/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 Differentiable vector functions ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Differentiable vector functions are continuous Show that if \(\mathbf{r}(t)=f(t) \mathbf{i}+g(t) \mathbf{j}+h(t) \mathbf{k}\) is differentiable at \(t=t_{0},\) then it is continuous at \(t_{0}\) as well.

Short Answer

Expert verified
If a vector function is differentiable at a point, it is also continuous at that point.

Step by step solution

01

Understand Differentiability

A vector function \( \mathbf{r}(t) \) is differentiable at \( t = t_0 \) if its derivative exists at that point. The derivative is given by \( \frac{d\mathbf{r}}{dt} = \frac{df}{dt} \mathbf{i} + \frac{dg}{dt} \mathbf{j} + \frac{dh}{dt} \mathbf{k} \).
02

Analyze Component Functions

The vector function \( \mathbf{r}(t) = f(t) \mathbf{i} + g(t) \mathbf{j} + h(t) \mathbf{k} \) is composed of the scalar component functions \( f(t) \), \( g(t) \), and \( h(t) \) for \( \mathbf{i} \), \( \mathbf{j} \), and \( \mathbf{k} \), respectively. If \( \mathbf{r}(t) \) is differentiable at \( t_0 \), each of these functions must also be differentiable at \( t_0 \).
03

Relate Differentiability to Continuity

Remember that for a function to be differentiable at a point \( t_0 \), it must also be continuous at that point. Specifically, if \( f(t) \), \( g(t) \), and \( h(t) \) are differentiable at \( t_0 \), then they are also continuous at \( t_0 \).
04

Apply to Vector Function

Since each component function \( f(t) \), \( g(t) \), and \( h(t) \) of the vector function \( \mathbf{r}(t) \) is continuous at \( t_0 \), it follows that \( \mathbf{r}(t) \) itself is continuous at \( t_0 \).
05

Final Conclusion

We conclude that if a vector function \( \mathbf{r}(t) \) is differentiable at a point \( t_0 \), then it must also be continuous at that point due to the continuity of its individual component functions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Calculus
Vector calculus is an essential field in mathematics that deals with vector functions and the calculus operations you can perform on them. A vector function maps real numbers to vectors and is an extension of the familiar scalar-valued function from single-variable calculus.
\(\mathbf{r}(t)=f(t)\mathbf{i}+g(t)\mathbf{j}+h(t)\mathbf{k}\)represents a vector function with three component functions: \( f(t) \),\( g(t) \), and \( h(t) \). These components are scalar functions of \( t \), the real number input. Vectors have both direction and magnitude and are common in physical applications such as forces or velocities.
  • Operations on Vector Functions: Differentiation and integration are the primary operations, similar to single-variable calculus. You differentiate each component function individually.
  • Applications: Used in fields like physics and engineering to model phenomena such as electromagnetic fields and fluid flow.
A deep understanding of vector calculus aids in grasping complex systems and aiding the modeling of real-world applications.
Continuous Functions
A function is continuous if its graph is an unbroken path, with no gaps or jumps. In more formal mathematical terms, a function \( f \) is continuous at a point \( t_0 \) if the limit of \( f(t) \) as \( t \) approaches \( t_0 \) is equal to \( f(t_0) \).
In the context of vector functions:
  • Each component function \( f(t) \), \( g(t) \), and \( h(t) \) must be continuous for the vector function \( \mathbf{r}(t) \) to be continuous.
  • If all component functions are continuous at a point \( t_0 \), then the whole vector function is continuous at \( t_0 \).
Continuity is crucial because it ensures that there are no sudden jumps in the vector function's path, making it predictable and smooth over its domain. This property is particularly important in modeling realistic physical systems, where abrupt changes are often non-physical.
Differentiability and Continuity
Differentiability is a stronger condition than continuity for a function. If a function is differentiable at a point, then it is automatically continuous at that point, but not vice versa.
For a function to be differentiable at a point \( t_0 \), it means that its derivative exists at that point. This implies the function behaves in a linear way at that proximity, with no sharp turns.
  • Relationship: Being differentiable implies being continuous. If \( \mathbf{r}(t) \) is differentiable at \( t_0 \), then each component \( f(t) \), \( g(t) \), and \( h(t) \) is continuous at \( t_0 \).
  • Application in Vector Functions: Differentiability of vector functions implies a smooth change in direction and magnitude, important in physics to predict motion accurately.
Thus, differentiability assures the smoothness and predictability of the function's behavior right at the point of differentiation, connecting directly to the continuous nature of the function at that spot, gripping how changes accumulate over time without disruption.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Hitting a baseball under a wind gust A baseball is hit when it is 2.5 \(\mathrm{ft}\) above the ground. It leaves the bat with an initial velocity of 145 \(\mathrm{ft} / \mathrm{sec}\) at a launch angle of \(23^{\circ} .\) At the instant the ball is hit, an instantaneous gust of wind blows against the ball, adding a component of \(-14 \mathbf{i}(\mathrm{ft} / \mathrm{sec})\) to the ball's initial velocity. A 15 -ft-high fence lies 300 \(\mathrm{ft}\) from home plate in the direction of the flight. a. Find a vector equation for the path of the baseball. b. How high does the baseball go, and when does it reach maximum height? c. Find the range and flight time of the baseball, assuming that the ball is not caught. d. When is the baseball 20 \(\mathrm{ft}\) high? How far (ground distance) is the baseball from home plate at that height? e. Has the batter hit a home run? Explain.

Evaluate the integrals in Exercises \(21-26\) $$ \int_{1}^{2}\left[(6-6 t) \mathbf{i}+3 \sqrt{t} \mathbf{j}+\left(\frac{4}{t^{2}}\right) \mathbf{k}\right] d t $$

Show that a moving particle will move in a straight line if the normal component of its acceleration is zero.

Evaluate the integrals in Exercises \(21-26\) $$ \int_{0}^{1}\left[\frac{2}{\sqrt{1-t^{2}}} \mathbf{i}+\frac{\sqrt{3}}{1+t^{2}} \mathbf{k}\right] d t $$

In Exercises \(11-14\) , find the arc length parameter along the curve from the point where \(t=0\) by evaluating the integral $$ s=\int_{0}^{t}|\mathbf{v}(\tau)| d \tau $$ from Equation ( \(3 ) .\) Then find the length of the indicated portion of the curve. $$ \mathbf{r}(t)=(4 \cos t) \mathbf{i}+(4 \sin t) \mathbf{j}+3 t \mathbf{k}, \quad 0 \leq t \leq \pi / 2 $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.