Chapter 12: Problem 45
Sketch the surfaces in Exercises \(13-76\) $$ x^{2}+y^{2}+z^{2}=4 $$
Short Answer
Expert verified
The surface is a sphere centered at (0,0,0) with radius 2.
Step by step solution
01
Identify the Type of Surface
The given equation \(x^{2}+y^{2}+z^{2}=4\) is in the form \(x^2 + y^2 + z^2 = a^2\), which represents a sphere.
02
Determine the Center and Radius
Comparing the equation \(x^{2}+y^{2}+z^{2}=4\) with the standard form of a sphere \((x-h)^2 + (y-k)^2 + (z-l)^2 = r^2\), we identify that \(h = 0\), \(k = 0\), \(l = 0\) and \(r^2 = 4\). Thus, the sphere is centered at (0, 0, 0) with a radius of \(\sqrt{4} = 2\).
03
Sketch the Sphere
Since the sphere is centered at the origin (0,0,0) with a radius of 2, plot the sphere in three dimensions. Mark the points (2, 0, 0), (0, 2, 0), (0, 0, 2), (-2, 0, 0), (0, -2, 0), and (0, 0, -2) as these are intersections with the axes. Ensure the sketch represents a symmetric ball around the origin with surface all points equidistant (at 2 units) from the center.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sphere
A sphere is a perfectly round three-dimensional shape where every point on its surface is equidistant from its center. This distance is called the radius. In many ways, it resembles a ball or globe. Imagine a basketball or the planet Earth; these are physical representations of a sphere. Spheres are classified as one of the simplest types of shapes in three-dimensional geometry.
Spheres are unique because they have no faces, edges, or vertices, which distinguishes them from polygons or polyhedra. They are defined solely by their center and radius:
Spheres are unique because they have no faces, edges, or vertices, which distinguishes them from polygons or polyhedra. They are defined solely by their center and radius:
- The center of the sphere is a single point within the sphere.
- The radius extends from the center to any point on the surface.
Equation of a Sphere
The equation of a sphere in a three-dimensional Cartesian coordinate system is derived from the distance formula. It can be written in its standard form as:\[(x-h)^2 + (y-k)^2 + (z-l)^2 = r^2\]Here,
Let's consider the example from the exercise, \(x^2 + y^2 + z^2 = 4\), which is a special case where the center is the origin \((0, 0, 0)\) and the radius squared is \(4\). This equation signifies a sphere at the origin with all points on the surface 2 units away from the center.
- \( (h, k, l) \) is the center of the sphere.
- \( r \) is the radius.
Let's consider the example from the exercise, \(x^2 + y^2 + z^2 = 4\), which is a special case where the center is the origin \((0, 0, 0)\) and the radius squared is \(4\). This equation signifies a sphere at the origin with all points on the surface 2 units away from the center.
Radius and Center of a Sphere
Identifying the radius and center of a sphere from its equation is crucial for understanding and visualizing it in 3D space. For a sphere defined by the equation \((x-h)^2 + (y-k)^2 + (z-l)^2 = r^2\):
- The center is represented by the coordinates \((h, k, l)\).
- The radius is \( r \), which you find by taking the square root of the value on the right-hand side of the equation \((r^2)\).
- The center is \((0, 0, 0)\), since the terms do not include offsets \((h, k, l)\).
- The radius is \( \sqrt{4} \ = 2\).