Chapter 4: Problem 1
Minimizing perimeter What is the smallest perimeter possible for a rectangle whose area is 16 in. \(^{2}\) , and what are its dimensions?
Short Answer
Expert verified
The smallest perimeter is 16 inches, with dimensions 4 x 4 inches.
Step by step solution
01
Understand the Problem
You need to find the dimensions of a rectangle that minimize the perimeter, given its area is 16 square inches.
02
Area of Rectangle
The area of a rectangle is given by the formula: \( Area = length \times width \). For this problem, \( length \times width = 16 \).
03
Perimeter of Rectangle
The perimeter of a rectangle is given by \( P = 2(length + width) \). We want to minimize this perimeter.
04
Express Width in Terms of Length
Using the area equation \( width = \frac{16}{length} \). Substitute into the perimeter equation to get \( P = 2(length + \frac{16}{length}) \).
05
Differentiate Perimeter Function
Find the derivative of the perimeter function with respect to length: \( \frac{dP}{dl} = 2(1 - \frac{16}{l^2}) \).
06
Find Critical Points
Set the derivative equal to zero and solve for \( l \): \( 1 - \frac{16}{l^2} = 0 \), which implies \( l^2 = 16 \), so \( l = 4 \).
07
Determine Width
Substitute \( l = 4 \) back into the width equation: \( width = \frac{16}{4} = 4 \).
08
Calculate Perimeter
Substitute the values of length and width into the perimeter formula to find minimum perimeter: \( P = 2(4 + 4) = 16 \).
09
Verify Minimality
Since changing the dimensions alters the area without minimizing the perimeter further, a square with length and width as 4 in. each is appropriate and optimal.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Perimeter Minimization
Minimizing the perimeter of a geometric figure like a rectangle while maintaining a constant area is a classic optimization problem in calculus. In essence, you want to keep the boundary as short as possible while the area inside remains the same.
For a rectangle with a given area, the perimeter is minimized when the rectangle is as close to being a square as possible. This happens because a square configuration maximizes the amount of area enclosed for a given perimeter.
To solve perimeter minimization problems:
For a rectangle with a given area, the perimeter is minimized when the rectangle is as close to being a square as possible. This happens because a square configuration maximizes the amount of area enclosed for a given perimeter.
To solve perimeter minimization problems:
- Start with the area equation, ensuring that the product of length and width equals the desired area.
- Next, express the perimeter in terms of one variable, making it ripe for differentiation.
- Find the minimum perimeter by deriving and analyzing a critical point.
Derivative Application
Applying derivatives is a powerful tool in calculus, especially useful for finding maximum and minimum values, such as minimizing a perimeter. Differentiation gives us the rate of change of a function, allowing us to identify points where the function reaches its critical values — these are the maxima or minima.
Follow these steps to apply derivatives in optimization problems:
Follow these steps to apply derivatives in optimization problems:
- Formulate the problem in terms of a function and express it with a single variable.
- Differentiating this function with respect to that variable provides the necessary information about its behavior.
- Set the derivative equal to zero to determine critical points, which can indicate maxima or minima.
Rectangle Dimensions
Understanding the dimensions of a rectangle is essential in solving both geometric and optimization problems. The basic understanding of a rectangle involves its length and width, which together define its area and perimeter.
For an optimization problem like perimeter minimization, knowing how dimensions interact is crucial. A rectangle can continually shift dimensions while keeping its area constant — this flexibility requires us to strategically select the optimal dimensions.
Key points to consider about rectangle dimensions:
For an optimization problem like perimeter minimization, knowing how dimensions interact is crucial. A rectangle can continually shift dimensions while keeping its area constant — this flexibility requires us to strategically select the optimal dimensions.
Key points to consider about rectangle dimensions:
- The formula for the area, where length times width gives a constant value, is pivotal in finding compatible dimensions.
- The perimeter equation, which relies on the sum of length and width, guides us to minimize the perimeter.
- Reformulating either length or width based on the other using known constraints (like area) helps streamline problem-solving.