Chapter 7: Problem 53
Evaluate the integrals. \(\int_{0}^{\pi / 2} 7^{\cos t} \sin t d t\)
Short Answer
Expert verified
The integral evaluates to \( \frac{6}{\ln 7} \).
Step by step solution
01
Recognizing the Integral Form
The given integral is \( \int_{0}^{\pi / 2} 7^{\cos t} \sin t \, dt \). This type of integral often suggests a substitution might simplify the problem.
02
Choosing a Substitution
Let's use the substitution \( u = \cos t \). Thus, the derivative \( du = -\sin t \, dt \), or \( \sin t \, dt = -du \). This substitution changes the bounds as well: when \( t = 0, u = 1 \) and when \( t = \pi/2, u = 0 \).
03
Substituting and Changing the Limits
Substitute \( u = \cos t \) into the integral to get \( \int_{1}^{0} 7^u (-du) \). The negative sign can be used to swap the limits giving \( \int_{0}^{1} 7^u \, du \).
04
Integrating the New Expression
The integral \( \int 7^u \, du \) is equal to \( \frac{7^u}{\ln 7} + C \). So, \( \int_{0}^{1} 7^u \, du = \left[ \frac{7^u}{\ln 7} \right]_{0}^{1} \).
05
Evaluating the Definite Integral
Compute \( \left[ \frac{7^u}{\ln 7} \right]_{0}^{1} = \frac{7^1}{\ln 7} - \frac{7^0}{\ln 7} = \frac{7}{\ln 7} - \frac{1}{\ln 7} = \frac{7 - 1}{\ln 7} = \frac{6}{\ln 7} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Definite Integrals
Definite integrals are used in calculus to calculate the accumulated value of a function over a given interval. This involves computing the area under the curve of the function between two specific points on the x-axis. For the integral \( \int_{a}^{b} f(x) \, dx \), \( a \) and \( b \) are the limits of integration, indicating the start and end points of the interval respectively.
Instead of producing another function as the result, like indefinite integrals do, definite integrals provide a single numerical value. This makes them very useful for solving problems in physics and engineering where measurements over a specific distance or period are needed.
Definite integrals are evaluated using the Fundamental Theorem of Calculus which states:
Instead of producing another function as the result, like indefinite integrals do, definite integrals provide a single numerical value. This makes them very useful for solving problems in physics and engineering where measurements over a specific distance or period are needed.
Definite integrals are evaluated using the Fundamental Theorem of Calculus which states:
- If \( F(x) \) is an antiderivative of \( f(x) \), then
- \( \int_{a}^{b} f(x) \, dx = F(b) - F(a) \).
Substitution Method
The substitution method is a popular technique used in calculus to simplify complex integrals. This technique often comes into play when an integral contains composite functions, or when a direct algebraic integration seems difficult. The method involves substituting a part of the integral with a new variable, which facilitates easier integration.
The process typically involves:
The process typically involves:
- Identifying a substitution \( u = g(x) \) which simplifies the integral.
- Finding the differential \( du = g'(x) \, dx \), helping to express \( dx \) in terms of \( du \).
- Changing the limits of integration as per the new variable \( u \).
- Evaluating the simpler integral in terms of \( u \).
Integration Techniques
There are various integration techniques in calculus, each suited for different types of integrals. Two of these were crucial in solving the given exercise: the substitution method and properties of exponential functions in integration.
Each technique aims to simplify integration by either breaking it down into simpler parts or transforming it into a form that's more straightforward to integrate:
Each technique aims to simplify integration by either breaking it down into simpler parts or transforming it into a form that's more straightforward to integrate:
- Substitution: Makes a difficult integral easier by changing variables.
- Exponential Integration: Involves integrations of functions like \( a^x \) where the integral is given by \( \frac{a^x}{\ln a} + C \) for an indefinite integral.