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Use series to evaluate the limits in Exercises \(47-56\) $$ \lim _{x \rightarrow \infty}(x+1) \sin \frac{1}{x+1} $$

Short Answer

Expert verified
The limit is 1.

Step by step solution

01

Identify the Series Expansion

To solve the limit using series, identify the series expansion of the function involved. Consider the Taylor series expansion of the sine function around 0: \( \sin x = x - \frac{x^3}{6} + \frac{x^5}{120} - \cdots \). For small values of \( x \), \( \sin x \approx x \).
02

Simplify the Expression

Here, \( x \to \infty \) means we consider \( \frac{1}{x+1} \to 0 \). Use the approximation \( \sin \left(\frac{1}{x+1}\right) \approx \frac{1}{x+1} \) for large \( x \). This simplifies the expression to \( (x+1) \cdot \frac{1}{x+1} = 1 \).
03

Evaluate the Limit

With the simplification \( \lim_{x \to \infty} (x+1) \sin \left( \frac{1}{x+1} \right) = \lim_{x \to \infty} 1 = 1 \), as all terms inside the limit simplify to 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Taylor Series
The Taylor series is a powerful mathematical tool used for approximating functions by series of polynomials. For many functions, it's possible to express them as an infinite sum of terms, calculated from the values of its derivatives at a single point. When we talk about a series expansion for functions like sine, cosine, or exponential functions, we use Taylor or its specific case, the Maclaurin series.

  • The basic formula for the Taylor series of a function \( f(x) \) about a point \( a \) is:
\[ f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \frac{f'''(a)}{3!}(x-a)^3 + \cdots \]However, when centered around 0, it is specifically called a Maclaurin series, where \( a = 0 \).

For the sine function, the Maclaurin series is:
  • \( \sin x = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \cdots \)

This provides a way to approximate the behavior of sine especially when \( x \) values are small.
Limit Evaluation
Evaluating limits often involves finding the output value a function approaches as the input approaches some value. This concept is foundational in calculus and is essential for understanding the behavior of functions at points where they aren't easily computed.

For example, calculating limits involving series expansions can simplify the process. In our problem, we use the property that, as \( x \to \infty \), any reciprocal \( \frac{1}{x+1} \) becomes infinitesimally small. Using Taylor series, this allows the sine function to be approximated by its linear term around 0, simplifying the complex trigonometric function into more basic arithmetic.

Approximating with series expansions for limit computations:
  • Converts complex expressions into simpler polynomial forms.
  • Allows for easier evaluation by reducing higher-order polynomial terms which diminish faster.
Infinite Limits
Infinite limits occur when the variables in a function approach infinity, leading the function to either increase or decrease without bound. They are important for understanding long-term behavior of functions.

In many practical applications, we use series expansion and limit evaluation to address infinite limits to manage the function's complexity as variables grow exceedingly large.
  • In our example, as \( x \to \infty \), the point \( \frac{1}{x+1} \to 0 \).
  • This means the sine function simplifies, making it easier to manage computationally.
  • The transformed product \((x+1) \sin \left( \frac{1}{x+1} \right) \to 1\) gives a limit result that is clean and intuitive.
Sine Function
The sine function \( \sin x \) is fundamental in trigonometry, essential for modeling waves, oscillations, and circular motion.

In calculus and mathematical analysis, the nature of sine becomes more manageable through series expansions. At a microlocal level, especially in its Taylor series form, \( \sin x \) can be roughly approximated by \( x \) when \( x \) is near 0, as seen in our problem example.
  • This approximation helps simplify complex expressions involving trigonometric functions.
  • Furthermore, using the first term of its Maclaurin series assists in dealing with limits and expressions that approach zero.
By understanding these properties and approximations, using the sine function in practical scenarios becomes less cumbersome and more intuitive.

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Most popular questions from this chapter

Find series solutions for the initial value problems in Exercises \(15-32\) . $$ y^{\prime \prime}+y=x, \quad y^{\prime}(0)=1 \text { and } y(0)=2 $$

Use series to evaluate the limits in Exercises \(47-56\) $$ \lim _{t \rightarrow 0} \frac{1-\cos t-\left(t^{2} / 2\right)}{t^{4}} $$

Show that if \(\Sigma_{n=1}^{\infty} a_{n}\) converges absolutely, then $$\left|\sum_{n=1}^{\infty} a_{n}\right| \leq \sum_{n=1}^{\infty}\left|a_{n}\right|$$

Which of the series converge, and which diverge? Give reasons for your answers. (When you check an answer, remember that there may be more than one way to determine the series’ convergence or divergence.) $$ \sum_{n=1}^{\infty} \operatorname{sech}^{2} n $$

Compound interest, deposits, and withdrawals If you invest an amount of money \(A_{0}\) at a fixed annual interest rate \(r\) compounded \(m\) times per year, and if the constant amount \(b\) is added to the account at the end of each compounding period (or taken from the account if \(b<0 ),\) then the amount you have after \(n+1\) compounding periods is $$ A_{n+1}=\left(1+\frac{r}{m}\right) A_{n}+b $$ a. If \(A_{0}=1000, r=0.02015, m=12,\) and \(b=50\) , calculate and plot the first 100 points \(\left(n, A_{n}\right) .\) How much money is in your account at the end of 5 years? Does \(\left\\{A_{n}\right\\}\) converge? Is \(\left\\{A_{n}\right\\}\) bounded? b. Repeat part (a) with \(A_{0}=5000, r=0.0589, m=12,\) and \(b=-50 .\) c. If you invest 5000 dollars in a certificate of deposit (CD) that pays 4.5\(\%\) annually, compounded quarterly, and you make no further investments in the CD, approximately how many years will it take before you have \(20,000\) dollars? What if the CD earns 6.25\(\% ?\) d. It can be shown that for any \(k \geq 0\) , the sequence defined recursively by Equation \((1)\) satisfies the relation $$ A_{k}=\left(1+\frac{r}{m}\right)^{k}\left(A_{0}+\frac{m b}{r}\right)-\frac{m b}{r} $$ For the values of the constants \(A_{0}, r, m,\) and \(b\) given in part (a), validate this assertion by comparing the values of the first 50 terms of both sequences. Then show by direct substitution that the terms in Equation \((2)\) satisfy the recursion formula in Equation ( 1\()\) .

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