/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 a. Graph the functions \(f(x)=3 ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

a. Graph the functions \(f(x)=3 /(x-1)\) and \(g(x)=2 /(x+1)\) together to identify the values of \(x\) for which $$ \frac{3}{x-1}<\frac{2}{x+1} $$ b. Confirm your findings in part (a) algebraically.

Short Answer

Expert verified
\( x < -1 \) or \( x > 1 \). Algebra confirms \( x < -5 \) as part of this range.

Step by step solution

01

Understand the Functions

We have two functions, \( f(x) = \frac{3}{x-1} \) and \( g(x) = \frac{2}{x+1} \). Both are rational functions with vertical asymptotes due to division by zero at \( x = 1 \) for \( f(x) \) and \( x = -1 \) for \( g(x) \). We need to graph them both to compare their values visually.
02

Graph the Functions

Plot \( f(x) = \frac{3}{x-1} \) and \( g(x) = \frac{2}{x+1} \). Notice that \( f(x) \) has a vertical asymptote at \( x = 1 \), while \( g(x) \) has a vertical asymptote at \( x = -1 \). Observe the intersection points or regions where \( f(x) < g(x) \).
03

Identify Regions

From the graph, identify regions where the function \( f(x) \) is less than \( g(x) \). This typically occurs in intervals between the asymptotes and beyond them. Based on general graph behavior, this inequality holds when \( x < -1 \) or \( x > 1 \).
04

Algebraic Solution

Solve the inequality algebraically: \( \frac{3}{x-1} < \frac{2}{x+1} \). Start by cross-multiplying (assuming no division by zero): \( 3(x+1) < 2(x-1) \). This simplifies to \( 3x + 3 < 2x - 2 \). Solve for \( x \): \( x < -5 \).
05

Reconcile Graph and Algebra

Combine insights from both graphical and algebraic solutions. The inequality holds for \( x < -1 \) and {{\( x > 5 \)} - areas outside the influence of overlapped asymptotes. The algebra confirmed \( x < -5 \) within that \( x < -1 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphing Rational Functions
Rational functions are ratios of two polynomials, and graphing them can often reveal insights into their behavior. To graph the functions, consider their forms: \( f(x) = \frac{3}{x-1} \) and \( g(x) = \frac{2}{x+1} \). These functions indicate vertical asymptotes, as they become undefined where the denominator equals zero. For \( f(x) \), this happens at \( x = 1 \), and for \( g(x) \), at \( x = -1 \). Now, when you plot these, look for where the graphs intersect or diverge. This visual representation shows the values of \( x \) where \( f(x) \) is less than \( g(x) \). Typically, graphing reveals the relative positions and possible intersection points, helping solve inequalities visually. The key here is to focus on the behavior around the vertical asymptotes and observe how the functions behave as \( x \) approaches these critical points. By plotting, you might notice where one function dips below another.
Vertical Asymptotes
Vertical asymptotes are lines where a function's value grows infinitely large, either positively or negatively. This occurs in rational functions when the denominator is zero and the numerator is not zero at the same point. For the functions \( f(x) = \frac{3}{x-1} \) and \( g(x) = \frac{2}{x+1} \), the vertical asymptotes are at \( x = 1 \) and \( x = -1 \) respectively. These asymptotes act as significant boundaries for the function's graph. They separate regions where the function changes direction, going to infinity one way and negative infinity the other. When graphing these functions, always mark the vertical asymptotes. They break the x-axis into sections that help in understanding the inequality. Remember, the function doesn't touch or intersect an asymptote but gets extremely close. These key points provide insights on where you might typically compare or "jump" between functions when solving inequalities. A focus on asymptotes helps delineate where the functions are increasing or decreasing and how they align with each other.
Solving Inequalities Algebraically
Solving inequalities involving rational functions often requires careful algebraic manipulation alongside awareness of asymptotic behavior. Consider the inequality \( \frac{3}{x-1} < \frac{2}{x+1} \). A typical approach is to cross-multiply: assuming that neither side leads to division by zero. Cross-multiplication leads to \( 3(x+1) < 2(x-1) \). When simplified, this results in \( 3x + 3 < 2x - 2 \). Solving this equation for \( x \) gives \( x < -5 \). However, this algebraic step can miss constraints set by vertical asymptotes. In this case, consider when the original inequality holds across broader ranges identified from graphing. Thus, though algebra shows one solution, it's crucial to reconcile it with a graph. This combination shows the solution is not only \( x < -5 \) equating to \( x < -1 \) graphically, but also \( x > 1 \). Combining algebra with graphical insights ensures an answer that respects all constraints, highlighting sections outside the undefined regions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Industrial costs Dayton Power and Light, Inc., has a power plant on the Miami River where the river is 800 ft wide. To lay a new cable from the plant to a location in the city 2 mi downstream on the opposite side costs \(\$ 180\) per foot across the river and \(\$ 100\) per foot along the land. Graph cannot copy a. Suppose that the cable goes from the plant to a point \(Q\) on the opposite side that is \(x\) ft from the point \(P\) directly opposite the plant. Write a function \(C(x)\) that gives the cost of laying the cable in terms of the distance \(x\) . b. Generate a table of values to determine if the least expensive location for point \(Q\) is less than 2000 \(\mathrm{ft}\) or greater than 2000 \(\mathrm{ft}\) from point \(P .\)

Evaluate \(\sin \frac{7 \pi}{12}\) as \(\sin \left(\frac{\pi}{4}+\frac{\pi}{3}\right)\)

In Exercises \(67-70,\) you will explore graphically the general sine function $$f(x)=37 \sin \left(\frac{2 \pi}{365}(x-101)\right)+25$$ as you change the values of the constants \(A, B, C,\) and \(D .\) Use a CAS or computer grapher to perform the steps in the exercises. The horizontal shift \(C \quad\) Set the constants \(A=3, B=6, D=0\) a. Plot \(f(x)\) for the values \(C=0,1,\) and 2 over the interval \(-4 \pi \leq x \leq 4 \pi\) . Describe what happens to the graph of the general sine function as \(C\) increases through positive values. b. What happens to the graph for negative values of \(C ?\) c. What smallest positive value should be assigned to \(C\) so the graph exhibits no horizontal shift? Confirm your answer with a plot.

In Exercises \(1-6,\) find the domain and range of each function. $$ g(z)=\frac{1}{\sqrt{4-z^{2}}} $$

A cone problem Begin with a circular piece of paper with a 4 in. radius as shown in part (a). Cut out a sector with an arc length of \(x\) . Join the two edges of the remaining portion to form a cone with radius \(r\) and height \(h,\) as shown in part (b). Graph cannot copy a. Explain why the circumference of the base of the cone is \(8 \pi-x .\) b. Express the radius \(r\) as a function of \(x\) . c. Express the height \(h\) as a function of \(x\) . d. Express the volume \(V\) of the cone as a function of \(x\) .

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.