/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 Sketch the surfaces in Exercises... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the surfaces in Exercises \(13-76\) $$ y=1-x^{2}-z^{2} $$

Short Answer

Expert verified
The surface is a downward-opening elliptic paraboloid with vertex at \((0,1,0)\). It intersects the \(xz\)-plane as circles centered at the origin.

Step by step solution

01

Recognizing the Equation Type

The given equation is \( y = 1 - x^2 - z^2 \). This is a quadratic equation in \(x\) and \(z\), which indicates it's a surface of a paraboloid.
02

Understanding the Surface

The equation \( y = 1 - x^2 - z^2 \) describes an elliptic paraboloid that opens downwards along the \(y\)-axis. The plane \(y = 1\) is its vertex. As \(x\) and \(z\) increase, \(y\) decreases because of the subtraction of \(x^2 + z^2\).
03

Sketching the Cross-Sections

First, consider cross-sections when \( y = k \), a constant. Rearrange as \( x^2 + z^2 = 1 - k \). These are circles when \( y < 1 \), centered at the origin in the \(xz\)-plane, with radius \( \sqrt{1-k} \) as long as \( \sqrt{1-k} \geq 0 \). The cross-section clearly vanishes for \( y > 1 \).
04

Analyzing the XZ-plane

In the \(xz\)-plane (where \(y=0\)), the trace becomes \( 0 = 1 - x^2 - z^2 \), which becomes \( x^2 + z^2 = 1 \), a circle centered at the origin with radius 1. This confirms the paraboloid shape when viewed along the \(y\)-axis.
05

Drawing the Surface

Begin your sketch by plotting the vertex at the point \((0, 1, 0)\). From this vertex, draw levels of decreasing circles in the \(xz\)-plane as \(y\) decreases from 1 to negative numbers. The shape resembles a bowl opening downwards, symmetric around the \(y\)-axis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Elliptic Paraboloid
An elliptic paraboloid is a three-dimensional surface that looks similar to a bowl or an upward-opening umbrella, but can open either upwards or downwards. In the equation form, an elliptic paraboloid has the general structure of \[ y = a - bx^2 - cz^2 \]where the coefficients determine its orientation and curvature. In this case, the equation is \[ y = 1 - x^2 - z^2 \]which describes an elliptic paraboloid opening downwards along the y-axis. The reason it's called elliptic is because its cross-sections parallel to the xz-plane form ellipses or circles, depending on the particular slice.

Key features of this surface include:
  • The vertex, which is the highest or lowest point on the paraboloid. For the given equation, the vertex is at \[(0, 1, 0)\].
  • An axis of symmetry, the y-axis in this case, along which all the cross-sections retain their patterned symmetry.
  • Opening direction, downwards here, meaning as we move away from the vertex, the value of y decreases.
Visualizing an elliptic paraboloid can greatly help in understanding its 3D nature and curvature.
Cross-Sections
Cross-sections of a surface refer to the shape you obtain when you "slice" through the surface at a certain height, typically a constant value of one of the coordinates. For the elliptic paraboloid defined by \[ y = 1 - x^2 - z^2 \], and focusing on constant y-values, the cross-section equation adapts to:\[ x^2 + z^2 = 1 - y \].This equation represents a circle centered at the origin with a radius \[ \sqrt{1-y} \] when \[ y < 1 \].

These circles provide insight into the surface's shape as it varies along the y-axis:
  • For \[ y = 0 \], we get the largest circle with radius 1.
  • For \[ y = 0.75 \], we get a smaller circle with radius \[ \sqrt{0.25} = 0.5 \].
  • Cross-sections disappear when \[ y > 1 \], as the equation \[ x^2 + z^2 = 1-y \] can no longer hold true.
This means that the cross-sections not only describe the shape of the paraboloid better, but actively demonstrate how its width changes vertically.
XZ-plane
The XZ-plane is a two-dimensional plane where the y-coordinate is set to zero, effectively reducing the complexity of observing 3D shapes by focusing on a "slice" through the origin in 3D space. For the given paraboloid, setting y to 0 in the equation \[ y = 1 - x^2 - z^2 \] leads us to the trace \[ x^2 + z^2 = 1 \], which is a circle centered at the origin with radius 1.

Looking at the XZ-plane gives a direct view of the paraboloid's horizontal profiles:
  • This circle identifies the maximum extent of the paraboloid on the plane y=0.
  • Because the circle is perfectly centered, it exposes the elliptic symmetry of the paraboloid without complication from vertical offsets.
  • Changes in the y-coordinate don't affect the location of the paraboloid along this plane, only its vertical extent.
By understanding the characteristics of the XZ-plane, students can appreciate the symmetry and form of the paraboloid in three dimensions, highlighting how simple cross-section shapes can roll up into complex surfaces.

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