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Parametrization of a surface of revolution Suppose that the parametrized curve \(C :(f(u), g(u))\) is revolved about the \(x\) -axis, where \(g(u)>0\) for \(a \leq u \leq b\) a. Show that $$\mathbf{r}(u, v)=f(u) \mathbf{i}+(g(u) \cos v) \mathbf{j}+(g(u) \sin v) \mathbf{k}$$ is a parametrization of the resulting surface of revolution, where \(0 \leq v \leq 2 \pi\) is the angle from the \(x y\) -plane to the point \(\mathbf{r}(u, v)\) on the surface. (See the accompanying figure.) Notice that \(f(u)\) measures distance along the axis of revolution and \(g(u)\) measures distance from the axis of revolution. b. Find a parametrization for the surface obtained by revolving the curve \(x=y^{2}, y \geq 0,\) about the \(x\) -axis.

Short Answer

Expert verified
The surface is parametrized by \( \textbf{r}(t, v) = t^2 \textbf{i} + (t \cos v) \textbf{j} + (t \sin v) \textbf{k} \).

Step by step solution

01

Understanding the Surface of Revolution

A surface of revolution is created when a curve is revolved around an axis. Here, the curve is \((f(u), g(u))\) and it is revolved around the \(x\)-axis. The parameter \(u\) represents points on the curve, while \(v\) is the angle of rotation about the \(x\)-axis.
02

Set the Parametric Equation

When the curve \((f(u), g(u))\) is revolved around the \(x\)-axis, points on the curve trace circles in planes perpendicular to the \(x\)-axis. The parametric equation \[\textbf{r}(u, v) = f(u)\textbf{i} + (g(u) \cos v)\textbf{j} + (g(u) \sin v)\textbf{k}\] represents this, where \(f(u)\) is the distance along the axis and \(g(u)\) is the radius of the circle traced by rotation.
03

Step a: Parametrization Verification

To verify the given parametric equation: 1. Rotate the point \((f(u), g(u))\) around the \(x\)-axis, noting that the \(x\)-coordinate remains \(f(u)\).2. The \(y\)- and \(z\)-coordinates form a circle of radius \(g(u)\) in the plane. Based on trigonometry, this yields \(g(u)\cos v\) as the \(y\)-coordinate and \(g(u)\sin v\) as the \(z\)-coordinate.3. Thus, the parametric form is correct for the surface created by this revolution.
04

Parametrizing a Specific Curve

Given the curve \(x = y^2\), with the parameterized form: 1. Derive parametrization with \(y = t\) such that \(x = t^2\).2. This gives \(f(t) = t^2\) and \(g(t) = t\).3. Substitute in the surface of revolution equation to get: \[ \textbf{r}(t, v) = t^2 \textbf{i} + (t \cos v) \textbf{j} + (t \sin v) \textbf{k} \] for \(t \geq 0\) and \(0 \leq v \leq 2\pi\).
05

Short Summary

By revolving the curve around the \(x\)-axis, the parametric function for any curve \((f(u), g(u))\) is given by \( \textbf{r}(u, v) = f(u)\textbf{i} + (g(u) \cos v)\textbf{j} + (g(u) \sin v)\textbf{k} \). For \(x = y^2\), this resolves to \( \textbf{r}(t, v) = t^2 \textbf{i} + (t \cos v) \textbf{j} + (t \sin v) \textbf{k} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parametrization
Parametrization is about expressing a curve or a surface using parameters. When dealing with surfaces of revolution, we look at revolving a curve around an axis to form a surface. Often, these surfaces are revolved about the x-axis. For example, consider the curve \( (f(u), g(u)) \). The parameter \( u \) helps us understand the positions along this curve. Basically, \( u \) decides the point we pick from the curve.
The process of parametrization in creating surfaces of revolution involves describing the entire surface through a set of parameters. Here, we involve two parameters, \( u \), which traces along the curve, and \( v \), which manages the angle of rotation.
  • \( f(u) \) is critical in measuring how far along the axis of rotation a point is.
  • \( g(u) \) shows how far the point is from the axis, contributing to the surface's circular shape.
By using these parameters, we transform a simple curve into a 3D shape. Thus, parametrization becomes essential in understanding complex surfaces.
Parametric Equations
Parametric equations are equations that use one or more variables, called parameters, to define curves or surfaces. In the context of surfaces of revolution, these act as the mathematical backbone for defining 3D shapes. We use parametric equations to illustrate complex geometries in easier, stepwise formats.
Consider the formula: \[ \textbf{r}(u, v) = f(u)\textbf{i} + (g(u) \cos v)\textbf{j} + (g(u) \sin v)\textbf{k} \] This explains the points on a surface of revolution around the x-axis.
  • The term \( f(u)\textbf{i} \) shows how far the point is along the x-axis.
  • \( (g(u) \cos v)\textbf{j} \) and \( (g(u) \sin v)\textbf{k} \) describe the radius of rotation, forming a circle.
By exploring these components, you can visualize how a simple 2D curve, when swept around an axis, evolves into a vast, complex surface. This transformation is vital for engineering, computer graphics, and physics.
Curve Transformation
Curve transformation is the process of taking a known curve and manipulating it to understand how it behaves when moved or reshaped. In this context, we're interested in revolving curves to generate a 3D surface. For instance, when we look at the curve given by \( x = y^2 \) which has \( y \geq 0 \), we want to transform this 2D view into a 3D surface.
Here's how it unfolds:
  • Parametrize the curve using \( y = t \), giving \( x = t^2 \).
  • This translates to \( f(t) = t^2 \) and \( g(t) = t \).

Using the parametric equation for surfaces of revolution, we set up:
\[ \textbf{r}(t, v) = t^2 \textbf{i} + (t \cos v)\textbf{j} + (t \sin v)\textbf{k} \] for \( t \geq 0 \) and \( 0 \leq v \leq 2\pi \).
This transformation moves each point on the parabola \( x = y^2 \) into a circular path, effectively forming a parabolic sheet around the x-axis. Curve transformations help bridge dimensions, turning familiar 2D curves into their 3D counterparts, unveiling new insights into geometry and space.

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Most popular questions from this chapter

In Exercises \(21-26,\) find the flux of the field \(\mathbf{F}\) across the portion of the sphere \(x^{2}+y^{2}+z^{2}=a^{2}\) in the first octant in the direction away from the origin. $$ \mathbf{F}(x, y, z)=z \mathbf{k} $$

Find the outward flux of the field \(\mathbf{F}=x z \mathbf{i}+y z \mathbf{j}+\mathbf{k}\) across the surface of the upper cap cut from the solid sphere \(x^{2}+y^{2}+z^{2} \leq 25\) by the plane \(z=3\)

In Exercises \(1-6,\) use the surface integral in Stokes' Theorem to calculate the circulation of the field \(\mathbf{F}\) around the curve \(C\) in the indicated direction. \(\mathbf{F}=x^{2} y^{3} \mathbf{i}+\mathbf{j}+z \mathbf{k}\) \(C :\) The intersection of the cylinder \(x^{2}+y^{2}=4\) and the hemisphere \(x^{2}+y^{2}+z^{2}=16, z \geq 0,\) counterclockwise when viewed from above.

Flux of a gradient field Let \(S\) be the surface of the portion of the solid sphere \(x^{2}+y^{2}+z^{2} \leq a^{2}\) that lies in the first octant and let \(f(x, y, z)=\ln \sqrt{x^{2}+y^{2}+z^{2}}\) . Calculate $$ \iint_{S} \nabla f \cdot \mathbf{n} d \sigma $$ \((\nabla f \cdot \mathbf{n}\) is the derivative of \(f\) in the direction of \(\mathbf{n} . )\)

Let \(\mathbf{F}\) be a differentiable vector field defined on a region containing a smooth closed oriented surface \(S\) and its interior. Let \(\mathbf{n}\) be the unit normal vector field on \(S .\) Suppose that \(S\) is the union of two surfaces \(S_{1}\) and \(S_{2}\) joined along a smooth simple closed curve \(C .\) Can anything be said about $$ \iint_{S} \nabla \times \mathbf{F} \cdot \mathbf{n} d \sigma ? $$ Give reasons for your answer.

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