Chapter 10: Problem 28
Find polar equations for the circles in Exercises \(21-28 .\) Sketch each circle in the coordinate plane and label it with both its Cartesian and polar equations. $$ x^{2}+y^{2}-\frac{4}{3} y=0 $$
Short Answer
Expert verified
The Cartesian equation is \(x^2 + (y-\frac{2}{3})^2 = (\frac{2}{3})^2\), and the polar equation is \(r = \frac{4}{3}\sin\theta\).
Step by step solution
01
Rearrange the Expression
Start with the given Cartesian equation: \[ x^2 + y^2 - \frac{4}{3} y = 0 \]Rearrange it to group the terms involving \(y\) on one side. This becomes: \[ x^2 + y^2 = \frac{4}{3} y \]
02
Completing the Square
To express the equation in a standard circle form, complete the square for the \(y\) terms.The equation becomes:\[ x^2 + \left(y^2 - \frac{4}{3}y\right) = 0 \]To complete the square, take half of the coefficient of \(y\), square it, and add and subtract it within the parentheses. Here, half of \(\frac{4}{3}\) is \(\frac{2}{3}\), so squaring gives \(\frac{4}{9}\):\[ x^2 + \left(y^2 - \frac{4}{3}y + \frac{4}{9} - \frac{4}{9}\right) = 0 \]\[ x^2 + \left(y - \frac{2}{3}\right)^2 - \frac{4}{9} = 0 \]
03
Simplify the Equation
Add \(\frac{4}{9}\) to both sides to simplify and isolate the completed square:\[ x^2 + \left(y - \frac{2}{3}\right)^2 = \frac{4}{9} \]This is now in the standard form of a circle, \[(x - h)^2 + (y - k)^2 = r^2 \] where \((h, k)\) is the center and \(r\) the radius.
04
Identifying Circle Parameters
From the equation above:- The center \((h, k)\) is \((0, \frac{2}{3})\)- The radius \(r\) is \(\sqrt{\frac{4}{9}} = \frac{2}{3}\).The Cartesian equation of the circle is \[ x^2 + (y - \frac{2}{3})^2 = \left(\frac{2}{3}\right)^2 \].
05
Convert to Polar Coordinates
In polar coordinates, the relationships are:\[ x = r\cos\theta \] \[ y = r\sin\theta \]Substitute these into the original equation:\[ (r\cos\theta)^2 + (r\sin\theta)^2 = \frac{4}{3}(r\sin\theta) \]Simplify using \(r^2 = r\sin\theta\) equation:\[ r = \frac{4}{3}\sin\theta \]This is the polar equation of the circle.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Completing the Square
Completing the square is a technique used to transform a quadratic expression into a perfect square trinomial, making it easier to work with, particularly for identifying the features of conic sections like circles. This method is essential when rearranging a quadratic equation into its standard form. Here's how it works:
- Identify the quadratic terms that require completion: any expression involving a square term, such as in our given exercise with the terms involving "nSafeguarding salad containersx^2" and "y2".
- Focus on the term linear in one variable (such as \(y\) in this exercise): take half of its coefficient and square it.For example, with the term \(\frac{4}{3}y\), half of \frac{4}{3}\( is \frac{2}{3}\), and squaring this gives \frac{4}{9}$.
- Add and subtract this squared term within the equation to maintain equality, allowing us to re-group and create a perfect square trinomial.
Cartesian Coordinates
Cartesian coordinates use a simple grid of horizontal (
x
-axis) and vertical (
y
-axis) lines to plot points in space. This system relies on two values
$(x, y)$ to determine a precise location in a flat plane. In the context of our given circle equation, the Cartesian coordinates enable us to visually represent the circle and understand geometric relationships more deeply.
- $x$ represents the horizontal position; greater values indicate movement to the right.
- $y$ represents the vertical position, with higher values indicating movement upwards.
Polar Coordinates
Polar coordinates provide an alternative to Cartesian coordinates, focusing instead on the angle (\theta) and distance (\(r\)) from a central point (the pole). This method is particularly useful when dealing with circular shapes or angles.
- The angle ( \theta) is measured from the positive x-axis, moving counterclockwise.
- The radius ( r) represents the length of a line from the origin to a given point.
Circle Equations
Circle equations in mathematics define the set of all points that are a certain distance from a given point, known as the circle's center. The essential form for a circle equation comes in two main varieties based on coordinate systems:
- Cartesian Form: With an equation like \( (x-h)^2 + (y-k)^2 = r^2\), you can easily identify the circle's center \((h, k)\) and radius \(r\).
- Polar Form: This leverages the polar-coordinate system, resulting in an expression such as \(r = \frac{4}{3}\sin\theta\), focusing on radial distances and angular references.