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Find the limits in Exercises \(23-26\). $$ \begin{array}{l}{\lim \left(2-\frac{3}{t^{1 / 3}}\right) \text { as }} \\\ {\text { a. } t \rightarrow 0^{+} \quad \text { b. } t \rightarrow 0^{-}}\end{array} $$

Short Answer

Expert verified
\(\lim_{t \to 0^+} \left(2-\frac{3}{t^{1/3}}\right) = -\infty\) and \(\lim_{t \to 0^-} \left(2-\frac{3}{t^{1/3}}\right) = +\infty\).

Step by step solution

01

Understand the Problem

We are given the expression \(2 - \frac{3}{t^{1/3}}\) and need to find the limit as \(t\) approaches zero from the positive side (\(t \to 0^+\)) and from the negative side (\(t \to 0^-\)). We analyze the behavior of \(\frac{3}{t^{1/3}}\) under these conditions.
02

Analyze \(t \to 0^+\)

For \(t \to 0^+\), \(t\) is a very small positive number. Consequently, \(t^{1/3}\) is also a small positive number, and \(\frac{3}{t^{1/3}}\) becomes very large and positive. Therefore, the expression \(2 - \frac{3}{t^{1/3}}\) becomes \(2 - \text{(large positive number)}\), which tends towards \(-\infty\).
03

Analyze \(t \to 0^-\)

For \(t \to 0^-\), \(t\) is a small negative number. \(t^{1/3}\) becomes a small negative number because the cube root of a negative number remains negative. Hence, \(\frac{3}{t^{1/3}}\) is a large negative number, making the expression \(2 - \text{(large negative number)}\) result in a very large positive number. This means the expression tends towards \(+\infty\).
04

Conclusion

Combining both analyses:- As \(t \to 0^+\), the limit is \(-\infty\).- As \(t \to 0^-\), the limit is \(+\infty\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

One-Sided Limits
One-sided limits simplify understanding how a function behaves as we approach a point from one direction. For instance, when dealing with the function \(2 - \frac{3}{t^{1/3}}\), we're particularly interested in seeing how this function behaves as \(t\) approaches zero from the right (positive side, \(t \to 0^+\)) and from the left (negative side, \(t \to 0^-\)).

  • Right-Hand Limit (\(t \to 0^+\)): Here, \(t\) is getting close to zero, but is positive. \(t^{1/3}\) will also be small and positive, making \(\frac{3}{t^{1/3}}\) a large positive number. So, \(2 - \frac{3}{t^{1/3}}\) tends towards \(-\infty\).
  • Left-Hand Limit (\(t \to 0^-\)): In this case, \(t\) approaches zero from the negative direction. \(t^{1/3}\) is negative and small, hence \(\frac{3}{t^{1/3}}\) becomes a large negative number. This makes \(2 - \frac{3}{t^{1/3}}\) head towards \(+\infty\).
Understanding these one-sided limits helps predict the direction in which a function heads as it near a point from specific paths.
Behavior of Functions
The behavior of functions, especially as they approach a specific point, reveals important insights into how that function behaves broadly. The function \(2 - \frac{3}{t^{1/3}}\) clearly shows different behaviors when \(t\) is near zero, depending on whether \(t\) is positive or negative.

  • When \(t\) is positive and close to zero, the behavior of \(\frac{3}{t^{1/3}}\) causes the entire expression to decrease rapidly, resulting in large negative values (\(-\infty\)).
  • With a negative \(t\) near zero, this changes dramatically. \(\frac{3}{t^{1/3}}\), being negative too, will subtract a large negative number (which effectively adds a large number), pushing the function far into positive values (\(+\infty\)).
Recognizing how different values of \(t\) affect the function helps build a more comprehensive understanding of its overall behavior.
Limits at Zero
Limits at zero can often indicate significant features about the continuity and performance of a function at and near this crucial point. For the expression \(2 - \frac{3}{t^{1/3}}\), examining the limit at zero from both sides reveals differing results.

  • From the positive side (\(t \to 0^+\)), the limit tends towards infinity in the negative direction. This suggests that just before reaching zero, the function drops off dramatically.
  • From the negative side (\(t \to 0^-\)), we're observing towards \(+\infty\). This captures a rapid upward shoot just as \(t\) crosses zero from the negative spectrum.
The asymmetrical nature of these behaviors represents a discontinuity at \(t = 0\). This indicates that the function doesn't settle into a single predictable value, but rather divides sharply between two extreme directions.

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