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\(\operatorname{div}(\operatorname{curl} G)\) is zero a. Show that if the necessary partial derivatives of the components of the field \(\mathbf{G}=M \mathbf{i}+N \mathbf{j}+P \mathbf{k}\) are continuous, then \(\nabla \cdot \nabla \times \mathbf{G}=0 .\) b. What, if anything, can you conclude about the flux of the field \(\nabla \times \mathbf{G}\) across a closed surface? Give reasons for your answer.

Short Answer

Expert verified
a. \( \nabla \cdot \nabla \times \mathbf{G} = 0 \). b. No net flux; the flux across a closed surface is zero.

Step by step solution

01

Understand the Formula for Curl

The curl of a vector field \( \mathbf{G} = M \mathbf{i} + N \mathbf{j} + P \mathbf{k} \) is given by:\[abla \times \mathbf{G} = \left(\frac{\partial P}{\partial y} - \frac{\partial N}{\partial z}\right) \mathbf{i} + \left(\frac{\partial M}{\partial z} - \frac{\partial P}{\partial x}\right) \mathbf{j} + \left(\frac{\partial N}{\partial x} - \frac{\partial M}{\partial y}\right) \mathbf{k}\]
02

Apply Divergence to the Curl

The divergence of the curl of the vector field \( \mathbf{G} \) is computed as:\[abla \cdot abla \times \mathbf{G} = \frac{\partial}{\partial x} \left(\frac{\partial P}{\partial y} - \frac{\partial N}{\partial z}\right) + \frac{\partial}{\partial y} \left(\frac{\partial M}{\partial z} - \frac{\partial P}{\partial x}\right) + \frac{\partial}{\partial z} \left(\frac{\partial N}{\partial x} - \frac{\partial M}{\partial y}\right)\]
03

Recognize Zero Identity for Divergence of Curl

If the necessary partial derivatives are continuous, then each term in the divergence of the curl cancels out due to the symmetry of second derivatives (i.e., \( \frac{\partial^2}{\partial x \partial y} = \frac{\partial^2}{\partial y \partial x} \)). Thus:\[abla \cdot abla \times \mathbf{G} = 0\]This establishes that the divergence of the curl of any vector field is always zero.
04

Discuss Implications for Flux Across a Closed Surface

The divergence theorem states that the flux of a vector field \( \mathbf{F} \) across a closed surface \( S \) is equal to the integral of its divergence over the volume \( V \) enclosed by the surface. For \( abla \times \mathbf{G} \), since \( abla \cdot abla \times \mathbf{G} = 0 \), the integral over any volume \( V \) is zero, implying the flux across any closed surface \( S \) is zero. This means that the field \( abla \times \mathbf{G} \) has no net flux across \( S \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Divergence
The concept of divergence is central in vector calculus. It provides a measure of how much a vector field spreads out from a given point. Imagine a field representing wind blowing across a landscape. If the wind seems to be expanding outwards or converging inward at a certain location, that's divergence in action. Mathematically, divergence is denoted by \( abla \cdot \mathbf{F} \), where \( \mathbf{F} \) is a vector field.
  • It involves taking the dot product of the gradient operator with the vector field.
  • This operation results in a scalar field, representing the rate of outflux per unit volume at each point.
To put it simply, divergence tells us how much a field "diverges" from, or spreads out around, a particular point.
Curl
Curl is another fundamental concept in vector calculus that describes the tendency of rotation or swirling of a vector field. Consider water swirling as it goes down a drain; this swirling motion is similar to what curl measures. The curl of a vector field \( \mathbf{G} = M \mathbf{i} + N \mathbf{j} + P \mathbf{k} \) is computed using the formula:\[abla \times \mathbf{G} = \left(\frac{\partial P}{\partial y} - \frac{\partial N}{\partial z}\right) \mathbf{i} + \left(\frac{\partial M}{\partial z} - \frac{\partial P}{\partial x}\right) \mathbf{j} + \left(\frac{\partial N}{\partial x} - \frac{\partial M}{\partial y}\right) \mathbf{k}\]
  • Curl produces another vector field as its result.
  • It quantifies the amount of "twisting" at a point within the field.
Curl is crucial in understanding the rotational characteristics of fields like magnetic and fluid dynamics.
Flux
Flux measures the quantity of a vector field that passes through a given surface. It's akin to how much wind flows through a window. You can visualize this as the number or strength of field lines crossing through a surface.
  • If you have a vector field \( \mathbf{F} \) and a surface \( S \), the flux through \( S \) is captured by the surface integral \( \int_S \mathbf{F} \cdot d\mathbf{A} \), where \( d\mathbf{A} \) is an infinitesimal area vector on \( S \).
  • Flux can be thought of as the "flow strength" through a surface.
Understanding flux helps in many practical applications, like determining the flow of fluids or the intensity of electric fields through surfaces.
Divergence Theorem
The Divergence Theorem, also known as Gauss's theorem, links the divergence of a vector field to the flux through a closed surface. It's a powerful tool that simplifies the calculation of flux.Here's what the theorem states:The flux of a field \( \mathbf{F} \) across a closed surface \( S \) is equal to the integral of the divergence of \( \mathbf{F} \) over the volume \( V \) that \( S \) encloses, i.e., \[\int_S \mathbf{F} \cdot d\mathbf{A} = \int_V (abla \cdot \mathbf{F}) \, dV\]
  • It shows a deep connection between surface integrals and volume integrals.
  • When applied to \( abla \times \mathbf{G} \), since its divergence is zero, its flux through any closed surface is zero.
This theorem is not only fundamental in theoretical calculations but is also extensively applied in fields like electromagnetism and fluid dynamics to simplify complex problems.

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Most popular questions from this chapter

In Exercises \(13-18\) , use the surface integral in Stokes' Theorem to calculate the flux of the curl of the field \(\mathbf{F}\) across the surface \(S\) in the direction of the outward unit normal \(\mathbf{n} .\) $$ \begin{array}{l}{\mathbf{F}=2 z \mathbf{i}+3 x \mathbf{j}+5 y \mathbf{k}} \\\ {S : \mathbf{r}(r, \theta)=(r \cos \theta) \mathbf{i}+(r \sin \theta) \mathbf{j}+\left(4-r^{2}\right) \mathbf{k}} \\ {0 \leq r \leq 2, \quad 0 \leq \theta \leq 2 \pi}\end{array} $$

In Exercises \(35-44,\) use a parametrization to find the flux \(\iint_{S} \mathbf{F} \cdot \mathbf{n} d \sigma\) across the surface in the given direction. Parabolic cylinder \(\mathbf{F}=x^{2} \mathbf{j}-x z \mathbf{k}\) outward (normal away from the \(y z\) -plane) through the surface cut from the parabolic cylinder \(y=x^{2},-1 \leq x \leq 1,\) by the planes \(z=0\) and \(z=2\)

Bendixson's criterion The streamlines of a planar fluid flow are the smooth curves traced by the fluid's individual particles. The vectors \(\mathbf{F}=M(x, y) \mathbf{i}+N(x, y) \mathbf{j}\) of the flow's velocity field are the tangent vectors of the streamlines. Show that if the flow takes place over a simply connected region \(R\) (no holes or missing points) and that if \(M_{x}+N_{y} \neq 0\) throughout \(R\) , then none of the streamlines in \(R\) is closed. In other words, no particle of fluid ever has a closed trajectory in \(R .\) The criterion \(M_{x}+N_{y} \neq 0\) is called Bendixson's criterion for the nonexistence of closed trajectories.

Conservation of mass \(\quad\) Let \(\mathbf{v}(t, x, y, z)\) be a continuously differ- entiable vector field over the region \(D\) in space and let \(p(t, x, y, z)\) be a continuously differentiable scalar function. The variable \(t\) represents the time domain. The Law of Conservation of Mass asserts that $$\frac{d}{d t} \iiint_{D} p(t, x, y, z) d V=-\iint_{S} p \mathbf{v} \cdot \mathbf{n} d \sigma$$ where \(S\) is the surface enclosing \(D\) a. Give a physical interpretation of the conservation of mass law if \(v\) is a velocity flow field and \(p\) represents the density of the fluid at point \((x, y, z)\) at time \(t .\) b. Use the Divergence Theorem and Leibniz's Rule, $$\frac{d}{d t} \iiint_{D} p(t, x, y, z) d V=\iiint_{D} \frac{\partial p}{\partial t} d V$$ to show that the Law of Conservation of Mass is equivalent to the continuity equation, $$\nabla \cdot p \mathbf{v}+\frac{\partial p}{\partial t}=0$$ (In the first term \(\nabla \cdot p \mathbf{v}\) , the variable \(t\) is held fixed, and in the second term \(\partial p / \partial t,\) it is assumed that the point \((x, y, z)\) in \(D\) is held fixed.)

In Exercises \(47-52,\) use a CAS to perform the following steps for finding the work done by force \(\mathbf{F}\) over the given path: a. Find \(d \mathbf{r}\) for the path \(\mathbf{r}(t)=g(t) \mathbf{i}+h(t) \mathbf{j}+k(t) \mathbf{k}\) b. Evaluate the force \(\mathbf{F}\) along the path. c. Evaluate \(\int_{C} \mathbf{F} \cdot d \mathbf{r}\) $$ \begin{array}{l}{\mathbf{F}=\left(x^{2} y\right) \mathbf{i}+\frac{1}{3} x^{3} \mathbf{j}+x y \mathbf{k} ; \quad \mathbf{r}(t)=(\cos t) \mathbf{i}+(\sin t) \mathbf{j}+} \\ {\left(2 \sin ^{2} t-1\right) \mathbf{k}, \quad 0 \leq t \leq 2 \pi}\end{array} $$

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