/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 Which of the sequences \(\left\\... [FREE SOLUTION] | 91Ó°ÊÓ

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Which of the sequences \(\left\\{a_{n}\right\\}\) in Exercises \(23-84\) converge, and which diverge? Find the limit of each convergent sequence. $$ a_{n}=\sin \left(\frac{\pi}{2}+\frac{1}{n}\right) $$

Short Answer

Expert verified
The sequence converges to 1.

Step by step solution

01

Understand the Formula

The sequence given is \( a_{n} = \sin \left( \frac{\pi}{2} + \frac{1}{n} \right) \). We need to analyze how this sequence behaves as \( n \to \infty \).
02

Simplify the Formula for Convergence

Notice that as \( n \to \infty \), the term \( \frac{1}{n} \) approaches zero. Thus, \( \frac{\pi}{2} + \frac{1}{n} \to \frac{\pi}{2} \).
03

Evaluate the Sequence Limit

The sine function is continuous, so we can evaluate \( \lim_{n \to \infty} a_{n} = \lim_{n \to \infty} \sin \left( \frac{\pi}{2} + \frac{1}{n} \right) = \sin \left( \lim_{n \to \infty} \left( \frac{\pi}{2} + \frac{1}{n} \right) \right) = \sin \left( \frac{\pi}{2} \right) \).
04

Find the Convergent Limit

Using the result from the previous step, we find that \( \sin \left( \frac{\pi}{2} \right) = 1 \). Therefore, the sequence converges to 1.
05

Conclusion

Based on the derivation, the sequence \( a_{n} \) converges to the limit 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limit of a sequence
In mathematics, a sequence is a list of numbers written in a definite order. We say that a sequence converges to a limit if, as we proceed along the sequence, the numbers get infinitely close to a particular fixed number. For example, consider the sequence given by \( a_{n} = \sin \left( \frac{\pi}{2} + \frac{1}{n} \right) \). When \( n \to \infty \), the term \( \frac{1}{n} \) becomes very small, trending towards zero.

As a result, \( \frac{\pi}{2} + \frac{1}{n} \) approaches \( \frac{\pi}{2} \). The limit of the sequence then is evaluated by substituting this value into the given function. If the sequence is \( a_{n} \), then \( \lim_{n \to \infty} a_{n} = \sin \left( \lim_{n \to \infty} \left( \frac{\pi}{2} + \frac{1}{n} \right) \right) = \sin \left( \frac{\pi}{2} \right) \). Since \( \sin \left( \frac{\pi}{2} \right) = 1 \), the limit of this sequence is 1.

Thus, the sequence converges to 1. This means that as we increase \( n \), the value of \( a_{n} \) comes increasingly closer to 1 without ever changing after reaching it.
Sin function behavior
The sine function is an essential trigonometric function with periodic behavior. It oscillates between -1 and 1 as its input varies. The formula for sine is \( \sin(x) \), and it is periodic with a cycle of \( 2\pi \). This means every time you add \( 2\pi \) to the angle, the function repeats its values.

In the context of this sequence, we are interested in small changes around \( \frac{\pi}{2} \). Remember that \( \sin \) is maximized when its argument is \( \frac{\pi}{2} + k(2\pi) \), where \( k \) is an integer, resulting in the maximum value of 1.

The addition of \( \frac{1}{n} \) to \( \frac{\pi}{2} \) introduces a very tiny shift towards \( \frac{\pi}{2} \), given that \( \frac{1}{n} \) becomes negligible for very large \( n \). Hence, the sine function gradually approaches 1 as \( n \to \infty \). This is why the sequence \( \sin \left( \frac{\pi}{2} + \frac{1}{n} \right) \) converges to the value 1.
Continuity of trigonometric functions
Continuity is a fundamental property of functions. A function is continuous if small changes in the input result in small changes in the output. For trigonometric functions like sine and cosine, continuity holds true across their entire domain. This means there are no abrupt jumps or gaps in their graphs.

In the scenario of evaluating the sequence \( a_{n} = \sin \left( \frac{\pi}{2} + \frac{1}{n} \right) \), continuity of the sine function allows us to directly apply limits.

Specifically, because \( \lim_{n \to \infty} \left( \frac{\pi}{2} + \frac{1}{n} \right) = \frac{\pi}{2} \), the continuity of the sine function supports that \( \lim_{n \to \infty} \sin \left( \frac{\pi}{2} + \frac{1}{n} \right) = \sin \left( \lim_{n \to \infty} \left( \frac{\pi}{2} + \frac{1}{n} \right) \right) \).

With no sudden changes at \( \frac{\pi}{2} \), this result equals \( \sin \left( \frac{\pi}{2} \right) \), which is clearly 1. Thus, continuity is a key aspect that allows the calculation of limits in sequences involving trigonometric functions like our example above.

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Most popular questions from this chapter

Use a CAS to perform the following steps for the sequences in Exercises \(129-140 .\) a. Calculate and then plot the first 25 terms of the sequence. Does the sequence appear to be bounded from above or below? Does it appear to converge or diverge? If it does converge, what is the limit \(L ?\) b. If the sequence converges, find an integer \(N\) such that \(\left|a_{n}-L\right| \leq 0.01\) for \(n \geq N .\) How far in the sequence do you have to get for the terms to lie within 0.0001 of \(L ?\) $$ a_{n}=\frac{n^{41}}{19^{n}} $$

Logistic difference equation The recursive relation $$ a_{n+1}=r a_{n}\left(1-a_{n}\right) $$ is called the logistic difference equation, and when the initial value \(a_{0}\) is given the equation defines the logistic sequence \(\left\\{a_{n}\right\\} .\) Throughout this exercise we choose \(a_{0}\) in the interval \(03.57\) . Choose \(r=3.65\) and calculate and plot the first 300 terms of \(\left\\{a_{n}\right\\} .\) Observe how the terms wander around in an unpredictable, chaotic fashion. You cannot predict the value of \(a_{n+1}\) from previous values of the sequence. g. For \(r=3.65\) choose two starting values of \(a_{0}\) that are close together, say, \(a_{0}=0.3\) and \(a_{0}=0.301 .\) Calculate and plot the first 300 values of the sequences determined by each starting value. Compare the behaviors observed in your plots. How far out do you go before the corresponding terms of your two sequences appear to depart from each other? Repeat the exploration for \(r=3.75 .\) Can you see how the plots look different depending on your choice of \(a_{0} ?\) We say that the logistic sequence is sensitive to the initial condition a_{0} .

Find series solutions for the initial value problems in Exercises \(15-32\) . $$ y^{\prime \prime}+y=0, \quad y^{\prime}(0)=0 \text { and } y(0)=1 $$

In Exercises \(45-48\) , estimate the magnitude of the error involved in using the sum of the first four terms to approximate the sum of the entire series. $$ \frac{1}{1+t}=\sum_{n=0}^{\infty}(-1)^{n} t^{n}, \quad 0 < t < 1 $$

Outline of the proof of the Rearrangement Theorem a. Let \(\epsilon\) be a positive real number, let \(L=\sum_{n=1}^{\infty} a_{n}\), and let \(s_{k}=\sum_{n=1}^{k} a_{n} .\) Show that for some index \(N_{1}\) and for some index \(N_{2} \geq N_{1}\), $$ \sum_{n=N_{1}}^{\infty}\left|a_{n}\right|<\frac{\epsilon}{2} \text { and }\left|s_{N_{2}}-L\right|<\frac{\epsilon}{2} $$ Since all the terms \(a_{1}, a_{2}, \ldots, a_{N_{2}}\) appear somewhere in the sequence \(\left\\{b_{n}\right\\}\), there is an index \(N_{3} \geq N_{2}\) such that if \(n \geq N_{3}\), then \(\left(\sum_{k=1}^{n} b_{k}\right)-s_{N_{2}}\) is at most a sum of terms \(a_{m}\) with \(m \geq N_{1}\). Therefore, if \(n \geq N_{3}\), $$ \begin{aligned} \left|\sum_{k=1}^{n} b_{k}-L\right| & \leq\left|\sum_{k=1}^{n} b_{k}-s_{N_{2}}\right|+\left|s_{N_{2}}-L\right| \\ & \leq \sum_{k=N_{1}}^{\infty}\left|a_{k}\right|+\left|s_{N_{2}}-L\right|<\epsilon \end{aligned} $$ b. The argument in part (a) shows that if \(\sum_{n=1}^{\infty} a_{n}\) converges absolutely then \(\sum_{n=1}^{\infty} b_{n}\) converges and \(\sum_{n=1}^{\infty} b_{n}=\sum_{n=1}^{\infty} a_{n}\) Now show that because \(\sum_{n=1}^{\infty}\left|a_{n}\right|\) converges, \(\sum_{n=1}^{\infty}\left|b_{n}\right|\) converges to \(\sum_{n=1}^{\infty}\left|a_{n}\right|\).

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