Chapter 12: Problem 30
Sketch the surfaces in Exercises \(13-76\) $$ y=1-x^{2}-z^{2} $$
Short Answer
Expert verified
The surface is a downward-opening elliptic paraboloid with vertex at \((0,1,0)\). It intersects the \(xz\)-plane as circles centered at the origin.
Step by step solution
01
Recognizing the Equation Type
The given equation is \( y = 1 - x^2 - z^2 \). This is a quadratic equation in \(x\) and \(z\), which indicates it's a surface of a paraboloid.
02
Understanding the Surface
The equation \( y = 1 - x^2 - z^2 \) describes an elliptic paraboloid that opens downwards along the \(y\)-axis. The plane \(y = 1\) is its vertex. As \(x\) and \(z\) increase, \(y\) decreases because of the subtraction of \(x^2 + z^2\).
03
Sketching the Cross-Sections
First, consider cross-sections when \( y = k \), a constant. Rearrange as \( x^2 + z^2 = 1 - k \). These are circles when \( y < 1 \), centered at the origin in the \(xz\)-plane, with radius \( \sqrt{1-k} \) as long as \( \sqrt{1-k} \geq 0 \). The cross-section clearly vanishes for \( y > 1 \).
04
Analyzing the XZ-plane
In the \(xz\)-plane (where \(y=0\)), the trace becomes \( 0 = 1 - x^2 - z^2 \), which becomes \( x^2 + z^2 = 1 \), a circle centered at the origin with radius 1. This confirms the paraboloid shape when viewed along the \(y\)-axis.
05
Drawing the Surface
Begin your sketch by plotting the vertex at the point \((0, 1, 0)\). From this vertex, draw levels of decreasing circles in the \(xz\)-plane as \(y\) decreases from 1 to negative numbers. The shape resembles a bowl opening downwards, symmetric around the \(y\)-axis.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Elliptic Paraboloid
An elliptic paraboloid is a three-dimensional surface that looks similar to a bowl or an upward-opening umbrella, but can open either upwards or downwards. In the equation form, an elliptic paraboloid has the general structure of \[ y = a - bx^2 - cz^2 \]where the coefficients determine its orientation and curvature. In this case, the equation is \[ y = 1 - x^2 - z^2 \]which describes an elliptic paraboloid opening downwards along the y-axis. The reason it's called elliptic is because its cross-sections parallel to the xz-plane form ellipses or circles, depending on the particular slice.
Key features of this surface include:
Key features of this surface include:
- The vertex, which is the highest or lowest point on the paraboloid. For the given equation, the vertex is at \[(0, 1, 0)\].
- An axis of symmetry, the y-axis in this case, along which all the cross-sections retain their patterned symmetry.
- Opening direction, downwards here, meaning as we move away from the vertex, the value of y decreases.
Cross-Sections
Cross-sections of a surface refer to the shape you obtain when you "slice" through the surface at a certain height, typically a constant value of one of the coordinates. For the elliptic paraboloid defined by \[ y = 1 - x^2 - z^2 \], and focusing on constant y-values, the cross-section equation adapts to:\[ x^2 + z^2 = 1 - y \].This equation represents a circle centered at the origin with a radius \[ \sqrt{1-y} \] when \[ y < 1 \].
These circles provide insight into the surface's shape as it varies along the y-axis:
These circles provide insight into the surface's shape as it varies along the y-axis:
- For \[ y = 0 \], we get the largest circle with radius 1.
- For \[ y = 0.75 \], we get a smaller circle with radius \[ \sqrt{0.25} = 0.5 \].
- Cross-sections disappear when \[ y > 1 \], as the equation \[ x^2 + z^2 = 1-y \] can no longer hold true.
XZ-plane
The XZ-plane is a two-dimensional plane where the y-coordinate is set to zero, effectively reducing the complexity of observing 3D shapes by focusing on a "slice" through the origin in 3D space. For the given paraboloid, setting y to 0 in the equation \[ y = 1 - x^2 - z^2 \] leads us to the trace \[ x^2 + z^2 = 1 \], which is a circle centered at the origin with radius 1.
Looking at the XZ-plane gives a direct view of the paraboloid's horizontal profiles:
Looking at the XZ-plane gives a direct view of the paraboloid's horizontal profiles:
- This circle identifies the maximum extent of the paraboloid on the plane y=0.
- Because the circle is perfectly centered, it exposes the elliptic symmetry of the paraboloid without complication from vertical offsets.
- Changes in the y-coordinate don't affect the location of the paraboloid along this plane, only its vertical extent.