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My bank advertises a compound interest rate of \(2.4 \%\), although, without making deposits or withdrawals, the balance in my account increased by \(2.43 \%\) in one year.

Short Answer

Expert verified
We derived the formula needed to find the number of times the interest was compounded per year. However, due to its complexity, it needs to be solved using a numerical method or a calculator with numerical equation solving capability. The answer will thus heavily depend on the student's capabilities.

Step by step solution

01

Understand the relationship between compound and effective interest rates

We know that \( P = A / (1 + r/n)^{nt} \). Where \( P \) is the principal amount (initial investment), \( r \) is annual interest rate, \( n \) is the number of times that interest is compounded per year, and \( t \) is the time the money is invested for. In this case, we know the interest rate \( r \), the final amount after one year, which allows us to calculate \( A \) (since it increased by 2.43%), and \( t \) is 1 year. We are solving for \( n \).
02

Rearrange the formula to solve for n

To get \( n \) by itself, we will rearrange the formula to: \( n = \frac{ \log(A/P) } { rt \log(1 + r/n) } \). Now we can substitute our known values into the new equation to solve for \( n \).
03

Substitute values into the equation

We then substitute \( r = 0.024 \) (since it's 2.4%), \( t = 1 \) year, and using the fact that the account increased by 2.43%, giving us \( A/P = 1.0243 \). This leads to our equation becoming \( n = \frac{ \log(1.0243) } { 0.024 \log(1 + 0.024/n) } \)
04

Solve for n

We now need to solve the equation for \( n \). However, this is an equation that requires some form of numerical technique to solve, like using bisection method, newton's method or perhaps a calculator with numerical equation solving capability. Thus the solution will heavily depend on the capabilities of the student. We're not able to ultimately solve the equation in any further steps.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Effective Interest Rate
When a bank advertises a compound interest rate, it's important to distinguish this from the effective interest rate. The effective interest rate reflects the actual return on an investment, including compounding. It's the interest rate that would be needed to achieve the same final amount with simple interest, which is interest calculated only on the principal each period.

For instance, if a bank advertises a rate of 2.4% compounded annually, but your balance grows by 2.43% in one year, the effective interest rate is higher than the advertised rate due to the impact of compounding. The effective rate can be calculated using the formula: \[\text{Effective Interest Rate} = (1 + \frac{r}{n})^{n} - 1\] where \( r \) is the nominal interest rate and \( n \) is the number of compounding periods per year. Understanding this will better align your expectations with the actual growth of your investments.
Compound Interest Formula
The formula for compound interest is fundamental in understanding how investments grow over time. The compound interest formula is \[\text{Future Value} = P(1 + \frac{r}{n})^{nt}\] where \( P \) is the principal, \( r \) is the annual interest rate, \( n \) is the number of times interest is compounded per year, and \( t \) is the number of years invested.

This formula helps investors to calculate the amount of money they will have in the future, considering the effects of interest compounding at certain intervals. It's valuable because it demonstrates how money can grow at an increasing rate, as interest is earned on top of interest already accrued. As seen in the example, by manipulating this formula to solve for missing variables, you can uncover details like how often interest was compounded within a given period.
Numerical Methods in Finance
In finance, numerical methods are crucial for solving equations that are too complex for analytical solutions. These methods allow for approximations of roots or solutions of equations and are especially useful for dealing with compound interest problems where multiple compounding periods play a role.

Methods such as the bisection method, Newton-Raphson method, and fixed-point iteration are employed to find values that satisfy financial equations. These numerical techniques come in handy when you can't isolate a variable algebraically, as seen with the formula for compound interest when solving for the number of compounding periods \( n \). Understanding these methods is essential for financial analytics and modeling complex scenarios where simple algebra doesn't suffice.
Logarithmic Equations
Logarithmic equations are essential in finance for solving problems involving exponential relationships, such as those seen in compound interest calculations. By using logarithms, we can re-express multiplicative relationships as additive ones, making it possible to solve for unknown variables.

For example, rearranging the compound interest formula to solve for the number of compounding periods requires using logarithms to bring down the exponent. The equation \[\text{Number of periods}, \, n = \frac{\log(\frac{A}{P})}{\log(1 + \frac{r}{n})} \] involves logarithms to solve for \( n \). Mastery over logarithmic equations and properties of logarithms is indispensable when dealing with such financial equations, as it provides a powerful tool for dissecting complex exponential relationships in finance.

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Most popular questions from this chapter

In Exercises 25-30, round to the nearest dollar. Suppose that you earned a bachelor's degree and now you're teaching high school. The school district offers teachers the opportunity to take a year off to earn a master's degree. To achieve this goal, you deposit \(\$ 2000\) at the end of each year in an annuity that pays \(7.5 \%\) compounded annually. a. How much will you have saved at the end of 5 years? b. Find the interest.

Describe one advantage and one disadvantage of an adjustable-rate mortage over a fixed-rate mortgage.

In Exercises 1-10, \((n)\) a. Find the value of each annuity. Round to the nearest dollar. b. Find the interest. $$ \begin{array}{l|l|l} \$ 100 \text { at the end of } & 4.5 \% \text { compounded } & 25 \text { years } \\ \text { every six months } & \text { semiannually } & \\ \hline \end{array} $$

Make Sense? In Exercises 47-53, determine whether each statement makes sense or does not make sense, and explain your reasoning. By putting \(\$ 10\) at the end of each month into an annuity that pays \(3.5 \%\) compounded monthly, I'll be able to retire comfortably in just 30 years.

Exercises 19 and 20 refer to the stock tables for Goodyear (the tire company) and Dow Chemical given below. In each exercise, use the stock table to answer the following questions. Where necessary, round dollar amounts to the nearest cent. a. What were the high and low prices for a share for the past 52 weeks? b. If you owned 700 shares of this stock last year, what dividend did you receive? c. What is the annual return for the dividends alone? How does this compare to a bank offering a \(3 \%\) interest rate? d. How many shares of this company's stock were traded yesterday? e. What were the high and low prices for a share yesterday? f. What was the price at which a share last traded when the stock exchange closed yesterday? g. What was the change in price for a share of stock from the market close two days ago to yesterday's market close? h. Compute the company's annual earnings per share using Annual earnings per share $$ \begin{array}{|c|c|c|c|c|c|c|c|c|c|c|c|} \hline \text { 52-Week High } & \text { 52-Week Low } & \text { Stock } & \text { SYM } & \text { Div } & \text { Yld \% } & \text { PE } & \text { Vol 100s } & \text { Hi } & \text { Lo } & \text { Close } & \text { Net Chg } \\ \hline 73.25 & 45.44 & \text { Goodyear } & \text { GT } & 1.20 & 2.2 & 17 & 5915 & 56.38 & 54.38 & 55.50 & +1.25 \\ \hline \end{array} $$

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