Chapter 11: Problem 22
In Exercises \(21-28\) , find the Taylor series generated by \(f\) at \(x=a\) $$ f(x)=2 x^{3}+x^{2}+3 x-8, \quad a=1 $$
Short Answer
Expert verified
The Taylor series is \( -2 + 11(x-1) + 7(x-1)^2 + 2(x-1)^3 \).
Step by step solution
01
Write down the formula for the Taylor series
The Taylor series for a function \( f(x) \) centered at \( x = a \) is given by \( \sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!} (x-a)^n \). We will use this formula to find the Taylor series for \( f(x) \) around \( x = a = 1 \).
02
Evaluate the function \( f(x) \) at \( x = a \)
Substitute \( x = 1 \) into the function: \[ f(1) = 2(1)^3 + (1)^2 + 3(1) - 8 = 2 + 1 + 3 - 8 = -2 \]. So, \( f(1) = -2 \).
03
Calculate the first derivative \( f'(x) \) and evaluate at \( x = a \)
Find the first derivative: \( f'(x) = 6x^2 + 2x + 3 \). Substitute \( x = 1 \) to get \( f'(1) = 6(1)^2 + 2(1) + 3 = 6 + 2 + 3 = 11 \). Thus, \( f'(1) = 11 \).
04
Calculate the second derivative \( f''(x) \) and evaluate at \( x = a \)
Find the second derivative: \( f''(x) = 12x + 2 \). Calculate \( f''(1) = 12(1) + 2 = 14 \). Hence, \( f''(1) = 14 \).
05
Calculate the third derivative \( f'''(x) \) and evaluate at \( x = a \)
The third derivative is \( f'''(x) = 12 \) (since it is a constant). So, \( f'''(1) = 12 \).
06
Substitute into the Taylor series formula and compute terms
The Taylor series expansion of \( f(x) \) around \( x = 1 \) is: \[ f(x) \approx f(1) + f'(1)(x-1) + \frac{f''(1)}{2!} (x-1)^2 + \frac{f'''(1)}{3!} (x-1)^3 \].Substituting the values:\[ -2 + 11(x-1) + \frac{14}{2} (x-1)^2 + \frac{12}{6} (x-1)^3 = -2 + 11(x-1) + 7(x-1)^2 + 2(x-1)^3 \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Functions
Polynomial functions are mathematical expressions involving a sum of powers in one or more variables multiplied by coefficients. In a single-variable polynomial, the function is typically expressed as a sequence of terms like \(a_n x^n + a_{n-1} x^{n-1} + \dots + a_1 x + a_0\), where each term has a coefficient \(a_i\) and a non-negative integer power of \(x\), known as the degree. The highest exponent in the polynomial dictates the degree of the polynomial. Here are some important points about polynomial functions:
- The degree of a polynomial gives us an idea about the shape and end behavior of its graph.
- Polynomial functions are smooth and continuous, meaning there are no sharp turns or holes in their graphs.
- The coefficients of a polynomial can be any real number, and these numbers impact the position and orientation of the graph.
Derivatives
Derivatives represent the rate of change of a function concerning its variable. For a polynomial function, each term of the function is differentiated according to the power rule. Here's how derivatives influence the behavior of polynomial functions:
- The first derivative, \(f'(x)\), provides information about the slope of the tangent to the curve at any point and helps in identifying increasing or decreasing behavior.
- The second derivative, \(f''(x)\), informs us about the concavity of the graph, indicating whether the graph is curving upwards or downwards at a given point.
- Higher-order derivatives become progressively more straightforward for polynomials due to reducing powers and eventually reaching constant values.
Series Expansion
Series expansion is a method to represent functions as infinite sums of terms calculated from the function's derivatives at a single point. The Taylor series is a type of series expansion centered on a point \(x = a\), allowing approximation of functions around that point using derivatives.
This is especially useful as it transforms complex functions into manageable polynomial forms that approximate the original function within a certain range. The Taylor series formula is:
\[\sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!} (x-a)^n\]
Here is how each component fits into the picture:
This is especially useful as it transforms complex functions into manageable polynomial forms that approximate the original function within a certain range. The Taylor series formula is:
\[\sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!} (x-a)^n\]
Here is how each component fits into the picture:
- \(f^{(n)}(a)\) are the derivatives of the function evaluated at the point \(a\).
- \((x-a)^n\) represents the power series about the center \(x = a\).
- \(n!\) is the factorial of \(n\), used to normalize each term of the series.