Chapter 7: Problem 30
Find the derivative of \(y\) with respect to the given independent variable. \(y=\log _{5} \sqrt{\left(\frac{7 x}{3 x+2}\right)^{\ln 5}}\)
Short Answer
Expert verified
The derivative is \( \frac{1}{2x(3x+2)} \).
Step by step solution
01
Simplify the Expression
Rewrite the given function in a simpler form. We have:\[ y = \log_5 \left( \sqrt{\left( \frac{7x}{3x+2} \right)^{\ln 5}} \right) \]First, express the square root as an exponent:\[ y = \log_5 \left( \left( \frac{7x}{3x+2} \right)^{(\ln 5)/2} \right) \]Use the property of logarithms that states \( \log_b(a^c) = c \cdot \log_b(a) \):\[ y = \frac{\ln 5}{2} \cdot \log_5 \left( \frac{7x}{3x+2} \right) \]
02
Change Logarithm Base
Use the change of base formula to convert the base of the logarithm to natural logarithms as it simplifies differentiation:\[ \log_5 \left( \frac{7x}{3x+2} \right) = \frac{\ln\left( \frac{7x}{3x+2} \right)}{\ln 5} \]Substitute back into the expression for \(y\):\[ y = \frac{\ln 5}{2} \cdot \frac{\ln\left( \frac{7x}{3x+2} \right)}{\ln 5} \]This simplifies to:\[ y = \frac{1}{2} \ln\left( \frac{7x}{3x+2} \right) \]
03
Differentiate Simplified Expression
Differentiate \( y = \frac{1}{2} \ln\left( \frac{7x}{3x+2} \right) \) with respect to \( x \). Use the chain rule and the derivative of \( \ln(u) \) which is \( \frac{1}{u} \frac{du}{dx} \):Let \( u = \frac{7x}{3x+2} \).Then, \( \frac{du}{dx} = \frac{(3x+2) \cdot 7 - 7x \cdot 3}{(3x+2)^2} = \frac{21x + 14 - 21x}{(3x+2)^2} = \frac{14}{(3x+2)^2} \).The derivative of \( y \) is:\[ \frac{dy}{dx} = \frac{1}{2} \cdot \frac{1}{u} \cdot \frac{du}{dx} = \frac{1}{2} \cdot \frac{1}{\frac{7x}{3x+2}} \cdot \frac{14}{(3x+2)^2} \]Simplifies to:\[ \frac{dy}{dx} = \frac{7(3x+2)}{2(7x)(3x+2)^2} = \frac{7}{2(7x)(3x+2)} = \frac{1}{2x(3x+2)} \]
04
Final Expression
So, the derivative \( \frac{dy}{dx} \) is:\[ \frac{dy}{dx} = \frac{1}{2x(3x+2)} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Logarithm
Logarithms are an essential mathematical concept, especially when dealing with exponential functions. A logarithm essentially asks the question: "What power must this base be raised to, to obtain a certain number?" This is expressed in the form:
The logarithmic property used to simplify the expression is \( \log_b(a^c) = c \cdot \log_b(a) \). This allows expressing complex exponents or powers in a simpler, linear form. Another property that helps in converting bases is the change of base formula, which will be discussed in detail in another section.
- For example, if we say \( \log_b(a) = c \), it means that \( b^c = a \).
The logarithmic property used to simplify the expression is \( \log_b(a^c) = c \cdot \log_b(a) \). This allows expressing complex exponents or powers in a simpler, linear form. Another property that helps in converting bases is the change of base formula, which will be discussed in detail in another section.
Chain Rule
The chain rule is a fundamental tool for differentiating composite functions. When a function is composed of multiple functions nested together, the chain rule helps to break them apart for differentiation.
To find \( \frac{du}{dx} \), the chain rule requires finding derivatives of these internal components. Consequently, the straightforward derivative of the natural logarithm \( \ln(u) \), which is \( \frac{1}{u} \cdot \frac{du}{dx} \), is applied. This breaks the derivation into manageable pieces, efficiently moving through complex logarithmic and algebraic transformations.
- The standard expression of the chain rule is: \( \frac{d}{dx} [f(g(x))] = f'(g(x)) \cdot g'(x) \).
To find \( \frac{du}{dx} \), the chain rule requires finding derivatives of these internal components. Consequently, the straightforward derivative of the natural logarithm \( \ln(u) \), which is \( \frac{1}{u} \cdot \frac{du}{dx} \), is applied. This breaks the derivation into manageable pieces, efficiently moving through complex logarithmic and algebraic transformations.
Change of Base Formula
The change of base formula is a significant mathematical utility for working with logarithms. It allows us to express a logarithm in one base in terms of another base, typically using base 10 or base \( e \). This is particularly useful in calculus, where differentiating logarithms in the natural base \( e \) simplifies the process.
The conversion helps streamline the differentiation process: the base conversion reduces the expression to involve \( \ln \) operations, which standardizes the derivatives involved, thus transforming the function into a simpler form that is less cumbersome to handle analytically.
- The formula is expressed as \( \log_b(a) = \frac{\ln(a)}{\ln(b)} \) when converting to natural logs.
The conversion helps streamline the differentiation process: the base conversion reduces the expression to involve \( \ln \) operations, which standardizes the derivatives involved, thus transforming the function into a simpler form that is less cumbersome to handle analytically.