Chapter 16: Problem 10
In Exercises \(7-12,\) find a potential function \(f\) for the field \(\mathbf{F}\) $$ \mathbf{F}=(y \sin z) \mathbf{i}+(x \sin z) \mathbf{j}+(x y \cos z) \mathbf{k} $$
Short Answer
Expert verified
The potential function is \( f(x, y, z) = xy \sin z + C \).
Step by step solution
01
Identify Potential Function
A potential function for a vector field \( \mathbf{F} = (y \sin z) \mathbf{i} + (x \sin z) \mathbf{j} + (xy \cos z) \mathbf{k} \) can be determined if it is conservative. A conservative vector field \( \mathbf{F} \) is one where there exists a scalar function \( f(x, y, z) \) such that \( \mathbf{F} = abla f \). Start by observing the components: \( F_x = y \sin z \), \( F_y = x \sin z \), and \( F_z = xy \cos z \).
02
Determine Each Component's Contribution
Since \( \mathbf{F} = abla f \), we use \( f_x = y \sin z \), \( f_y = x \sin z \), and \( f_z = xy \cos z \). The partial derivatives lead us to integrate each component separately, ensuring consistency across variables.
03
Integrate First Component for \( f(x, y, z) \)
Integrate \( f_x = y \sin z \) with respect to \( x \):\[ f(x, y, z) = \int y \sin z \, dx = xy \sin z + g(y, z)\]where \( g(y, z) \) is an arbitrary function of \( y \) and \( z \).
04
Integrate Second Component for Consistency
Next, integrating the second component \( f_y = x \sin z \) with respect to \( y \):\[ xy \sin z + h(x, z) = \int x \sin z \, dy = xy \sin z + h(x, z)\]This implies \( g(y, z) = h(x, z) \).
05
Check Third Component for Completeness
Differentiate \( f(x, y, z) = xy \sin z + g(y, z) \) with respect to \( z \) and set it equal to \( f_z \):\[ \frac{\partial}{\partial z} [xy \sin z + g(y, z)] = xy \cos z + \frac{\partial g}{\partial z} = xy \cos z\]Thus, \( \frac{\partial g}{\partial z} = 0 \), ensuring that \( g(y, z) \) is independent of \( z \), i.e., \( g(y, z) = C \), where \( C \) is a constant.
06
Compose Potential Function
After confirming the components, the potential function \( f(x, y, z) \) is:\[ f(x, y, z) = xy \sin z + C\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Potential Function
A potential function is a scalar function whose gradient yields a given vector field. In essence, if a vector field \( \mathbf{F} \) is conservative, there is a scalar function \( f(x, y, z) \) such that \( abla f = \mathbf{F} \). This means the function \( f \) describes a field of potential energy from which the vector field can be derived. To find this potential function, the components of the vector field \( \mathbf{F} \) are expressed as the partial derivatives \( f_x, f_y, \) and \( f_z \) of the potential function \( f \). Solving for \( f \) involves integrating these partial derivatives. The challenge is ensuring consistency across different variables so that the discovered \( f \) represents fully the vector field.
Conservative Vector Field
A conservative vector field is characterized by being the gradient of some scalar potential function. This means that the work done by moving along a path in the vector field is independent of the path taken, depending only on the end points. **Key Properties of Conservative Vector Fields:**
- The line integral over any closed path is zero.
- Such a field can be described by a scalar potential function \( f \) such that \( \mathbf{F} = abla f \).
- The vector field is irrotational, meaning its curl is zero: \( abla \times \mathbf{F} = \mathbf{0} \).
Partial Derivatives
Partial derivatives represent how a function changes as one of its input variables changes, while the others are held constant. In the context of potential functions and conservative vector fields, the components of a vector field correspond to the partial derivatives of the potential function:
- Given \( \mathbf{F} = abla f \), \( F_x \) relates to \( f_x \), the derivative of \( f \) with respect to \( x \).
- Similarly, \( F_y = f_y \) and \( F_z = f_z \).
Integration
Integration is the process of finding the antiderivative of a function. In vector calculus, integration is used to determine the potential function from its partial derivatives. Let us break down the process: - Start with the component expressions of the vector field, corresponding to \( f_x, f_y, \) and \( f_z \). - Integrate each component to find part of the potential function. - Make sure to consider arbitrary functions that can arise during integration, ensuring these are consistent with the other components. During the integration of \( f_x = y \sin z \), for example, integrating with respect to \( x \) gives \( xy \sin z + g(y, z) \), where \( g(y, z) \) is an arbitrary function that depends on \( y \) and \( z \). Checking subsequent components helps refine this arbitrary function, leading to the full potential function. This intricate process ensures that the reconstructed function truly represents the original vector field consistently.