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In Exercises \(1-8,\) find equations for the (a) tangent plane and (b) normal line at the point \(P_{0}\) on the given surface. $$ x^{2}-x y-y^{2}-z=0, \quad P_{0}(1,1,-1) $$

Short Answer

Expert verified
Tangent plane: \( x - 3y - z + 3 = 0 \); Normal line: \( x = 1 + t, y = 1 - 3t, z = -1 - t \).

Step by step solution

01

Find Gradient of the Surface Function

The given surface is defined by the function \( f(x, y, z) = x^2 - xy - y^2 - z \). To find the tangent plane and normal line, we first calculate the gradient \( abla f \). The gradient is given by \[ abla f = \left( \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}, \frac{\partial f}{\partial z} \right). \]Compute the partial derivatives:- \( \frac{\partial f}{\partial x} = 2x - y \)- \( \frac{\partial f}{\partial y} = -x - 2y \)- \( \frac{\partial f}{\partial z} = -1 \).Thus, the gradient vector is \( abla f = (2x - y, -x - 2y, -1) \).
02

Evaluate the Gradient at Point \(P_0\)

Substitute the point \( P_0(1, 1, -1) \) into the gradient to find its specific value at this point.- \( \frac{\partial f}{\partial x} = 2(1) - 1 = 1 \)- \( \frac{\partial f}{\partial y} = -1 - 2(1) = -3 \)- \( \frac{\partial f}{\partial z} = -1 \)Thus, \( abla f(1, 1, -1) = (1, -3, -1) \). This is the normal vector at \( P_0 \).
03

Write the Equation of the Tangent Plane

The equation of the tangent plane at a point \((x_0, y_0, z_0)\) with normal vector \(a, b, c\) is given by:\[ a(x - x_0) + b(y - y_0) + c(z - z_0) = 0 \].Using the normal vector \((1, -3, -1)\) and point \((1, 1, -1)\), the tangent plane equation is:\[ 1(x - 1) - 3(y - 1) - 1(z + 1) = 0 \].Simplifying, we have:\[ x - 3y - z + 3 = 0 \].
04

Write the Equation of the Normal Line

The equation of the normal line can be written in parametric form using the point and the normal vector:- \( x = x_0 + at \)- \( y = y_0 + bt \)- \( z = z_0 + ct \)For \( P_0 = (1, 1, -1) \) and normal vector \( (1, -3, -1) \), the parametric equations are:\[\begin{align*}x &= 1 + t \y &= 1 - 3t \z &= -1 - t\end{align*}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gradient Vector
The gradient vector is a critical aspect when working with surfaces and their properties, like tangent planes and normal lines. It is essentially a vector that summarizes how a function changes at any point across its three dimensions. The gradient of a scalar field, such as our surface equation, is obtained by taking the partial derivatives of the function with respect to each variable:
  • Partial derivative with respect to x, denoted as \( \frac{\partial f}{\partial x} \).
  • Partial derivative with respect to y, denoted as \( \frac{\partial f}{\partial y} \).
  • Partial derivative with respect to z, denoted as \( \frac{\partial f}{\partial z} \).
In this problem, our surface function is \( f(x, y, z) = x^2 - xy - y^2 - z \). Calculating these, we find the gradient \( abla f = (2x - y, -x - 2y, -1) \). The gradient essentially points in the direction of the steepest ascent and is perpendicular to the contour line at the point we’re considering.
Normal Line
The normal line to a surface at a given point is a line that is perpendicular to the surface. In the context of a 3D surface, this line can be particularly useful as it provides a direction of maximum change from the surface. The normal vector we calculated from the gradient in this instance serves as the direction vector for our normal line.
To define a normal line using a parametric equation, we use the point \( P_0 = (1, 1, -1) \) and the gradient vector \( (1, -3, -1) \):
  • For x: \( x = 1 + t \)
  • For y: \( y = 1 - 3t \)
  • For z: \( z = -1 - t \)
The parameter \( t \) allows us to trace out the line across space as it passes through \( P_0 \) and extends in the direction determined by the normal vector.
Partial Derivatives
Partial derivatives are a foundational concept in multivariable calculus. They measure how a function changes as only one of the input variables changes, holding all others constant. To compute the partial derivatives of a surface function, differentiate the function with respect to one variable at a time.
For the surface function \( f(x, y, z) = x^2 - xy - y^2 - z \):
  • \( \frac{\partial f}{\partial x} = 2x - y \)
  • \( \frac{\partial f}{\partial y} = -x - 2y \)
  • \( \frac{\partial f}{\partial z} = -1 \)
These derivatives are essential for forming the gradient vector \( abla f \), which combines them into a single vector. This vector is used to find both the tangent plane and the normal line to the surface.
Surface Equation
The surface equation is a mathematical way to describe a shape or a surface in a multi-dimensional space. For this exercise, the surface of interest is defined by the implicit equation \( x^2 - xy - y^2 - z = 0 \). This equation helps to understand how the surface behaves in the three-dimensional space formed by the x, y, and z axes.
The equation itself represents a set of all points \((x, y, z)\) that satisfy this condition, forming a surface. At any point \( P_0 \) on this surface, characteristics like the tangent plane and the normal line can be derived using the gradient vector.
The tangent plane at a point is formed using the gradient vector at that point, resulting in the equation: \( 1(x - 1) - 3(y - 1) - 1(z + 1) = 0 \), simplified to \( x - 3y - z + 3 = 0 \). This equation gives us a flat plane that just barely touches the surface at \( P_0 \), representing the surface's best linear approximation there.

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