Chapter 3: Problem 60
Show that the approximation of \(\tan x\) by its linearization at the origin must improve as \(x \rightarrow 0\) by showing that . $$ \lim _{x \rightarrow 0} \frac{\tan x}{x}=1 $$
Short Answer
Expert verified
The limit is 1, confirming the approximation improves as \( x \to 0 \).
Step by step solution
01
Understand the linearization
The linearization of a function \( f(x) \) at a point \( a \) is given by \( f(a) + f'(a)(x-a) \). For \( \tan x \) at the origin (\( x = 0 \)), the linearization simplifies to \( x \) because \( \tan 0 = 0 \) and \( \sec^2 0 = 1 \).
02
Write the ratio to be evaluated
The problem requires us to find the limit of \( \frac{\tan x}{x} \) as \( x \to 0 \). For small \( x \), \( \tan x \approx x \), so we expect this ratio to approach 1.
03
Use Taylor series expansion
Expand \( \tan x \) using its Taylor series: \( \tan x = x + \frac{x^3}{3} + \frac{2x^5}{15} + \cdots \). For small \( x \), higher-order terms become negligible, giving us \( \tan x \approx x \).
04
Simplify the ratio
Substitute the expansion into the ratio: \( \frac{\tan x}{x} = \frac{x + \frac{x^3}{3} + \cdots}{x} = 1 + \frac{x^2}{3} + \cdots \) which approaches 1 as \( x \rightarrow 0 \).
05
Calculate the limit
Apply the limit directly: \[\lim_{x \to 0} \left( 1 + \frac{x^2}{3} + \cdots \right) = 1\]The limit of higher-order terms is zero as \( x \to 0 \).
06
Conclude the improvement
Since the limit \( \lim_{x \rightarrow 0} \frac{\tan x}{x}=1 \), the approximation of \( \tan x \) by \( x \) gets better as \( x \) approaches zero.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Linearization
Linearization is a technique used to approximate the value of a function near a certain point. It simplifies complex functions by using straight lines (linear functions).
For a function \( f(x) \), the linear approximation near a point \( a \) is given by:\[ f(a) + f'(a)(x-a) \]
This linear function, \( x \), serves as a close approximation to \( \tan x \) when \( x \) is near zero, which helps us understand how \( \tan x \) behaves in that vicinity.
For a function \( f(x) \), the linear approximation near a point \( a \) is given by:\[ f(a) + f'(a)(x-a) \]
- \( f(a) \) is the function value at the point \( a \).
- \( f'(a) \) is the derivative of the function at the point \( a \), indicating the slope of the tangent line.
This linear function, \( x \), serves as a close approximation to \( \tan x \) when \( x \) is near zero, which helps us understand how \( \tan x \) behaves in that vicinity.
Taylor Series
A Taylor series is a powerful tool for approximating functions.
It expresses a function as an infinite sum of terms, calculated from the derivatives of the function at a single point.
The Taylor series for a function \( f(x) \) centered at \( a \) is:\[ f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \frac{f'''(a)}{3!}(x-a)^3 + \cdots\]This series provides insight into how functions like \( \tan x \) can be approximated.
For \( \tan x \), the series expansion looks like:\[ \tan x = x + \frac{x^3}{3} + \frac{2x^5}{15} + \cdots\]
It expresses a function as an infinite sum of terms, calculated from the derivatives of the function at a single point.
The Taylor series for a function \( f(x) \) centered at \( a \) is:\[ f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \frac{f'''(a)}{3!}(x-a)^3 + \cdots\]This series provides insight into how functions like \( \tan x \) can be approximated.
For \( \tan x \), the series expansion looks like:\[ \tan x = x + \frac{x^3}{3} + \frac{2x^5}{15} + \cdots\]
- The first term \( x \) represents the linear approximation at zero.
- Higher-order terms (like \( \frac{x^3}{3} \)) become very small when \( x \) is near zero, refining the approximation.
Trigonometric Functions
Trigonometric functions play a crucial role in mathematics, especially for describing periodic phenomena.
When analyzing \( \tan x \) near \( x = 0 \), understanding of limits and infinitesimally small behavior becomes essential.
This is because standard trigonometric functions can be approximated by simpler components (like \( x \) and higher powers) to investigate their behavior in fine detail.
When approaching limit questions such as \( \lim_{x \to 0} \frac{\tan x}{x} = 1 \), recognizing that \( \tan x \approx x \) for small \( x \) is impactful, showcasing the blend of geometry and algebra that trigonometric functions encapsulate.
- Functions such as \( \sin x \), \( \cos x \), and \( \tan x \) are fundamental.
- These functions are periodic, meaning they repeat values in regular intervals.
When analyzing \( \tan x \) near \( x = 0 \), understanding of limits and infinitesimally small behavior becomes essential.
This is because standard trigonometric functions can be approximated by simpler components (like \( x \) and higher powers) to investigate their behavior in fine detail.
When approaching limit questions such as \( \lim_{x \to 0} \frac{\tan x}{x} = 1 \), recognizing that \( \tan x \approx x \) for small \( x \) is impactful, showcasing the blend of geometry and algebra that trigonometric functions encapsulate.