Chapter 11: Problem 14
Which of the series in Exercises \(1-26\) converge, and which diverge? Give reasons for your answers. (When checking your answers, remember there may be more than one way to determine a series' convergence or divergence.) $$ \sum_{n=1}^{\infty}\left(\frac{1}{n}-\frac{1}{n^{2}}\right)^{n} $$
Short Answer
Expert verified
The series converges.
Step by step solution
01
Understanding the Series
The given series is \( \sum_{n=1}^{\infty} \left( \frac{1}{n} - \frac{1}{n^2} \right)^{n} \). We need to determine if the series converges or diverges, which requires examining the behavior of the terms \( a_n = \left( \frac{1}{n} - \frac{1}{n^2} \right)^{n} \) as \( n \) becomes very large.
02
Simplifying the Terms
Consider the term \( a_n = \left( \frac{1}{n} - \frac{1}{n^2} \right)^n \). We can simplify the inside of the parentheses to \( \frac{1}{n} (1 - \frac{1}{n}) \), thus the term becomes:\[ a_n = \left( \frac{1}{n} \right)^n (1 - \frac{1}{n})^n = \frac{1}{n^n} (1 - \frac{1}{n})^n \]
03
Applying Exponential Limits
Recognize that \( (1 - \frac{1}{n})^n \) approaches \( e^{-1} \) as \( n \to \infty \). Using this, the term \( a_n \) becomes:\[ a_n \approx \frac{e^{-1}}{n^n} \] As \( n \) increases, \( \frac{1}{n^n} \) rapidly approaches zero, being much smaller than \( e^{-1} \).
04
Testing for Convergence (Ratio Test)
Use the Ratio Test for terms \( a_n \) in the series. Calculate:\[ \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| = \lim_{n \to \infty} \left| \frac{\left( \frac{1}{n+1} - \frac{1}{(n+1)^2} \right)^{n+1}}{\left( \frac{1}{n} - \frac{1}{n^2} \right)^n} \right| \]Analyzing these terms shows that the ratio decreases rapidly to zero, confirming the series' convergence.
05
Conclusion
The series \( \sum_{n=1}^{\infty} \left( \frac{1}{n} - \frac{1}{n^2} \right)^{n} \) converges. The Ratio Test indicates that the ratio of successive terms \( a_{n+1}/a_n \) approaches zero, implying that the series terms decrease fast enough to ensure convergence.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ratio Test
The Ratio Test is a popular method for determining whether an infinite series converges or diverges. It works by examining the ratio of consecutive terms in a given series. To apply the Ratio Test, consider a series with terms \( a_n \). We calculate the limit:
- \( \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| \)
- less than 1, the series converges.
- greater than 1, the series diverges.
- equal to 1, the test is inconclusive; another method must be used to confirm convergence or divergence.
Exponential Limits
Exponential limits are a key concept in calculus, often used to simplify the analysis of sequences and series. In the context of series convergence, exponential limits help us evaluate how rapidly a function approaches zero or infinity.For example, recognize the pattern:
- \( (1 - \frac{1}{n})^n \) approaches \( e^{-1} \) as \( n \to \infty \)
Term Behavior Analysis
Term behavior analysis involves studying how the individual terms of a series behave as \( n \) increases. It's a foundational component in deciding whether a series will converge. In practice, this means looking at the term's composition to see if it decreases or has specific features.Consider the series \( \sum_{n=1}^{\infty} \left( \frac{1}{n} - \frac{1}{n^2} \right)^n \):
- The term \( a_n = \frac{e^{-1}}{n^n} \) as simplified implies that each \( a_n \) becomes extremely small as \( n \) gets larger.