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Write the sums in Exercises \(1-6\) without sigma notation. Then evaluate them. $$ \sum_{k=1}^{4}(-1)^{k} \cos k \pi $$

Short Answer

Expert verified
The sum evaluates to 4.

Step by step solution

01

Expand the Sigma Notation

Firstly, let's expand the sigma notation \( \sum_{k=1}^{4} (-1)^k \cos(k \pi) \). This means we have to evaluate the expression \((-1)^k \cos(k \pi)\) for values of \(k\) starting from 1 to 4. The expanded form will be:\[ (-1)^1 \cos(1 \pi) + (-1)^2 \cos(2 \pi) + (-1)^3 \cos(3 \pi) + (-1)^4 \cos(4 \pi) \]
02

Calculate Each Term

Now, compute the value of each term in the expanded sum:- For \(k=1\): \((-1)^1 \cos(1 \pi) = -1 \times (-1) = 1\)- For \(k=2\): \((-1)^2 \cos(2 \pi) = 1 \times 1 = 1\)- For \(k=3\): \((-1)^3 \cos(3 \pi) = -1 \times (-1) = 1\)- For \(k=4\): \((-1)^4 \cos(4 \pi) = 1 \times 1 = 1\)
03

Sum the Terms

Add up the calculated values:\[1 + 1 + 1 + 1 = 4\]
04

Final Evaluation

The sum of the series \( \sum_{k=1}^{4} (-1)^k \cos(k \pi) \) evaluates to \(4\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mathematical Series
Mathematical series are essentially a sequence of numbers added together, represented in compact form using sigma notation. This notation uses the Greek letter sigma (\( \Sigma \)) to indicate summation and tells us to add up expressions over specified ranges. In our example, the series \( \sum_{k=1}^{4} (-1)^k \cos(k \pi) \) is expressed in sigma notation, meaning that we must evaluate expressions for each integer from 1 to 4. This highlights a key benefit of sigma notation: it provides a powerful way to represent long sums within a compact and easy-to-read expression. Sigma notation is particularly useful when dealing with series in calculus and other higher-level mathematics.
  • It reduces redundancy, making complex calculations more manageable.
  • You can quickly see which terms need calculation.
  • It is essential for both arithmetic and geometric series.
Trigonometric Functions
Trigonometric functions play a crucial role in mathematical analyses, especially in series that involve periodic components such as sine or cosine. In the given series, we deal with the cosine function, \( \cos(k \pi) \). It’s essential to remember that trigonometric functions like cosine relate angles to side ratios in right-angled triangles. However, in advanced mathematics, they are also viewed through their periodic properties. The expression \( \cos(k \pi) \) signifies the values of cosine at certain integer multiples of \( \pi \), producing either +1 or -1.
These specific values come in handy, as they make calculation simpler by flipping the sign depending on whether the integer \( k \) is odd or even.
  • If \( k \) is odd, \( \cos(k \pi) = -1 \).
  • If \( k \) is even, \( \cos(k \pi) = 1 \).
This understanding helps simplify the process of calculating the sum in our series.
Expansion of Series
The expansion of series involves breaking down a sigma notation into its individual components, allowing for straightforward evaluation. This crucial step reveals each part of the sum, so you can calculate them one by one. Let’s look at the series we expanded in the exercise: \(-1^1 \cos(1 \pi) + (-1)^2 \cos(2 \pi) + (-1)^3 \cos(3 \pi) + (-1)^4 \cos(4 \pi)\), which simplifies into separate components ready for evaluation. Each term consists of a pattern of alternating coefficients and trigonometric values, combining rules of arithmetic progression with trigonometric identities.
  • Calculate each term independently using alternating sign rules and cosine values.
  • Recognize that this approach is systematic and reduces error risk.
The expansion allows us to verify each step clearly, ensuring the final sum is correct. By simplifying each step, this process prepares us for working with more complex series in advanced mathematics.

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Most popular questions from this chapter

a. Show that if \(f\) is odd on \([-a, a],\) then $$\int_{-a}^{a} f(x) d x=0$$ b. Test the result in part (a) with \(f(x)=\sin x\) and \(a=\pi / 2\) .

If you do not know what substitution to make, try reducing the integral step by step, using a trial substitution to simplify the integral a bit and then another to simplify it some more. You will see what we mean if you try the sequences of substitutions in Exercises 49 and 50 . $$ \begin{array}{l}{\int \sqrt{1+\sin ^{2}(x-1)} \sin (x-1) \cos (x-1) d x} \\\ {\text { a. } u=x-1, \text { followed by } v=\sin u, \text { then by } w=1+v^{2}} \\ {\text { b. } u=\sin (x-1), \text { followed by } v=1+u^{2}} \\\ {\text { c. } u=1+\sin ^{2}(x-1)}\end{array} $$

In Exercises \(75-78,\) let \(F(x)=\int_{a}^{u(x)} f(t) d t\) for the specified \(a, u,\) and \(f\) . Use a CAS to perform the following steps and answer the questions posed. a. Find the domain of \(F\) b. Calculate \(F^{\prime}(x)\) and determine its zeros. For what points in its domain is \(F\) increasing? decreasing? c. Calculate \(F^{\prime \prime}(x)\) and determine its zero. Identify the local extrema and the points of inflection of \(F\) . d. Using the information from parts (a)-(c), draw a rough hand-sketch of \(y=F(x)\) over its domain. Then graph \(F(x)\) on your CAS to support your sketch. $$ a=0, \quad u(x)=x^{2}, \quad f(x)=\sqrt{1-x^{2}} $$

Use the Substitution Formula in Theorem 6 to evaluate the integrals in Exercises \(1-24 .\) $$ \int_{0}^{1}\left(4 y-y^{2}+4 y^{3}+1\right)^{-2 / 3}\left(12 y^{2}-2 y+4\right) d y $$

In Exercises \(91-94\) , you will find the area between curves in the plane when you cannot find their points of intersection using simple algebra. Use a CAS to perform the following steps: a. Plot the curves together to see what they look like and how many points of intersection they have. b. Use the numerical equation solver in your CAS to find all the points of intersection. c. Integrate \(|f(x)-g(x)|\) over consecutive pairs of intersection values. d. Sum together the integrals found in part (c). $$ f(x)=\frac{x^{4}}{2}-3 x^{3}+10, \quad g(x)=8-12 x $$

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