Chapter 7: Problem 16
Find the derivative of \(y\) with respect to the given independent variable. \(y=t^{1-e}\)
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Chapter 7: Problem 16
Find the derivative of \(y\) with respect to the given independent variable. \(y=t^{1-e}\)
These are the key concepts you need to understand to accurately answer the question.
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Evaluate the integrals in Exercises \(67-74\) in terms of a. inverse hyperbolic functions. b. natural logarithms. $$ \int_{1}^{2} \frac{d x}{x \sqrt{4+x^{2}}} $$
Find the limits in Exercises \(113-116\) $$ \lim _{x \rightarrow 0} \frac{2 \tan ^{-1} 3 x^{2}}{7 x^{2}} $$
Find the limits in Exercises \(113-116\) $$ \lim _{x \rightarrow 0} \frac{\sin ^{-1} 5 x}{x} $$
When hyperbolic function keys are not available on a calculator, it is still possible to evaluate the inverse hyperbolic functions by expressing them as logarithms, as shown here. $$ \begin{array}{rlrl}{\sinh ^{-1} x} & {=\ln \left(x+\sqrt{x^{2}+1}\right),} & {-\infty < x < \infty} \\ {\cosh ^{-1} x} & {=\ln \left(x+\sqrt{x^{2}+1}\right),} & {x \geq 1} \\ {\tanh ^{-1} x} & {=\frac{1}{2} \ln \frac{1+x}{1-x},} & {|x| < 1} \\ {\operatorname{sech}^{-1} x} & {=\ln \left(\frac{1+\sqrt{1-x^{2}}}{x}\right),} & {0 < x \leq 1} \\\ {\operatorname{csch}^{-1} x} & {=\ln \left(\frac{1}{x}+\frac{\sqrt{1+x^{2}}}{|x|}\right),} & {x \neq 0} \\\ {\operatorname{coth}^{-1} x} & {=\frac{1}{2} \ln \frac{x+1}{x-1},} & {|x| > 1}\end{array} $$ Use the formulas given above to express the numbers in Exercises \(61-66\) in terms of natural logarithms. $$ \operatorname{sech}^{-1}(3 / 5) $$
Verify the integration formulas in Exercises \(37-40\). $$ \int \tanh ^{-1} x d x=x \tanh ^{-1} x+\frac{1}{2} \ln \left(1-x^{2}\right)+C $$
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