/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 62 Which of the sequences \(\left\\... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Which of the sequences \(\left\\{a_{n}\right\\}\) in Exercises \(23-84\) converge, and which diverge? Find the limit of each convergent sequence. $$ a_{n}=\frac{n !}{2^{n} \cdot 3^{n}} $$

Short Answer

Expert verified
The sequence \( a_n = \frac{n!}{6^n} \) diverges.

Step by step solution

01

Identify the Sequence Type

The sequence given is \( a_n = \frac{n!}{2^n \cdot 3^n} \). This is a numerical sequence involving factorials \( n! \) and exponential terms \( 2^n \cdot 3^n \). Understanding the growth behavior of these components individually will help in analyzing the sequence.
02

Examine Growth of Terms

Factorials grow very quickly compared to exponential terms. For \( n! \), the growth is roughly faster than \( n^n \). Both factorials and exponentials can be compared as \( n! \)'s growth tends to outpace \( (constant)^n \) for large values of \( n \). We need to compare these rates to determine convergence.
03

Simplify the Denominator

Rewrite the denominator: \( 2^n \cdot 3^n = 6^n \). This simplifies the sequence to \( a_n = \frac{n!}{6^n} \). Understanding this helps clarify how \( n! \) compares to \( 6^n \).
04

Employ the Ratio Test

The ratio test is useful to determine the convergence of sequences involving factorials and exponentials. Calculate the ratio of successive terms: \( \frac{a_{n+1}}{a_n} = \frac{(n+1)!}{6^{n+1}} \cdot \frac{6^n}{n!} = \frac{n+1}{6} \).
05

Analyze the Ratio

Evaluate \( \lim_{n \to \infty} \frac{n+1}{6} \). As \( n \) approaches infinity, this ratio approaches infinity as well, indicating that the terms grow without bound.
06

Conclude Divergence

Since the ratio approaches infinity and not a value less than 1, the sequence \( a_n = \frac{n!}{6^n} \) diverges by the ratio test.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factorials
Factorials are an important component found in sequence calculations, especially in determining their convergence or divergence. The factorial of a non-negative integer, denoted by \( n! \), is the product of all positive integers less than or equal to \( n \). For instance, \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \). Factorials exhibit rapid growth as \( n \) increases. This growth is generally faster than exponential growth for large \( n \).
  • Factorials are defined only for non-negative integers.
  • The growth of factorials can be visualized as an exponential function of \( n \), but its actual growth is much faster than common base exponential functions like \( 2^n \) or \( 3^n \).
  • Understanding the growth of factorials is crucial when they appear in the numerator of a sequence, as they significantly impact the sequence's convergence behavior.
To assess a sequence involving factorials and exponentials, compare how their growths relate, which is vital in later testing methods, such as the Ratio Test.
Ratio Test
The Ratio Test is a powerful method for determining the convergence or divergence of a sequence or series, especially those involving factorials or exponential growth. For the sequence \( a_n \), the Ratio Test involves evaluating the limit of the ratio of successive terms as \( n \) approaches infinity:
\[ L = \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| \]
  • If \( L < 1 \), the series converges.
  • If \( L > 1 \) or \( L = +\infty \), the series diverges.
  • If \( L = 1 \), the test is inconclusive.
In the given problem, the Ratio Test involves calculating \( \frac{a_{n+1}}{a_n} \) for \( a_n = \frac{n!}{6^n} \). The result \( L = \lim_{n \to \infty} \frac{n+1}{6} \) shows divergence as \( L \to +\infty \). This indicates the terms grow without bound, confirming that the sequence diverges.
Exponential Growth
Exponential growth describes processes that increase rapidly at a constant growth rate per unit time. It is commonly expressed as \( b^n \), where \( b > 1 \), representing continuous and constant percentage increases. For sequences, exponential growth signifies that each term increases by a multiple as \( n \) becomes large.
Exponential terms often compete with other rapidly growing functions like factorials in sequences and series. In the provided example, the denominator consists of \( 6^n \), an exponential growth factor because \( 2^n \cdot 3^n = 6^n \).
  • Exponential growth is slower than factorial growth for large \( n \) due to how factorial growth compounds multiplicatively over all preceding integers.
  • In expressions like \( \frac{n!}{b^n} \), observing how factorials and exponential terms compare helps determine if exponential growth can "keep up" or if its influence wanes as terms grow larger.
  • Sequences often diverge when exponential terms cannot balance out the rapid growth of other terms, like factorials, as shown in this problem.
Understanding the dynamics of exponential growth aids in comprehending why sequences involving a competition between factorials and exponentials can lead to divergence, as factorials overpower exponential terms in such cases.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Estimate the error if \(\cos t^{2}\) is approximated by \(1-\frac{t^{4}}{2}+\frac{t^{8}}{4 !}\) in the integral \(\int_{0}^{1} \cos t^{2} d t .\)

Which of the series converge, and which diverge? Give reasons for your answers. (When you check an answer, remember that there may be more than one way to determine the series’ convergence or divergence.) $$ \sum_{n=1}^{\infty} n \tan \frac{1}{n} $$

Estimating Pi About how many terms of the Taylor series for \(\tan ^{-1} x\) would you have to use to evaluate each term on the right-hand side of the equation $$ \pi=48 \tan ^{-1} \frac{1}{18}+32 \tan ^{-1} \frac{1}{57}-20 \tan ^{-1} \frac{1}{239} $$ with an error of magnitude less than \(10^{-6} ?\) In contrast, the convergence of \(\sum_{n=1}^{\infty}\left(1 / n^{2}\right)\) to \(\pi^{2} / 6\) is so slow that even 50 terms will not yield two-place accuracy.

Obtain the Taylor series for 1\(/(1+x)^{2}\) from the series for \(-1 /(1+x) .\)

Compound interest, deposits, and withdrawals If you invest an amount of money \(A_{0}\) at a fixed annual interest rate \(r\) compounded \(m\) times per year, and if the constant amount \(b\) is added to the account at the end of each compounding period (or taken from the account if \(b<0 ),\) then the amount you have after \(n+1\) compounding periods is $$ A_{n+1}=\left(1+\frac{r}{m}\right) A_{n}+b $$ a. If \(A_{0}=1000, r=0.02015, m=12,\) and \(b=50\) , calculate and plot the first 100 points \(\left(n, A_{n}\right) .\) How much money is in your account at the end of 5 years? Does \(\left\\{A_{n}\right\\}\) converge? Is \(\left\\{A_{n}\right\\}\) bounded? b. Repeat part (a) with \(A_{0}=5000, r=0.0589, m=12,\) and \(b=-50 .\) c. If you invest 5000 dollars in a certificate of deposit (CD) that pays 4.5\(\%\) annually, compounded quarterly, and you make no further investments in the CD, approximately how many years will it take before you have \(20,000\) dollars? What if the CD earns 6.25\(\% ?\) d. It can be shown that for any \(k \geq 0\) , the sequence defined recursively by Equation \((1)\) satisfies the relation $$ A_{k}=\left(1+\frac{r}{m}\right)^{k}\left(A_{0}+\frac{m b}{r}\right)-\frac{m b}{r} $$ For the values of the constants \(A_{0}, r, m,\) and \(b\) given in part (a), validate this assertion by comparing the values of the first 50 terms of both sequences. Then show by direct substitution that the terms in Equation \((2)\) satisfy the recursion formula in Equation ( 1\()\) .

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.