/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 Graph the functions in Exercises... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Graph the functions in Exercises \(7-18 .\) What symmetries, if any, do the graphs have? Specify the intervals over which the function is increasing and the intervals where it is decreasing. $$ y=-\frac{1}{x^{2}} $$

Short Answer

Expert verified
The graph is symmetric about the y-axis, decreasing on \((- fty, 0)\) and \((0, fty)\).

Step by step solution

01

Understand the Function

The function given is \( y = -\frac{1}{x^2} \). This is a rational function where \( x^2 \) appears in the denominator with a negative sign in front of it. It's important to note that the function is undefined at \( x = 0 \).
02

Analyze Symmetry

A function is symmetric with respect to the y-axis if \( f(-x) = f(x) \) for all \( x \). Substitute \( -x \) into the function: \( y = -\frac{1}{(-x)^2} = -\frac{1}{x^2} \). We observe that \( f(-x) = f(x) \), indicating symmetry with respect to the y-axis.
03

Determine Intervals of Increase and Decrease

The function \( y = -\frac{1}{x^2} \) decreases as \( x \) moves away from zero in both the positive and negative directions because the value becomes more negative as \( |x| \) increases. To verify, calculate the derivative: \( y' = \frac{2}{x^3} \). The derivative is positive when \( x < 0 \) and negative when \( x > 0 \), indicating that the function decreases over \((-fty, 0)\) and \((0, fty)\).
04

Graph the Function

Graphing \( y = -\frac{1}{x^2} \), we see vertical asymptotes at \( x = 0 \) since the function shoots to negative infinity around \( x = 0 \). The graph is a downward opening curve in both \((-fty, 0)\) and \((0, fty)\), confirming that the function decreases on these intervals.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Symmetry
Function symmetry is an important concept when graphing rational functions like \( y = -\frac{1}{x^2} \). Symmetry makes it easier to understand how the graph behaves around the axes. For a function to be symmetric with respect to the y-axis, it must satisfy the condition \( f(-x) = f(x) \). This means that the graph on one side of the y-axis is a mirror image of the graph on the other side.
In this case, substituting \(-x\) into the function results in \( y = -\frac{1}{(-x)^2} = -\frac{1}{x^2} \). We observe that the expression remains unchanged, indicating y-axis symmetry. This type of symmetry shows that the behavior of the function at positive x values is mirrored at the negative x values. This insight simplifies the graphing process, offering a better visual understanding of how the function transforms over its domain.
Increasing and Decreasing Intervals
Identifying intervals where the function is increasing or decreasing provides a deeper insight into its behavior. For the function \( y = -\frac{1}{x^2} \), we find it is undefined at \( x = 0 \), but we can analyze the intervals \((-fty, 0)\) and \((0, fty)\).
The function decreases as the absolute value of \( x \) rises, either positively or negatively. This is because as \( |x| \) increases, the magnitude of \( -\frac{1}{x^2} \) becomes larger and thus more negative. Therefore, we say:
  • The function decreases over the interval \((-fty, 0)\)
  • The function also decreases over \((0, fty)\)
Thus, the entire function is decreasing in both intervals separated by the vertical asymptote at \( x = 0 \). This knowledge is useful for predicting how the graph dives toward negative infinity as \( x \) moves away from zero.
Derivative Analysis
Derivatives play a crucial role in determining where a function is increasing or decreasing. By analyzing the derivative, we gain insight into the function's slope at various points in its domain.
For \( y = -\frac{1}{x^2} \), the derivative is calculated as \( y' = \frac{2}{x^3} \). This derivative is positive when \( x < 0 \) and negative when \( x > 0 \). But note that being positive or negative here refers to the position of the graph rather than increase or decrease directions — which is an essential distinction.
As the derivative here shifts signs across \( x = 0 \), the function itself is entirely decreasing, meaning its downward slope becomes steeper as we move away from zero. From a derivative perspective, we conclude:
  • The negative slope of the function suggests a decreasing behavior
  • The change in sign at \( x = 0 \) accentuates the continuous decrease
Overall, derivative analysis confirms and complements the understanding of the graph and its decreasing intervals.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.