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Evaluate the integrals in Exercises \(1-26\) $$ \int_{0}^{4}\left(3 x-\frac{x^{3}}{4}\right) d x $$

Short Answer

Expert verified
The integral evaluates to 8.

Step by step solution

01

Identify the integral components

The given integral is \( \int_{0}^{4}\left(3 x-\frac{x^{3}}{4}\right) d x \). It consists of two functions, \( 3x \) and \( -\frac{x^3}{4} \), combined in a single expression. Both can be integrated separately.
02

Integrate each component separately

First, integrate \( 3x \). The integral of \( 3x \) with respect to \( x \) is \( \frac{3x^2}{2} \).Next, integrate \( -\frac{x^3}{4} \). The integral of \( -\frac{x^3}{4} \) with respect to \( x \) is \( -\frac{x^4}{16} \).
03

Combine the integrated components

Combine the results from the integration:\[ \int \left( 3x - \frac{x^3}{4} \right) dx = \frac{3x^2}{2} - \frac{x^4}{16} + C \] We don't include \( C \) as it's a definite integral.
04

Evaluate the definite integral from 0 to 4

Substitute the limits 0 and 4 into the integrated expression:\[\left[ \frac{3(4)^2}{2} - \frac{(4)^4}{16} \right] - \left[ \frac{3(0)^2}{2} - \frac{(0)^4}{16} \right]\]Compute each term:\[\frac{3(16)}{2} - \frac{256}{16} = 24 - 16 = 8.\]
05

Simplify the result

The value of the definite integral is simply the computed difference. As calculated:\[ 24 - 16 = 8 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Definite Integral
In calculus, a definite integral signifies the area under a curve within a stipulated interval. Consider \ \( \int_{a}^{b} f(x) \, dx \ \), where \( a \) and \( b \) are the lower and upper bounds, respectively. The integral calculates the total accumulation of \( f(x) \) from \( a \) to \( b \). For example, in the exercise \( \int_{0}^{4}\left(3 x-\frac{x^{3}}{4}\right) d x \), \( a \) is 0, and \( b \) is 4. This setup reflects an area under the function from \( x = 0 \) to \( x = 4 \).
Evaluating definite integrals involves determining the antiderivative and then computing the net area difference between the two bounds. The integration limits result in exact values rather than a function plus a constant of integration \( C \). Here, the final evaluation substitutes these bounds into the primitive function, yielding the numerical result.
Defining a clear start and end point allows us to calculate physical quantities such as displacement and total accumulated value over a segment, hence the common use of definite integrals in physics and engineering.
Polynomial Integration
Polynomial integration involves integrating algebraic expressions where the variables are raised to whole-number powers. An expression such as \( 3x - \frac{x^3}{4} \) consists of polynomial terms \( 3x \) and \( -\frac{x^3}{4} \). Polynomial integration leverages basic rules to solve each term independently.
To integrate any term \( ax^n \), we use the formula:
  • \( \int ax^n \, dx = \frac{a}{n+1}x^{n+1} + C \)
Using this, we can integrate \( 3x \) as \( \frac{3x^2}{2} \), where \( a = 3 \) and \( n = 1 \). Likewise, \(-\frac{x^3}{4} \) integrates to \( -\frac{x^4}{16} \), by applying the formula with \( a = -\frac{1}{4} \) and \( n = 3 \).
Mastering polynomial integration can serve as a powerful tool for tackling complex expressions, especially when they appear in more complex functions or real-world scenarios. Utilizing the integration rules allows for straightforward calculation of each polynomial part to yield the antiderivative.
Step-by-Step Solution
A step-by-step solution simplifies complex problems by breaking them down into manageable segments. Each step provides clarity and helps uncover the solution methodically. Let's go over the step-by-step solution in this context.
Firstly, identify the components of the function you need to integrate, as with \( 3x \) and \( -\frac{x^3}{4} \). Recognizing individual parts allows for easier manipulation under integration rules. Next, integrate each term using the integration rules appropriate for polynomials.
After integrating each component individually, combine them to form a complete antiderivative. Remember not to add the constant \( C \) since we're solving a definite integral. Follow it by evaluating the antiderivative at the boundaries of the integral, substituting the start and end values (0 and 4 in the exercise) into the antiderivative. Finally, calculate the numerical difference between these two results to obtain the value of the definite integral.
Engaging with problems using a step-by-step approach builds a stronger logical foundation and enhances understanding, allowing familiarity with more advanced calculus concepts later on.

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