/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 Evaluate the integrals in Exerci... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the integrals in Exercises \(13-48\) . $$ \int \frac{\sec z \tan z}{\sqrt{\sec z}} d z $$

Short Answer

Expert verified
The integral evaluates to \( \frac{2}{3} (\sec z)^{3/2} + C \).

Step by step solution

01

Simplify the Expression

Start by simplifying the given integral expression. We have \( \int \frac{\sec z \tan z}{\sqrt{\sec z}} \, d z \). Notice that \( \frac{\sec z}{\sqrt{\sec z}} = \sqrt{\sec z} \). Thus, the integral simplifies to \( \int \tan z \sqrt{\sec z} \, d z \).
02

Substitute to Simplify Integration

To simplify the integration, let's use the substitution method. Let \( u = \sec z \), making \( \frac{d u}{d z} = \sec z \tan z \). Thus, \( d u = \sec z \tan z \, d z \). Substitute \( u \) into the integral: \( \int \tan z \sqrt{\sec z} \, d z = \int \sqrt{u} \, d u \).
03

Integrate Using Power Rule

Now, integrate \( \int \sqrt{u} \, d u \). Recall that \( \sqrt{u} \) can be rewritten as \( u^{1/2} \). The power rule for integration states \( \int u^n \, d u = \frac{u^{n+1}}{n+1} + C \). Applying this, we get \( \int u^{1/2} \, d u = \frac{u^{3/2}}{3/2} + C = \frac{2}{3} u^{3/2} + C \).
04

Substitute Back to Original Variable

Now, substitute back to the original variable \( z \) by replacing \( u \) with \( \sec z \). Thus, the integrated form becomes \( \frac{2}{3} (\sec z)^{3/2} + C \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Substitution Method
The substitution method is a powerful technique used to simplify hard-to-integrate expressions into more manageable forms. Think of it like changing the perspective on a problem to make it easier to solve. In the original problem, we deal with the integral \( \int \frac{\sec z \tan z}{\sqrt{\sec z}} \, d z \). To simplify this integration process, we can substitute a part of the expression with a new variable.Let's choose \( u = \sec z \). Why \( \sec z \)? Because when we look at its differential, \( \frac{d u}{d z} = \sec z \tan z \), it neatly matches part of our integral. This match lets us express \( dz \) in terms of \( du \), ultimately rewriting the integral in a simpler form, specifically \( \int \sqrt{u} \, d u \).Using substitutions can significantly reduce the complexity of integrals. The goal is to replace variables and expressions to match common integral forms that we already know how to solve.
Power Rule for Integration
The power rule for integration is as straightforward as it is handy. It gives us a quick way to integrate functions of the form \( x^n \). The rule states that for any real number \( n eq -1 \),\[ \int x^n \, dx = \frac{x^{n+1}}{n+1} + C,\]where \( C \) is the constant of integration.In our problem, after using the substitution method, the integral transformed into \( \int \sqrt{u} \, d u \), which is the same as \( \int u^{1/2} \, d u \). By applying the power rule:
  • Identify \( n \) as \( 1/2 \).
  • Apply the formula: \( \int u^{1/2} \, d u = \frac{u^{3/2}}{3/2} + C \).
  • Simplify the expression to \( \frac{2}{3} u^{3/2} + C \).
Understanding the power rule allows you to tackle a wide variety of integrals efficiently, especially when paired with substitution.
Trigonometric Integrals
Trigonometric integrals often involve expressions with functions like sine, cosine, tangent, and secant. These can seem daunting at first, but with practice, they become approachable.In our exercise, we initially had \( \frac{\sec z \tan z}{\sqrt{\sec z}} \). The key was recognizing that part of these trigonometric identities could be substituted to simplify the integral.When dealing with trigonometric integrals, a useful strategy is to look for patterns or relationships based on known trigonometric identities. For example, knowing that \( \tan x = \frac{\sin x}{\cos x} \) and \( \sec x = \frac{1}{\cos x} \) might help in spotting substitutions or simplifications to perform.Substitution, as seen before, is often paired with trigonometric integrals to turn the integral into a more straightforward algebraic form. Thus, mastering trigonometric integrals opens up a broad range of possibilities for solving varied and complex calculus problems.

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Most popular questions from this chapter

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