Chapter 10: Problem 41
Replace the polar equations in Exercises \(23-48\) by equivalent Cartesian equations. Then describe or identify the graph. $$ r^{2}=-4 r \cos \theta $$
Short Answer
Expert verified
The graph is a circle with center (-2, 0) and radius 2.
Step by step solution
01
Understand the Polar Equation
The given polar equation is \( r^2 = -4r \cos \theta \). Our goal is to convert this to a Cartesian form and identify the graph. We know the relationships between polar and Cartesian coordinates: \( x = r \cos \theta \) and \( y = r \sin \theta \).
02
Apply Conversion Formulas
Using the conversion formulas, express \( r \cos \theta \) as \( x \). Substitute \( x \) into the equation to yield: \[ r^2 = -4x \].
03
Replace \( r^2 \) with Cartesian Variables
Recall that \( r^2 = x^2 + y^2 \) in Cartesian coordinates. Substitute \( r^2 \) with \( x^2 + y^2 \) to form the equation: \[ x^2 + y^2 = -4x \].
04
Rearrange for Completion of Square
Move \( -4x \) to the left side to obtain \( x^2 + y^2 + 4x = 0 \). To complete the square for the \( x \)-terms, rewrite \( x^2 + 4x \) as \((x+2)^2 - 4\). So the equation becomes: \( (x+2)^2 - 4 + y^2 = 0 \).
05
Complete the Square and Simplify
Simplify the equation by adding 4 to both sides to remove the negative term: \((x+2)^2 + y^2 = 4\). This is the equation of a circle with center \((-2, 0)\) and radius 2.
06
Identify the Graph
Based on the equation \((x+2)^2 + y^2 = 4\), the graph is a circle centered at \((-2, 0)\) with a radius of 2.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Coordinates
Polar coordinates provide a unique way to describe the position of a point on a plane. Instead of using the traditional Cartesian coordinate system, which uses a pair of numbers to specify a point's location in terms of horizontal and vertical distances from an origin, polar coordinates utilize a different approach.
The mathematical relationships between polar coordinates \((r, \theta)\) and Cartesian coordinates \((x, y)\) are defined as:
- The first coordinate, often noted as \( r \), represents the radial distance from the origin (the pole).
- The second coordinate, \( \theta \), indicates the angle from the positive x-axis in a counter-clockwise direction.
The mathematical relationships between polar coordinates \((r, \theta)\) and Cartesian coordinates \((x, y)\) are defined as:
- \( x = r \cos \theta \)
- \( y = r \sin \theta \)
Cartesian Coordinates
The Cartesian coordinate system is a widely used framework for describing the positions of points on a plane. It utilizes two perpendicular axes: the x-axis (horizontal) and the y-axis (vertical). Each ordered pair \((x, y)\) represents a unique point in this two-dimensional space.
In order to convert from polar coordinates to Cartesian coordinates, use substitutions based on trigonometric identities:
In order to convert from polar coordinates to Cartesian coordinates, use substitutions based on trigonometric identities:
- \( x = r \cos \theta \)
- \( y = r \sin \theta \)
- \( r^2 = x^2 + y^2 \)
Completing the Square
Completing the square is an algebraic technique often used to simplify equations, revealing hidden geometrical properties such as the center and radius of a circle.It involves rewriting a quadratic equation in a way that makes it easy to identify squares and solve or simplify further.
In the equation \( x^2 + y^2 + 4x = 0 \), completing the square focuses on the "\( x^2 + 4x \)" terms:
In the equation \( x^2 + y^2 + 4x = 0 \), completing the square focuses on the "\( x^2 + 4x \)" terms:
- Add and subtract the square of half the coefficient of \( x \), which is \( 2^2 = 4 \).
- This transforms \( x^2 + 4x \) into \( (x+2)^2 - 4 \).
Equation of a Circle
The equation of a circle in standard form provides clear insights about its geometry: \( (x-h)^2 + (y-k)^2 = r^2 \) where \( (h, k) \) is the center of the circle, and \( r \) is the radius.
From the problem and using completing the square, we derived \( (x+2)^2 + y^2 = 4 \), which uses the standard equation form for circles.
From the problem and using completing the square, we derived \( (x+2)^2 + y^2 = 4 \), which uses the standard equation form for circles.
- The term \( (x+2)^2 \) indicates a horizontal shift, moving the circle’s center to \( (-2, 0) \).
- \( y^2 \) indicates that there isn't any vertical shifting, keeping the center at zero on the y-axis.
- The radius, \( r \), comes from \( r^2 = 4 \), thus \( r = 2 \).