac{\pi}{4} = \tan(\ln|0+1| + C) \). Since \(\ln(1) = 0\), we have \( \frac{\pi}{4} = \tan(C)\). Thus, \( C = \tan^{-1}(\frac{\pi}{4}) \).
05

Solve for the Constant

Evaluate \( C = \tan^{-1}(\frac{\pi}{4}) \). Recalling the angle whose tangent is \(\frac{\pi}{4}\), we approximate it numerically, as \(\tan^{-1}(\frac{\pi}{4}) \approx 0.665\).
06

Write the Particular Solution

Substitute the constant \(C\) back into the general solution: \( x = \tan(\ln|t+1| + 0.665) \). This is the particular solution for the initial value problem \((t+1) \frac{dx}{dt} = x^2 + 1\), with the initial condition \(x(0) = \frac{\pi}{4}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differential Equation
A differential equation is a mathematical equation that relates a function with its derivatives. In simple terms, it expresses how the rate of change of a quantity depends on other variables. These equations are fundamental in describing various physical systems and phenomena, such as growth models, motions, or decay processes.
For example, in our exercise, the differential equation is given by \[(t+1) \frac{dx}{dt} = x^2 + 1\] Here, the derivative \(\frac{dx}{dt}\) represents how the variable \(x\) changes with respect to \(t\).
The equation suggests that this rate of change is related to both the value of \(x\) itself and the function \(t + 1\). Differential equations can often be complex to solve, but understanding them is crucial for translating a wide range of real-world problems into solvable mathematical forms.
Separation of Variables
Separation of variables is a straightforward and effective method for solving some types of differential equations. The main idea is to rearrange the equation so that functions of each variable appear on opposite sides of the equation. This allows for easier integration.
In our example, the equation \[(t+1) \frac{dx}{dt} = x^2 + 1\] can be rearranged to separate \(x\) and \(t\) as follows:
  • \(\frac{dx}{x^2 + 1} = \frac{dt}{t+1}\)
This separation is the key to tackling the problem using integration. By isolating each variable, we can independently integrate both sides. This enables us to transform a challenging problem into more manageable pieces.
Integration
Integration is the mathematical process of finding the antiderivative of a function. It is the inverse operation of differentiation and is crucial in solving equations once variables are separated.
Once we've separated our equation, we integrate both sides:
  • Left side: \(\int \frac{dx}{x^2 + 1} = \tan^{-1}(x) + C_1\)
  • Right side: \(\int \frac{dt}{t+1} = \ln|t+1| + C_2\)

This step heavily relies on knowing standard integration formulas. The functions \(\tan^{-1}(x)\) and \(\ln|t+1|\) arise from specific integral results. The constants \(C_1\) and \(C_2\) are known as integration constants and are important for determining the particular solution to an initial value problem.

Initial Condition
The initial condition is an additional piece of information that specifies the value of the function at a certain point. This is crucial because differential equations typically have an infinite number of possible solutions. The initial condition helps us pinpoint a unique solution.
In our case, the initial condition is given as \(x(0) = \frac{\pi}{4}\). We incorporate this into our solution by substituting back after integrating:
  • \(\frac{\pi}{4} = \tan(\ln|0+1| + C)\)
  • Since \(\ln(1) = 0\), we simplify to find \(C = \tan^{-1}(\frac{\pi}{4})\)
The initial condition allows us to solve for the constant \(C\), thus refining the general solution into a specific one that precisely fits the problem's requirements. Through this step, the solution becomes applicable to real-world scenarios where specific starting values are known.

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Most popular questions from this chapter

Find the length of the curve \(y=x^{2}\) , \(0 \leq x \leq \sqrt{3} / 2\).

Use a CAS to perform the integrations. Evaluate the integrals a. \(\int x \ln x d x \) b. \(\int x^{2} \ln x d x\) c. \(\int x^{3} \ln x d x\) d. What pattern do you see? Predict the formula for \(\int x^{4} \ln x d x\) and then see if you are correct by evaluating it with a CAS. e. What is the formula for \(\int x^{n} \ln x d x, n \geq 1 ?\) Check your answer using a CAS.

Consider the integral \(\int_{-1}^{1} \sin \left(x^{2}\right) d x\) a. Find \(f^{(4)}\) for \(f(x)=\sin \left(x^{2}\right) .\) (You may want to check your work with a CAS if you have one available.) b. Graph \(y=f^{(4)}(x)\) in the viewing window \([-1,1]\) by \([-30,10] .\) c. Explain why the graph in part (b) suggests that \(\left|f^{(4)}(x)\right| \leq 30\) for \(-1 \leq x \leq 1\) d. Show that the error estimate for Simpson's Rule in this case becomes $$ \left|E_{S}\right| \leq \frac{(\Delta x)^{4}}{3} $$ e. Show that the Simpson's Rule error will be less than or equal to 0.01 in magnitude if \(\Delta x \leq 0.4 .\) f. How large must \(n\) be for \(\Delta x \leq 0.4 ?\)

Refer to formulas in the table of integrals at the back of the book. Derive Formula 46 by using a trigonometric substitution to evaluate $$\int \frac{d x}{x^{2} \sqrt{x^{2}-a^{2}}}$$

Use a CAS to perform the integrations. a. Use a CAS to evaluate $$\int_{0}^{\pi / 2} \frac{\sin ^{n} x}{\sin ^{n} x+\cos ^{n} x} d x$$ where \(n\) is an arbitrary positive integer. Does your CAS find the result? b. In succession, find the integral when \(n=1,2,3,5,7 .\) Comment on the complexity of the results. c. Now substitute \(x=(\pi / 2)-u\) and add the new and old integrals. What is the value of $$\int_{0}^{\pi / 2} \frac{\sin ^{n} x}{\sin ^{n} x+\cos ^{n} x} d x ?$$ This exercise illustrates how a little mathematical ingenuity solves a problem not immediately amenable to solution by a CAS.

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