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In Exercises \(21-26,\) find the flux of the field \(\mathbf{F}\) across the portion of the sphere \(x^{2}+y^{2}+z^{2}=a^{2}\) in the first octant in the direction away from the origin. $$ \begin{array}{c}{\mathbf{F}(x, y, z)=x \mathbf{i}+y \mathbf{j}+z \mathbf{k}} \\\ {x \mathbf{i}+y \mathbf{j}+z \mathbf{k}}\end{array} $$

Short Answer

Expert verified
The flux is \( \frac{\pi}{2}a^4 \).

Step by step solution

01

Define the Flux Integral

The flux of a vector field \( \mathbf{F} \) through a surface \( S \) is given by the surface integral \( \iint_{S} \mathbf{F} \cdot d\mathbf{S} \), where \( d\mathbf{S} \) is the outward-oriented surface element.
02

Determine the Surface Parameters

For the sphere \( x^2 + y^2 + z^2 = a^2 \) in the first octant, we'll parameterize it using spherical coordinates with restrictions for the first octant (where \( x, y, z \geq 0 \)). The parameterization is \( x = a\sin\theta\cos\phi \), \( y = a\sin\theta\sin\phi \), \( z = a\cos\theta \) where \( 0 \leq \theta \leq \pi/2 \) and \( 0 \leq \phi \leq \pi/2 \).
03

Calculate the Normal Vector

The normal to the surface \( d\mathbf{S} \) is given by \( \mathbf{n} \, dS \), where \( \mathbf{n} \) is the unit normal vector to the outward direction, simply \( \mathbf{n} = \frac{\mathbf{r}}{|\mathbf{r}|} = \frac{\langle x, y, z \rangle}{a} \). Hence, \( d\mathbf{S} = \langle x, y, z \rangle \, dS \).
04

Compute \( \mathbf{F} \cdot d\mathbf{S} \)

Substitute \( \mathbf{F}(x, y, z) = \langle x, y, z \rangle \) and \( d\mathbf{S} = \langle x, y, z \rangle \, dS \) to get \( \mathbf{F} \cdot d\mathbf{S} = \langle x, y, z \rangle \cdot \langle x, y, z \rangle \, dS = (x^2 + y^2 + z^2) \, dS \). Since \( x^2 + y^2 + z^2 = a^2 \), we have \( \mathbf{F} \cdot d\mathbf{S} = a^2 \, dS \).
05

Set Up and Evaluate the Integral

The flux integral then becomes \( \iint_{S} a^2 \, dS \). The area element in spherical coordinates is \( a^2\sin\theta \, d\theta \, d\phi \). Thus, the integral is \(\int_{0}^{\pi/2} \int_{0}^{\pi/2} a^2 a^2\sin\theta \, d\theta \, d\phi = a^4 \int_{0}^{\pi/2} \int_{0}^{\pi/2} \sin\theta \, d\theta \, d\phi \).Smoothly evaluate this, \(\int_{0}^{\pi/2} \sin\theta \, d\theta = 1\) and \( \int_{0}^{\pi/2} d\phi = \frac{\pi}{2} \).
06

Compute the Final Flux Value

Thus, the total flux is \( a^4 \times 1 \times \frac{\pi}{2} = \frac{\pi}{2}a^4 \). Therefore, the flux of the field \( \mathbf{F} \) across the portion of the sphere in the first octant away from the origin is \( \frac{\pi}{2}a^4 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spherical Coordinates
Spherical coordinates are an essential tool in calculus, especially when dealing with problems that have spherical symmetry. Unlike Cartesian coordinates, which use
  • rectangular components (x, y, z),
spherical coordinates describe a point in space using three values:
  • radius \(r\),
  • polar angle \(\theta\),
  • azimuthal angle \(\phi\).

In the exercise, the equation of the sphere is \(x^2 + y^2 + z^2 = a^2\). The points on this sphere can be expressed in spherical coordinates as:
  • \(x = a\sin\theta\cos\phi\),
  • \(y = a\sin\theta\sin\phi\),
  • \(z = a\cos\theta\).

The angle \(\theta\) represents the inclination from the positive z-axis, while \(\phi\) is the azimuthal angle within the xy-plane.
For the first octant, both \(\theta\) and \(\phi\) range from 0 to \(\pi/2\). This restriction ensures that \((x, y, z)\) are all non-negative, fitting the conditions of the first octant.
Surface Integral
Surface integrals are used to calculate the effect of a field across a surface. When dealing with vector fields, surface integrals determine quantities like flux.
The flux is essentially the amount of the vector field going through the surface. Mathematically, this is given by \[ \iint_{S} \mathbf{F} \cdot d\mathbf{S}, \] where \(S\) is the surface. Here, \(d\mathbf{S} \) is the differential surface element, which takes into account both the area of infinitesimally small surface patches and their orientation.

In context, for the sphere \(x^2 + y^2 + z^2 = a^2\) in the first octant, we are interested in how much of the vector field \(\mathbf{F}(x, y, z) = x\mathbf{i} + y\mathbf{j} + z\mathbf{k}\) passes through this portion of the sphere.
Surface integrals are a core concept in electromagnetism, fluid dynamics, and other fields where vector fields interact with surfaces.
Parameterization
Parameterization is a way to express a surface using a set of parameters, providing an alternative to the implicit description of the surface.
In this scenario, the sphere is parameterized using spherical coordinates.
  • This converts the challenging surface integral over the sphere into a more manageable double integral over the angles \(\theta\) and \(\phi\).

Parameterization allows us to change variables and simplify the calculation in integral problems, making it easier to perform the integration.
By using the equations \(x = a\sin\theta\cos\phi\), \(y = a\sin\theta\sin\phi\), and \(z = a\cos\theta\), we translate the problem from one complicated in \(xyz\) coordinates to one that is relatively straightforward in terms of \(\theta\) and \(\phi\).
This method greatly assists in evaluating integrals over complex surfaces like portions of spheres, where direct calculation would otherwise be cumbersome.
Flux Integral
The flux integral measures how much of a field passes through a specific surface. It's essential for understanding phenomena in physics such as fluid flow or electric and magnetic field interactions.
In the given problem, the goal is to find the flux of a vector field \(\mathbf{F} = x\mathbf{i} + y\mathbf{j} + z\mathbf{k}\) through the portion of a sphere in the first octant.
This requires the calculation of \[ \iint_{S} \mathbf{F} \cdot d\mathbf{S}. \] Here, \(d\mathbf{S} = \langle x, y, z \rangle \, dS\), where \(dS\) is the area element and \(\langle x, y, z \rangle\) is the normal vector.
This simplifies to \(\mathbf{F} \cdot d\mathbf{S} = a^2 \, dS\) by substituting the parameterization, which aligns with the sphere's definition \(x^2 + y^2 + z^2 = a^2\).
Understanding flux integrals is crucial in several fields, making it a fundamental part of vector calculus.

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Most popular questions from this chapter

The tangent plane at a point \(P_{0}\left(f\left(u_{0}, v_{0}\right), g\left(u_{0}, v_{0}\right), h\left(u_{0}, v_{0}\right)\right)\) on a parametrized surface \(\mathbf{r}(u, v)=f(u, v) \mathbf{i}+g(u, v) \mathbf{j}+h(u, v) \mathbf{k}\) is the plane through \(P_{0}\) normal to the vector \(\mathbf{r}_{u}\left(u_{0}, v_{0}\right) \times \mathbf{r}_{v}\left(u_{0}, v_{0}\right),\) the cross product of the tangent vectors \(\mathbf{r}_{u}\left(u_{0}, v_{0}\right)\) and \(\mathbf{r}_{v}\left(u_{0}, v_{0}\right)\) at \(P_{0} .\) In Exercises \(49-52,\) find an equation for the plane tangent to the surface at \(P_{0} .\) Then find a Cartesian equation for the surface and sketch the surface and tangent plane together. Cone The cone \(\mathbf{r}(r, \theta)=(r \cos \theta) \mathbf{i}+(r \sin \theta) \mathbf{j}+r \mathbf{k}, r \geq 0\) \(0 \leq \theta \leq 2 \pi\) at the point \(P_{0}(\sqrt{2}, \sqrt{2}, 2)\) corresponding to \((r, \theta)=(2, \pi / 4)\)

In Exercises \(25-28\) , find the circulation and flux of the field \(F\) around and across the closed semicircular path that consists of the semicircular arch \(\mathbf{r}_{1}(t)=(a \cos t) \mathbf{i}+(a \sin t) \mathbf{j}, 0 \leq t \leq \pi,\) followed by the line segment \(\mathbf{r}_{2}(t)=t \mathbf{i},-a \leq t \leq a\) $$ \mathbf{F}=-y^{2} \mathbf{i}+x^{2} \mathbf{j} $$

In Exercises \(27-34,\) integrate the given function over the given surface. Cone \(F(x, y, z)=z-x,\) over the cone \(z=\sqrt{x^{2}+y^{2}}\) \(0 \leq z \leq 1\)

Path of least work You have been asked to find the path along which a force field \(\mathbf{F}\) will perform the least work in moving a particle between two locations. A quick calculation on your part shows \(\mathbf{F}\) to be conservative. How should you respond? Give reasons for your answer.

Bendixson's criterion The streamlines of a planar fluid flow are the smooth curves traced by the fluid's individual particles. The vectors \(\mathbf{F}=M(x, y) \mathbf{i}+N(x, y) \mathbf{j}\) of the flow's velocity field are the tangent vectors of the streamlines. Show that if the flow takes place over a simply connected region \(R\) (no holes or missing points) and that if \(M_{x}+N_{y} \neq 0\) throughout \(R\) , then none of the streamlines in \(R\) is closed. In other words, no particle of fluid ever has a closed trajectory in \(R .\) The criterion \(M_{x}+N_{y} \neq 0\) is called Bendixson's criterion for the nonexistence of closed trajectories.

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