/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 Use a substitution to change the... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use a substitution to change the integral into one you can find in the table. Then evaluate the integral. \(\int \frac{\sqrt{x}}{\sqrt{1-x}} d x\)

Short Answer

Expert verified
\( \arcsin(\sqrt{x}) - \sqrt{x(1-x)} + C \)

Step by step solution

01

Identify the Substitution

To simplify the integral \( \int \frac{\sqrt{x}}{\sqrt{1-x}} \, dx \), choose a substitution that will eliminate the square roots. A good choice here is \( x = \sin^2(u) \). This substitution will help manage the square roots using trigonometric identities.
02

Differentiate the Substitution

Using the substitution \( x = \sin^2(u) \), differentiate to find \( dx \):- \( x = \sin^2(u) \) implies \( dx = 2\sin(u)\cos(u) \, du \).- Also note that \( \sqrt{x} = \sin(u) \) and \( \sqrt{1-x} = \cos(u) \) since \( 1 - x = 1 - \sin^2(u) = \cos^2(u) \).
03

Substitute and Simplify the Integral

Express the integral in terms of \( u \):\[ \int \frac{\sqrt{x}}{\sqrt{1-x}} \, dx = \int \frac{\sin(u)}{\cos(u)} \cdot 2\sin(u)\cos(u) \, du \]Simplify the expression:\[ = 2 \int \sin^2(u) \, du \]
04

Use Trigonometric Identity

Replace \( \sin^2(u) \) using the trigonometric identity \( \sin^2(u) = \frac{1 - \cos(2u)}{2} \) to simplify the integral:\[ 2 \int \sin^2(u) \, du = 2 \int \frac{1 - \cos(2u)}{2} \, du = \int (1 - \cos(2u)) \, du \]
05

Integrate

Integrate the simplified expression:\[ \int (1 - \cos(2u)) \, du = \int 1 \, du - \int \cos(2u) \, du \]The integrals are:- \( \int 1 \, du = u \)- \( \int \cos(2u) \, du = \frac{1}{2} \sin(2u) \)So the integrated result is \( u - \frac{1}{2} \sin(2u) + C \), where \( C \) is the constant of integration.
06

Back-Substitute

Replace \( u \) back in terms of \( x \) using \( u = \arcsin(\sqrt{x}) \):- Note that \( \sin(2u) = 2\sin(u)\cos(u) = 2\sqrt{x}\sqrt{1-x} = 2\sqrt{x(1-x)} \).Thus, the solution in terms of \( x \) is:\[ \arcsin(\sqrt{x}) - \sqrt{x(1-x)} + C \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Substitution
Trigonometric substitution is a technique used in integral calculus to simplify integrals involving square roots. The idea is to use trigonometric identities to transform a complex expression into a simpler form. This technique is particularly useful for integrals involving expressions like \( \sqrt{a^2 - x^2} \), \( \sqrt{a^2 + x^2} \), or \( \sqrt{x^2 - a^2} \).

In the given problem, we face an integral with a square root that is not straightforward to integrate directly. By substituting \( x = \sin^2(u) \), the expression \( \sqrt{x} \) becomes \( \sin(u) \) and \( \sqrt{1-x} \) becomes \( \cos(u) \). This transforms the integral into a more manageable form.

The choice of substitution is driven by the identity \( \sin^2(u) + \cos^2(u) = 1 \), which helps to eliminate the square roots. This process reduces the complexity of the integral, paving the way for straightforward application of integration techniques.
Integration Techniques
Integration techniques play a crucial role in solving complex integrals by simplifying them into forms that can be easily integrated. One common technique is trigonometric substitution, as used in our example. By transforming the integral into another form, we often arrive at more standard integrals that are easier to manage.

Once the substitution \( x = \sin^2(u) \) was applied, our integral contained terms \( \sin(u) \) and \( \cos(u) \). We simplified the expression further by recognizing it as \( 2 \int \sin^2(u) \, du \). To integrate \( \sin^2(u) \), we used the identity \( \sin^2(u) = \frac{1 - \cos(2u)}{2} \).

This identity allows the integral to be expressed as \( \int (1 - \cos(2u)) \, du \), a form more amenable to straightforward integration. Using these techniques, we transformed a challenging integral into something approachable using basic antiderivatives.
Definite Integrals
While the current problem addresses an indefinite integral, it's useful to connect it to definite integrals to understand broader applications. Definite integrals evaluate the accumulation of quantities across specific intervals, giving a total value or net change.

For example, if our transformed integral was calculated within set limits or bounds, we would be computing a definite integral. The process involves substituting these bounds into the antiderivative and finding the difference between the upper and lower evaluation.

When dealing with trigonometric substitution in definite integrals, the substitution process changes the bounds of integration. After finding the antiderivative, return to the original variable by reversing the substitution, applying the new integral limits. This careful attention to the substitution and its limits ensures accuracy in finding the area or value needed from the definite integral.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use a CAS to perform the integrations. a. Use a CAS to evaluate $$\int_{0}^{\pi / 2} \frac{\sin ^{n} x}{\sin ^{n} x+\cos ^{n} x} d x$$ where \(n\) is an arbitrary positive integer. Does your CAS find the result? b. In succession, find the integral when \(n=1,2,3,5,7 .\) Comment on the complexity of the results. c. Now substitute \(x=(\pi / 2)-u\) and add the new and old integrals. What is the value of $$\int_{0}^{\pi / 2} \frac{\sin ^{n} x}{\sin ^{n} x+\cos ^{n} x} d x ?$$ This exercise illustrates how a little mathematical ingenuity solves a problem not immediately amenable to solution by a CAS.

The error function The error function, $$ \operatorname{erf}(x)=\frac{2}{\sqrt{\pi}} \int_{0}^{x} e^{-t^{2}} d t $$ important in probability and in the theories of heat flow and signal transmission, must be evaluated numerically because there is no elementary expression for the antiderivative of \(e^{-t^{2}} .\) a. Use Simpson's Rule with \(n=10\) to estimate erf \((1) .\) b. \(\ln [0,1]\) $$ \left|\frac{d^{4}}{d t^{4}}\left(e^{-t^{2}}\right)\right| \leq 12 $$ Give an upper bound for the magnitude of the error of the estimate in part (a).

Evaluate the integrals in Exercises \(1-28\). $$ \int \frac{5 d x}{\sqrt{25 x^{2}-9}}, \quad x>\frac{3}{5} $$

Find the area of the region in the first quadrant that is enclosed by the coordinate axes and the curve \(y=\sqrt{9-x^{2} / 3}\).

Usable values of the sine-integral function The sine-integral function, $$ \operatorname{Si}(x)=\int_{0}^{x} \frac{\sin t}{t} d t $$ is one of the many functions in engineering whose formulas cannot be simplified. There is no elementary formula for the antiderivative of \((\sin 1) / t\) . The values of \(\mathrm{Si}(x),\) however, are readily estimated by numerical integration. Although the notation does not show it explicitly, the function being integrated is $$ f(t)=\left\\{\begin{array}{cl}{\frac{\sin t}{t},} & {t \neq 0} \\ {1,} & {t=0}\end{array}\right. $$ the continuous extension of \((\sin t) / t\) to the interval \([0, x] .\) The function has derivatives of all orders at every point of its domain. Its graph is smooth, and you can expect good results from Simpson's Rule. a. Use the fact that \(\left|f^{(4)}\right| \leq 1\) on \([0, \pi / 2]\) to give an upper bound for the error that will occur if $$ \operatorname{Si}\left(\frac{\pi}{2}\right)=\int_{0}^{\pi / 2} \frac{\sin t}{t} d t $$ is estimated by Simpson's Rule with \(n=4\) . b. Estimate \(\operatorname{Si}(\pi / 2)\) by Simpson's Rule with \(n=4\) c. Express the error bound you found in part (a) as a percentage of the value you found in part (b).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.