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Which of the series in Exercises 1–36 converge, and which diverge? Give reasons for your answers. $$ \sum_{n=1}^{\infty} \tan \frac{1}{n} $$

Short Answer

Expert verified
The series \( \sum_{n=1}^{\infty} \tan \left(\frac{1}{n}\right) \) diverges.

Step by step solution

01

Understand the problem

We need to determine whether the infinite series \( \sum_{n=1}^{\infty} \tan \left(\frac{1}{n}\right) \) converges or diverges. The series involves the tangent function evaluated at terms \( \frac{1}{n} \), where \( n \) is a positive integer.
02

Consider behavior of the terms

For large \( n \), the term \( \frac{1}{n} \) becomes small. As \( x \to 0, \tan x \approx x \), thus \( \tan \left(\frac{1}{n}\right) \approx \frac{1}{n} \). This approximation helps us understand the behavior of the terms as \( n \) grows.
03

Compare with a known series

Comparing with the harmonic series \( \sum_{n=1}^{\infty} \frac{1}{n} \), which is known to diverge, we see that the terms \( \tan \left(\frac{1}{n}\right) \approx \frac{1}{n} \) for large \( n \), suggesting similar behavior.
04

Apply Limit Comparison Test

Use the limit comparison test, which involves comparing the series \( \sum a_n \) and \( \sum b_n \) by computing \( \lim_{n \to \infty} \frac{a_n}{b_n} \). Here, set \( a_n = \tan \left(\frac{1}{n}\right) \) and \( b_n = \frac{1}{n} \).Calculate:\[ \lim_{n \to \infty} \frac{\tan \left(\frac{1}{n}\right)}{\frac{1}{n}} = \lim_{n \to \infty} \frac{n \cdot \tan \left(\frac{1}{n}\right)}{1} = 1 \]This non-zero finite limit means the series \( \sum \tan \left(\frac{1}{n}\right) \) will behave like the series \( \sum \frac{1}{n} \), which diverges.
05

Conclusion on convergence or divergence

Since the limit comparison test with the harmonic series shows that they both have the same divergence behavior, we conclude that \( \sum_{n=1}^{\infty} \tan \left(\frac{1}{n}\right) \) diverges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limit Comparison Test
The Limit Comparison Test is a nifty tool for determining the convergence or divergence of an infinite series.
It involves comparing a series you are interested in, say \( \sum a_n \), with another known series, \( \sum b_n \). Here's how it works:
  • Calculate \( \lim_{n \to \infty} \frac{a_n}{b_n} \).
  • If this limit is a positive finite number, then both series \( \sum a_n \) and \( \sum b_n \) either converge together, or diverge together.
This test is particularly useful when the terms of your series complicated or when they approximate the terms of a simpler known series. In the given exercise, it immediately shows us whether the series behaves like the harmonic series, which is a known diverging series.
Harmonic Series
The Harmonic Series is a classic example in the study of convergence. It is given by:\[ \sum_{n=1}^{\infty} \frac{1}{n} \].Though the terms \( \frac{1}{n} \) get smaller as \( n \) grows, they do not decrease fast enough for the series to converge.
In fact, the Harmonic Series diverges.
The divergence of this series can often be proven using the integral test or the limit comparison test. Because of its straightforward terms, the harmonic series is frequently used as a benchmark for other series in comparison tests. If the terms of a complex series can be shown to grow like the harmonic series, then we can easily determine the convergence behavior by observing the harmonic series.
Tangent Function
The Tangent Function is a familiar concept from trigonometry, often written as \( \tan(x) \). It relates to sine and cosine:\[ \tan(x) = \frac{\sin(x)}{\cos(x)} \]. For very small values of \( x \), the function behaves approximately like \( x \) itself, which is crucial for series involving tangent.
As in the exercise, for small inputs such as \( \frac{1}{n} \), we use the approximation:\[ \tan\left(\frac{1}{n}\right) \approx \frac{1}{n} \],which simplifies the problem significantly by allowing us to compare it to the harmonic series. This approximation is the key reason why the Limit Comparison Test can be applied, indicating that the given tangent series diverges.
Infinite Series
An Infinite Series is essentially the sum of infinitely many numbers listed in a sequence.
Formally, for a series \( \sum_{n=1}^{\infty} a_n \), this means trying to find out whether adding an infinite number of terms gives you a finite result or not.
  • If as you add more and more terms the sum gets closer and closer to a specific number, the series is said to converge.
  • If the sum keeps growing or fluctuates without settling on a number, the series diverges.
Understanding whether a series converges or diverges is integral to many areas of mathematics and its applications. Techniques like the Limit Comparison Test help us make these determinations, as with the series involving \( \tan \left( \frac{1}{n} \right) \), which was shown to diverge like the harmonic series it was compared against.

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Most popular questions from this chapter

Compound interest, deposits, and withdrawals If you invest an amount of money \(A_{0}\) at a fixed annual interest rate \(r\) compounded \(m\) times per year, and if the constant amount \(b\) is added to the account at the end of each compounding period (or taken from the account if \(b<0 ),\) then the amount you have after \(n+1\) compounding periods is $$ A_{n+1}=\left(1+\frac{r}{m}\right) A_{n}+b $$ a. If \(A_{0}=1000, r=0.02015, m=12,\) and \(b=50\) , calculate and plot the first 100 points \(\left(n, A_{n}\right) .\) How much money is in your account at the end of 5 years? Does \(\left\\{A_{n}\right\\}\) converge? Is \(\left\\{A_{n}\right\\}\) bounded? b. Repeat part (a) with \(A_{0}=5000, r=0.0589, m=12,\) and \(b=-50 .\) c. If you invest 5000 dollars in a certificate of deposit (CD) that pays 4.5\(\%\) annually, compounded quarterly, and you make no further investments in the CD, approximately how many years will it take before you have \(20,000\) dollars? What if the CD earns 6.25\(\% ?\) d. It can be shown that for any \(k \geq 0\) , the sequence defined recursively by Equation \((1)\) satisfies the relation $$ A_{k}=\left(1+\frac{r}{m}\right)^{k}\left(A_{0}+\frac{m b}{r}\right)-\frac{m b}{r} $$ For the values of the constants \(A_{0}, r, m,\) and \(b\) given in part (a), validate this assertion by comparing the values of the first 50 terms of both sequences. Then show by direct substitution that the terms in Equation \((2)\) satisfy the recursion formula in Equation ( 1\()\) .

Use series to evaluate the limits in Exercises \(47-56\) $$ \lim _{y \rightarrow 0} \frac{\tan ^{-1} y-\sin y}{y^{3} \cos y} $$

According to a front-page article in the December \(15,1992,\) issue of the Wall Street Journal, Ford Motor Company used about 7\(\frac{1}{4}\) hours of labor to produce stampings for the average vehicle, down from an estimated 15 hours in \(1980 .\) The Japanese needed only about 3\(\frac{1}{2}\) hours. Ford's improvement since 1980 represents an average decrease of 6\(\%\) per year. If that rate continues, then \(n\) years from 1992 Ford will use about $$ S_{n}=7.25(0.94)^{n} $$ hours of labor to produce stampings for the average vehicle. Assuming that the Japanese continue to spend 3\(\frac{1}{2}\) hours per vehicle, how many more years will it take Ford to catch up? Find out two ways: a. Find the first term of the sequence \(\left\\{S_{n}\right\\}\) that is less than or equal to \(3.5 .\) b. Graph \(f(x)=7.25(0.94)^{x}\) and use Trace to find where the graph crosses the line \(y=3.5 .\)

In Exercises \(33-36\) , use series to estimate the integrals' values with an error of magnitude less than \(10^{-3} .\) (The answer section gives the integrals' values rounded to five decimal places.) $$ \int_{0}^{0.1} \frac{1}{\sqrt{1+x^{4}}} d x $$

Obtain the Taylor series for 1\(/(1+x)^{2}\) from the series for \(-1 /(1+x) .\)

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