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In Exercises \(13-24\) , draw a tree diagram and write a Chain Rule formula for each derivative. $$ \begin{array}{l}{\frac{\partial w}{\partial x} \text { and } \frac{\partial w}{\partial y} \text { for } w=f(r, s, t), \quad r=g(x, y), \quad s=h(x, y)} \\\ {t=k(x, y)}\end{array} $$

Short Answer

Expert verified
Use the chain rule formulas: \( \frac{\partial w}{\partial x} = \frac{\partial f}{\partial r} \cdot \frac{\partial r}{\partial x} + \frac{\partial f}{\partial s} \cdot \frac{\partial s}{\partial x} + \frac{\partial f}{\partial t} \cdot \frac{\partial t}{\partial x} \) and \( \frac{\partial w}{\partial y} = \frac{\partial f}{\partial r} \cdot \frac{\partial r}{\partial y} + \frac{\partial f}{\partial s} \cdot \frac{\partial s}{\partial y} + \frac{\partial f}{\partial t} \cdot \frac{\partial t}{\partial y} \).

Step by step solution

01

Identify the Partial Derivatives Required

We are tasked with finding the partial derivatives \( \frac{\partial w}{\partial x} \) and \( \frac{\partial w}{\partial y} \). To do this, we need to use the chain rule to express these partial derivatives in terms of the partial derivatives of \( f \) with respect to \( r, s, \) and \( t \).
02

Draw the Tree Diagram

Create a tree diagram to represent the relationships between the functions:- The top node is \( w = f(r, s, t) \).- The middle nodes are \( r = g(x, y), s = h(x, y), \) and \( t = k(x, y) \).- The base nodes are \( x \) and \( y \).The diagram helps visualize how changes in \( x \) and \( y \) affect \( r, s, \) and \( t \), and ultimately \( w \).
03

Write the Chain Rule Formula for \( \frac{\partial w}{\partial x} \)

According to the chain rule for functions of multiple variables, the partial derivative \( \frac{\partial w}{\partial x} \) can be expressed as:\[\frac{\partial w}{\partial x} = \frac{\partial f}{\partial r} \cdot \frac{\partial r}{\partial x} + \frac{\partial f}{\partial s} \cdot \frac{\partial s}{\partial x} + \frac{\partial f}{\partial t} \cdot \frac{\partial t}{\partial x}\]
04

Write the Chain Rule Formula for \( \frac{\partial w}{\partial y} \)

Similarly, the partial derivative \( \frac{\partial w}{\partial y} \) is given by:\[\frac{\partial w}{\partial y} = \frac{\partial f}{\partial r} \cdot \frac{\partial r}{\partial y} + \frac{\partial f}{\partial s} \cdot \frac{\partial s}{\partial y} + \frac{\partial f}{\partial t} \cdot \frac{\partial t}{\partial y}\]
05

Verify the Chain Rule Formulas

Check that each part of the chain rule formula aligns with the tree diagram. Each path from \( x \) or \( y \) to \( w \) passes through \( r, s, \) or \( t \), ensuring all dependencies are accounted for in the derivatives.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Derivatives
Partial derivatives are a fundamental concept in calculus when dealing with functions of multiple variables. In simple terms, a partial derivative measures how a function changes as one of its input variables changes, while keeping the other input variables constant.
For example, if you have a function \( w = f(r, s, t) \), where each of \( r \), \( s \), and \( t \) are functions of \( x \) and \( y \), like \( r = g(x, y) \), \( s = h(x, y) \), and \( t = k(x, y) \), you can compute the partial derivatives of \( w \) with respect to \( x \) and \( y \).
This involves calculating \( \frac{\partial w}{\partial x} \) and \( \frac{\partial w}{\partial y} \). By applying the chain rule, you can figure out how a small change in either \( x \) or \( y \) will directly influence \( w \).

Partial derivatives are essential in many fields, such as physics, engineering, and economics, as they help understand how different factors contribute to a system's change.
Tree Diagram
A tree diagram is a visual tool that helps map out relationships between variables and functions, especially useful in multivariable calculus problems.
Consider a tree diagram for the exercise where the top node is \( w = f(r, s, t) \). Moving down the tree, the middle nodes represent \( r = g(x, y) \), \( s = h(x, y) \), and \( t = k(x, y) \), with base nodes \( x \) and \( y \).
  • Top Node: \( w = f(r, s, t) \)
  • Middle Nodes: \( r \), \( s \), \( t \)
  • Base Nodes: \( x \) and \( y \)
This structure clarifies how each input variable influences the function \( w \).

Using a tree diagram, you can clearly see the paths along which a change in an input variable stretches to impact \( w \). It's a great way to ensure you consider every necessary dependency when calculating partial derivatives using the chain rule.
Multivariable Calculus
Multivariable calculus extends single-variable calculus concepts to functions with multiple inputs. This branch of calculus focuses on understanding how variables interact and affect one another in a multi-dimensional space.

In the context of multivariable calculus, problems often involve functions like \( w = f(r, s, t) \), where \( r \), \( s \), and \( t \) themselves are dependent on more than one variable. The goal is to examine how slight variations in each variable influence the overall outcome or behavior of the function.
Key topics include:
  • Partial derivatives for analyzing individual variable impacts.
  • Chain rule for managing derivative relationships in composite functions.
  • Tree diagrams for visualizing variable dependencies.
In real-world scenarios, multi-variable calculus is invaluable for modeling dynamic systems such as weather patterns, financial markets, or engineering designs. It allows for the precise prediction and manipulation of complex systems by understanding each contributing factor's role.

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Most popular questions from this chapter

In Exercises \(51-56,\) find the limit of \(f\) as \((x, y) \rightarrow(0,0)\) or show that the limit does not exist. $$ f(x, y)=\frac{2 x}{x^{2}+x+y^{2}} $$

The Sandwich Theorem for functions of two variables states that if \(g(x, y) \leq f(x, y) \leq h(x, y)\) for all \((x, y) \neq\left(x_{0}, y_{0}\right)\) in a disk centered at \(\left(x_{0}, y_{0}\right)\) and if \(g\) and \(h\) have the same finite limit \(L\) as \((x, y) \rightarrow\left(x_{0}, y_{0}\right),\) then $$ \lim _{(x, y) \rightarrow\left(x_{0}, y_{0}\right)} f(x, y)=L $$ Use this result to support your answers to the questions in Exercises \(45-48 .\) Does knowing that $$ 1-\frac{x^{2} y^{2}}{3}<\frac{\tan ^{-1} x y}{x y}<1 $$ tell you anything about $$\lim _{(x, y) \rightarrow(0,0)} \frac{\tan ^{-1} x y}{x y} ?$$ Give reasons for your answer.

Can you conclude anything about \(f(a, b)\) if \(f\) and its first and second partial derivatives are continuous throughout a disk centered at \((a, b)\) and \(f_{x x}(a, b)\) and \(f_{y y}(a, b)\) differ in sign? Give reasons for your answer.

Estimating maximum error Suppose that \(u=x e^{y}+y \sin z\) and that \(x, y,\) and \(z\) can be measured with maximum possible errors of \(\pm 0.2, \pm 0.6\) , and \(\pm \pi / 180,\) respectively. Estimate the maximum possible error in calculating \(u\) from the measured values \(x=2, y=\ln 3, z=\pi / 2 .\)

Use a CAS to perform the following steps implementing the method of Lagrange multipliers for finding constrained extrema: a. Form the function \(h=f-\lambda_{1} g_{1}-\lambda_{2} g_{2},\) where \(f\) is the function to optimize subject to the constraints \(g_{1}=0\) and \(g_{2}=0 .\) b. Determine all the first partial derivatives of \(h\) , including the partials with respect to \(\lambda_{1}\) and \(\lambda_{2},\) and set them equal to \(0 .\) c. Solve the system of equations found in part (b) for all the unknowns, including \(\lambda_{1}\) and \(\lambda_{2} .\) d. Evaluate \(f\) at each of the solution points found in part (c) and select the extreme value subject to the constraints asked for in the exercise. Minimize \(f(x, y, z, w)=x^{2}+y^{2}+z^{2}+w^{2}\) subject to the constraints \(2 x-y+z-w-1=0\) and \(x+y-z+w-1=0\)

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