Chapter 2: Problem 17
Each of Exercises \(15-30\) gives a function \(f(x)\) and numbers \(L, x_{0}\) and \(\epsilon > 0 .\) In each case, find an open interval about \(x_{0}\) on which the inequality \(|f(x)-L| < \epsilon\) holds. Then give a value for \(\delta > 0\) such that for all \(x\) satisfying \(0 < \left|x-x_{0}\right| < \delta\) the inequality \(|f(x)-L| < \epsilon\) holds. $$ f(x)=\sqrt{x+1}, \quad L=1, \quad x_{0}=0, \quad \epsilon=0.1 $$
Short Answer
Step by step solution
Calculate the Function's Derivative
Evaluate the Derivative at \(x_0\)
Set Up Inequality for Distance Constraint
Solve the Inequality
Solve First Inequality
Solve Second Inequality
Determine Open Interval for \(x\)
Choose \(\delta\) Value
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Epsilon-Delta Definition
- \( |f(x) - L| < \epsilon \) whenever \( 0 < |x - x_0| < \delta \).
- \( \delta \) is the maximum allowable distance from \( x_0 \) to maintain the function's output close to \( L \).
Derivatives
- The derivative at a point \( x_0 \) provides insights into the function's slope at that location.
- A larger derivative value means the function changes rapidly, whereas a smaller derivative suggests gradual change.
- In our exercise, evaluating the derivative at \( x_0 = 0 \) helped us relate small changes in \( x \) to small changes in \( f(x) \).
Inequalities
- We transform problems involving functions into inequalities that we can manipulate mathematically. For \( f(x) = \sqrt{x+1} \), the inequality \( |\sqrt{x+1} - 1| < 0.1 \) creates boundaries for \( x \).
- These inequalities can be split and solved separately. Here, the two constraints, \( \sqrt{x+1} < 1.1 \) and \( \sqrt{x+1} > 0.9 \), define the open interval for \( x \).
Function Analysis
- We determined a suitable \( \delta \), as the smallest distance from \( x_0 \) that maintained the inequality \( |f(x) - L| < \epsilon \).
- The analysis of the open interval \(-0.19 < x < 0.21\) showed the extent of \( x \) values where the function stays close to the limit \( L \).
- Such deep analysis ensures that any disruptions in continuity can be captured and addressed.