/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 82 Could \(\log _{a} b\) possibly e... [FREE SOLUTION] | 91Ó°ÊÓ

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Could \(\log _{a} b\) possibly equal 1\(/ \log _{b} a ?\) Give reasons for your answer.

Short Answer

Expert verified
Yes, because \( \log_a b \) is the reciprocal of \( \log_b a \).

Step by step solution

01

Define the Problem

We want to determine if \( \log_a b = \frac{1}{\log_b a} \). This requires us to understand the properties of logarithms and how they interact.
02

Apply the Reciprocal Identity of Logarithms

We know that the change of base formula for logarithms states: \( \log_b a = \frac{1}{\log_a b} \). This suggests a reciprocal relationship.
03

Analyze the Identity

From Step 2, we see that \( \log_a b \) is indeed the reciprocal of \( \log_b a \). Therefore, \( \log_a b = \frac{1}{\log_b a} \) holds true.
04

Conclude the Reasoning

Based on the property of logarithms that \( \log_a b \cdot \log_b a = 1 \), we reaffirm that the original equation \( \log_a b = \frac{1}{\log_b a} \) is true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Change of Base Formula
The change of base formula is an extremely useful tool when working with logarithms. It allows you to convert a logarithm of any base into an expression with a different base, typically a base that is easier to work with, such as base 10 or base e. This is particularly helpful in calculations since most calculators can only compute logarithms in base 10 (common log) or base e (natural log).
The formula is given by:
  • \( \log_b a = \frac{\log_c a}{\log_c b} \)
What this tells us is that the logarithm of 'a' with base 'b' can be transformed into the quotient of logarithms in a new base 'c'.
With the change of base formula, we can explore logarithmic relationships from another perspective, such as what happens when bases are inverted.
This leads to our next topic, the reciprocal identity of logarithms.
Reciprocal Identity of Logarithms
The reciprocal identity of logarithms provides insight into a fascinating property: two logarithms can be reciprocal to each other if their bases swap places.
According to this identity:
  • \( \log_b a = \frac{1}{\log_a b} \)
This equation highlights that the logarithm of 'a' with base 'b' is the reciprocal of the logarithm of 'b' with base 'a'.
Essentially, if you know one of these logarithms, you can easily find the other by simply taking the reciprocal.
This relationship is crucial because it always holds true for positive numbers where neither 'a' nor 'b' equals 1, providing a symmetrical and balanced understanding of logarithmic behavior. Understanding this identity makes manipulation of logarithms far easier, especially in problems that require you to swap or convert bases.
Logarithmic Properties
Logarithmic properties are rules that make calculations involving logarithms more manageable by providing a structured toolkit. These properties help in solving equations, simplifying expressions, and understanding deeper mathematical relationships.
Here are some foundational logarithmic properties:
  • Product Property: \( \log_b (mn) = \log_b m + \log_b n \)
  • Quotient Property: \( \log_b \left( \frac{m}{n} \right) = \log_b m - \log_b n \)
  • Power Property: \( \log_b (m^n) = n \cdot \log_b m \)
These properties allow you to break down complex logarithmic expressions into simpler parts.
They maintain consistency across calculations, ensuring results are reliable and predictable.
In the context of the given exercise, the property \( \log_a b \cdot \log_b a = 1 \) plays a pivotal role, as it lays the groundwork for the reciprocal identity.
By understanding these logarithmic properties, you gain more than just the ability to solve problems; you gain insight into how numbers interrelate in logarithmic form.

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