Chapter 11: Problem 38
If \(\sum_{n=1}^{\infty} a_{n}\) is a convergent series of nonnegative numbers, can anything be said about \(\sum_{n=1}^{\infty}\left(a_{n} / n\right) ?\) Explain.
Short Answer
Expert verified
\(\sum \frac{a_n}{n}\) converges due to the decreasing impact of \(\frac{1}{n}\).
Step by step solution
01
Understanding Convergence of Series
A series \(\sum_{n=1}^{\infty} a_n\) is convergent if its sequence of partial sums \(S_n = a_1 + a_2 + \ldots + a_n\) approaches a finite limit as \(n\) approaches infinity. Since this series is given to be convergent with \(a_n \geq 0\), the sum \(\sum_{n=1}^{\infty} a_{n}\) must be finite.
02
Analyzing Series with Additional Division
The series \(\sum_{n=1}^{\infty} \frac{a_{n}}{n}\) involves each term \(a_n\) being divided by \(n\). This division generally makes each term smaller especially as \(n\) gets larger. The sequence \(b_n = \frac{a_n}{n}\) tends to become less than \(a_n\), as \(n\) increases.
03
Comparison with P-series
The series \(\sum_{n=1}^{\infty} \frac{1}{n^{p}}\) is known as a \(p\)-series and converges when \(p > 1\). In our case, \(\sum_{n=1}^{\infty} \frac{a_{n}}{n}\) can be thought of as a series similar to \(\sum_{n=1}^{\infty} \frac{1}{n}\), which diverges (this is the harmonic series). However, here we also have \(a_n\) terms which are non-negative and sum to a finite number.
04
Applying the Cauchy Condensation Test
The Cauchy Condensation Test can be applied to series of the form \(\sum \frac{a_n}{n}\). It simplifies examining the convergence of such a series to comparing with \(\sum 2^n \cdot \frac{a_{2^n}}{2^n}\). Since \(\sum a_n\) is finite, generally, dividing by \(n\) could produce a convergent series \(\sum \frac{a_n}{n}\).
05
Conclusion on Convergence
Generally, if \(\sum a_n\) is convergent and \(a_n \geq 0\), then \(\sum \frac{a_n}{n}\) converges by either direct comparison or applying condensation and recognizing the damping effect of \(\frac{1}{n}\) as \(n\to\infty\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cauchy Condensation Test
The Cauchy Condensation Test is a powerful tool in determining the convergence or divergence of infinite series. It holds particularly for series of the form \(\sum a_n\) where \(a_n\) are non-negative terms. Here's how it works:
- Transform the series \(\sum a_n\) into a new series \(\sum 2^n a_{2^n}\).
- The original series \(\sum a_n\) converges if and only if the condensed series \(\sum 2^n a_{2^n}\) converges.
p-series
A \(p\)-series is expressed as \(\sum_{n=1}^{\infty} \frac{1}{n^p}\). Understanding \(p\)-series helps us quickly recognize whether a given series will converge, based on the value of \(p\):
- The series converges if \(p > 1\).
- It diverges if \(0 < p \leq 1\).
partial sums
Partial sums play a crucial role in understanding the convergence of series. When you have a series, such as \(\sum_{n=1}^{\infty} a_n\), the partial sums are the sequences \(S_n = a_1 + a_2 + \ldots + a_n\). These are utilized for:
- Checking convergence: If partial sums of a series approach a finite limit as \(n\) grows, the series converges.
- Establishing series bounds: The behavior of \(S_n\) provides insights into the "weight" each subsequent term contributes to the series.