Chapter 11: Problem 33
The Taylor polynomial of order 2 generated by a twice-differentiable function \(f(x)\) at \(x=a\) is called the quadratic approximation of \(f\) at \(x=a .\) In Exercises \(33-38\) , find the (a) linearization (Taylor polynomial of order 1 ) and (b) quadratic approximation of \(f\) at \(x=0\) . $$ f(x)=\ln (\cos x) $$
Short Answer
Step by step solution
Find the first derivative
Evaluate the first derivative at a=0
Construct the linearization
Find the second derivative
Evaluate the second derivative at a=0
Construct the quadratic approximation
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Approximation
The formula for a quadratic approximation is:
- \( Q(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2}(x-a)^2 \)
Remember, the more derivatives we use, the more accurately our approximation mirrors the function.
Linearization
The formula for linearization is:
- \( L(x) = f(a) + f'(a)(x-a) \)
Linearization is particularly valuable for preliminary calculations and provides a good "first glance" estimate of function behavior within an interval.
Chain Rule
For a function \( f(g(x)) \), the derivative using the Chain Rule is computed as:
- \( \frac{d}{dx}f(g(x)) = f'(g(x)) \cdot g'(x) \)
Understanding the Chain Rule is crucial for dealing with complex, multi-layered functions.
Differentiability
In simple terms, if a function is smooth without breaks, sharp turns, or cusps at a point, it's differentiable. For twice-differentiable functions, like the one we worked with, you can calculate not only the first but also the second derivative.
This continuous nature allowed us to find both \( f'(x) = -\tan(x) \) and \( f''(x) = -\sec^2(x) \) for \( f(x) = \ln(\cos x) \).
- The first derivative gives the linear behavior.
- The second derivative provides insight into the function's curvature.