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Converge, and which diverge? Give reasons for your answers. If a series converges, find its sum. $$ \sum_{n=0}^{\infty} \frac{\cos n \pi}{5^{n}} $$

Short Answer

Expert verified
The series converges with a sum of \(\frac{5}{6}\).

Step by step solution

01

Determine Type of Series

First, observe that the given series is of the form \( \sum_{n=0}^{\infty} a_n \), where \( a_n = \frac{\cos(n\pi)}{5^n} \). Notice that \( \cos(n\pi) \) alternates between 1 and -1 for integer \( n \). Therefore, this is an alternating geometric series.
02

Identify the Common Ratio

For a geometric series, the common ratio \( r \) is the factor by which each term is multiplied to obtain the next term. Here, the terms are of the form \( a_n = (-1)^n \cdot \frac{1}{5^n} \). Thus, the common ratio is \( r = -\frac{1}{5} \).
03

Determine Convergence of the Series

A geometric series \( \sum_{n=0}^{\infty} ar^n \) converges if the absolute value of the common ratio \(|r| < 1\). In this series, \( |-\frac{1}{5}| = \frac{1}{5} < 1 \), so the series converges.
04

Calculate the Sum of the Series

The sum \( S \) of an infinite geometric series \( \sum_{n=0}^{\infty} ar^n \) is given by \( S = \frac{a}{1-r} \), where \( a \) is the first term of the series. Here, \( a = 1 \) (since \( \cos(0\pi) = 1 \) and \( \frac{1}{5^0} = 1 \)) and \( r = -\frac{1}{5} \). Therefore, \( S = \frac{1}{1 - (-\frac{1}{5})} = \frac{1}{1 + \frac{1}{5}} = \frac{1}{\frac{6}{5}} = \frac{5}{6} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Geometric Series
A geometric series is a special type of series where each term is multiplied by a constant factor to get to the next term. This constant factor is known as the 'common ratio'. For a series to be geometric, it must have terms of the form \( ar^n \), where \( a \) is the first term and \( r \) is the common ratio.

Key characteristics of a geometric series include:
  • The ratio between any two consecutive terms is constant.
  • The terms themselves are exponential with respect to the position \( n \).
  • The series can be either convergent or divergent, depending on the value of \( r \).
In the context of the given series \( \sum_{n=0}^{\infty} (-1)^n \cdot \frac{1}{5^n} \), it is a geometric series with a first term \( a = 1 \) and a common ratio \( r = -\frac{1}{5} \).

Understanding what makes a series geometric is crucial when analyzing whether it will converge or diverge, and what its sum might be if it converges.
Alternating Series
An alternating series is one where the terms flip in sign. This alternation typically happens because of a factor such as \((-1)^n\) in the terms of the series. Alternating series often oscillate between positive and negative values.

In the given series, \( \sum_{n=0}^{\infty} (-1)^n \cdot \frac{1}{5^n} \), the \((-1)^n\) part causes this alternation in sign. Alternating series have unique properties and require specific criteria to determine convergence.
  • A major point in these series is that the absolute values of the terms usually decrease steadily.
  • The alternating series test states that if the absolute value of the terms is steadily decreasing and has a limit of zero, then the alternating series converges.
This unique behavior of alternating series can affect the overall study of convergence and sums, as we see in this series where the geometric component and alternating nature both play roles in determining the sum.
Sum of Infinite Series
Finding the sum of an infinite series is an intriguing concept. While it might seem counterintuitive, some infinite series can be summed to a finite value. This happens particularly with convergent geometric series.

The formula to calculate the sum of an infinite geometric series \( \sum_{n=0}^{\infty} ar^n \) is \( S = \frac{a}{1-r} \), provided that \( |r| < 1 \). In the exercise, the series converges because the absolute value of the common ratio \( r = -\frac{1}{5} \) is less than 1, leading to a finite sum.
  • The first term \( a = 1 \) since \( \cos(0\pi) = 1 \) and \( 5^0 = 1 \).
  • Thus, using the formula, the sum is found to be \( \frac{5}{6} \).
Understanding this formula and concept is crucial for recognizing which sequences of numbers can be summed to a finite value despite having infinitely many terms.
Series Convergence Criteria
Determining convergence in a series is essential. Not all series converge; some go infinitely without approaching a particular value. Convergence criteria help us discern which series behave in which way.

For a geometric series to converge, the crucial factor is the common ratio \( r \). Specifically, the series converges if the absolute value of \( r \) is less than 1, i.e., \( |r| < 1 \). This ensures the terms gradually decrease to zero, making the infinite sum finite.
  • In alternating series, an additional look is needed at the sign change factor and the decreasing nature of terms.
  • If the series has qualities like a steadily decreasing absolute size of terms and the series alternates in sign, this also supports convergence.
Seeing how these factors interplay allows for better understanding and determination of whether a series will actually "settle" into a finite sum. This analytical process is central to working with both geometric and alternating series safely and accurately.

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Most popular questions from this chapter

Limits and subsequences If the terms of one sequence appear in another sequence in their given order, we call the first sequence a subsequence of the second. Prove that if two sub-sequences of a sequence \(\left\\{a_{n}\right\\}\) have different limits \(L_{1} \neq L_{2}\) then \(\left\\{a_{n}\right\\}\) diverges.

Prove that \(\lim _{n \rightarrow \infty} \sqrt[n]{n}=1\).

Prove that if \(\left\\{a_{n}\right\\}\) is a convergent sequence, then to every positive number \(\epsilon\) there corresponds an integer \(N\) such that for all \(m\) and \(n\) , $$ m>N \text { and } n>N \Rightarrow\left|a_{m}-a_{n}\right|<\epsilon $$

Compound interest, deposits, and withdrawals If you invest an amount of money \(A_{0}\) at a fixed annual interest rate \(r\) compounded \(m\) times per year, and if the constant amount \(b\) is added to the account at the end of each compounding period (or taken from the account if \(b<0 ),\) then the amount you have after \(n+1\) compounding periods is $$ A_{n+1}=\left(1+\frac{r}{m}\right) A_{n}+b $$ a. If \(A_{0}=1000, r=0.02015, m=12,\) and \(b=50\) , calculate and plot the first 100 points \(\left(n, A_{n}\right) .\) How much money is in your account at the end of 5 years? Does \(\left\\{A_{n}\right\\}\) converge? Is \(\left\\{A_{n}\right\\}\) bounded? b. Repeat part (a) with \(A_{0}=5000, r=0.0589, m=12,\) and \(b=-50 .\) c. If you invest 5000 dollars in a certificate of deposit (CD) that pays 4.5\(\%\) annually, compounded quarterly, and you make no further investments in the CD, approximately how many years will it take before you have \(20,000\) dollars? What if the CD earns 6.25\(\% ?\) d. It can be shown that for any \(k \geq 0\) , the sequence defined recursively by Equation \((1)\) satisfies the relation $$ A_{k}=\left(1+\frac{r}{m}\right)^{k}\left(A_{0}+\frac{m b}{r}\right)-\frac{m b}{r} $$ For the values of the constants \(A_{0}, r, m,\) and \(b\) given in part (a), validate this assertion by comparing the values of the first 50 terms of both sequences. Then show by direct substitution that the terms in Equation \((2)\) satisfy the recursion formula in Equation ( 1\()\) .

For what values of \(a,\) if any, do the series in converge? $$\sum_{n=3}^{\infty}\left(\frac{1}{n-1}-\frac{2 a}{n+1}\right)$$

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