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Chapter 12: Problem 23

Diagonals of a rhombus Show that the diagonals of a rhombus (parallelogram with sides of equal length) are perpendicular.

Short Answer

Expert verified
The diagonals of a rhombus are perpendicular because they intersect at right angles.

Step by step solution

01

Understand Properties of a Rhombus

A rhombus is a type of parallelogram where all four sides are of equal length. Therefore, each side can be labeled as \(s\) for side.
02

Diagonals in Rhombus

The diagonals of a rhombus have special properties: they bisect each other at right angles (90 degrees) and each diagonal bisects the rhombus into two congruent triangles.
03

Define Diagonals

Let's label the diagonals as \(d_1\) and \(d_2\). The diagonals intersect at point \(O\), the center of the rhombus.
04

Use Vector Representation

Represent the sides of the rhombus using vectors. Let \( \vec{AC} \) and \( \vec{BD} \) be the diagonals, and \(OA = OC\), \(OB = OD\). This means \( \vec{OA} = \vec{OC} \) and \( \vec{OB} = \vec{OD} \).
05

Show Perpendicularity

For perpendicularity, the dot product of the diagonals must be zero. Calculate \( \vec{AC} \cdot \vec{BD} = 0 \) since their intersection results in two right triangles \((\angle AOB = 90^\circ)\).
06

Conclusion

Since the dot product results in 0, this confirms that the diagonals of a rhombus are perpendicular to each other. Therefore, they divide the rhombus into four right-angled triangles.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Diagonals of a Rhombus
A rhombus is a special type of parallelogram where all sides are of equal length, making it a unique shape with interesting properties. One of these properties is related to its diagonals. Unlike the diagonals of regular parallelograms, which are not necessarily equal or perpendicular, the diagonals of a rhombus are known to bisect each other at right angles. This means each diagonal divides the rhombus into two congruent triangles, highlighting its symmetry.
  • Each diagonal splits the rhombus into two equal (congruent) triangles.
  • The diagonals intersect at a single point, which acts as the center of symmetry.
  • The property of being perpendicular ensures that the angle formed where they intersect is 90 degrees.
These properties are critical in various geometric proofs and constructions, simplifying calculations and providing understanding into the intricate beauty of the rhombus's structure.
Vector Representation in Geometry
Vectors provide a powerful way to represent geometric shapes mathematically, and the rhombus is no exception. In a rhombus, vectors can represent both the sides and the diagonals, allowing a precise study of their characteristics. When we think of diagonals in terms of vectors, using them provides a clear understanding of direction and magnitude.
  • Vectors can describe the diagonals of a rhombus by calculating differences between vertex points.
  • This representation helps in visualizing how the diagonals bisect each other within a coordinate plane.
  • Using vectors keeps the analysis algebraic, allowing calculations such as the dot product to ascertain perpendicularity.
Understanding vectors in geometry extends to numerous applications, creating bridges between algebra and geometry. This way, complex geometric concepts become more manageable with the numeric language of vectors.
Dot Product and Perpendicularity
The dot product is a fundamental operation in vector algebra, providing insight into the relationship between two vectors. In the context of a rhombus, it helps confirm the perpendicularity of diagonals. For two vectors to be perpendicular, their dot product must equal zero.
  • When two vectors are perpendicular, they form a 90-degree angle, which is key for confirming properties in shapes like the rhombus.
  • The formula for the dot product of two vectors \(\vec{a}\) and \(\vec{b}\) is given by: \(\vec{a} \cdot \vec{b} = a_xb_x + a_yb_y\), where each vector has components \((a_x, a_y)\) and \((b_x, b_y)\).
  • For the diagonals of a rhombus, this translates to solving \(\vec{AC} \cdot \vec{BD} = 0\) to ensure they intersect perpendicularly.
Using the dot product is a neat mathematical trick that not only proves perpendicularity but also connects geometry with algebra, simplifying validation of geometric properties.

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Most popular questions from this chapter

Double cancellation If \(\mathbf{u} \neq \mathbf{0}\) and if \(\mathbf{u} \times \mathbf{v}=\mathbf{u} \times \mathbf{w}\) and \(\mathbf{u} \cdot \mathbf{v}=\mathbf{u} \cdot \mathbf{w},\) then does \(\mathbf{v}=\mathbf{w} ?\) Give reasons for your answer.

Let \(\mathbf{u}, \mathbf{v},\) and \(\mathbf{w}\) be vectors. Which of the following make sense, and which do not? Give reasons for your answers. $$ \begin{array}{ll}{\text { a. }(\mathbf{u} \times \mathbf{v}) \cdot \mathbf{w}} & {\text { b. } \mathbf{u} \times(\mathbf{v} \cdot \mathbf{w})} \\\ {\mathbf{c} . \mathbf{u} \times(\mathbf{v} \times \mathbf{w})} & {\text { d. } \mathbf{u} \cdot(\mathbf{v} \cdot \mathbf{w})}\end{array} $$

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