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Chapter 7: Problem 47

Graph each horizontal or vertical line. \(x+1=0\)

Short Answer

Expert verified
The graph will be a vertical line that intersects the x-axis at -1.

Step by step solution

01

Solve the equation for \(x\)

By subtracting 1 from both sides of the equation \(x + 1 = 0\) to get the value of \(x\), you get \(x = -1\).
02

Determine the type of line

As given, the equation only has a single variable \(x\), hence it represents a vertical line.
03

Plot the line on a Cartesian Plane

Since \(x = -1\), find the line at position -1 on the x-axis, keeping in mind that this is a vertical line parallel to the y-axis. Thus, the line intersects the x-axis at \(-1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vertical Line
In a Cartesian Plane, a vertical line is a distinctive feature that runs parallel to the y-axis. When we encounter an equation like \(x = -1\), it signifies a vertical line. Here are some points to remember about vertical lines:
  • Vertical lines have a constant x-value. This means, no matter where you are on the line, the x-coordinate remains consistently -1 in this example.
  • Vertical lines do not have a defined slope. This is because slope is calculated using the change in y-values over the change in x-values. For a vertical line, the x-value does not change, leading to division by zero, which is undefined.
Understanding these characteristics is crucial when graphing such lines. Recognizing the pattern that lines of the form \(x = a\) are always vertical helps simplify graphing tasks.
Graphing Equations
Graphing equations involves plotting points that satisfy a given equation and connecting them to visualize the equation's structure. Here鈥檚 a simplified approach to graph vertical and horizontal lines:
  • For vertical lines, given by equations like \(x = a\), plot the line parallel to the y-axis at the specified x-value. For instance, \(x = -1\) would be a vertical line crossing the x-axis at -1.
  • For horizontal lines, represented by equations like \(y = b\), draw the line parallel to the x-axis at the specified y-value.
When graphing linear equations:
  • Identify the type of line based on the equation鈥檚 format.
  • Locate the intercept or constant value specified.
  • Draw the line through this intercept, ensuring it stays parallel to the respective axis.
Always pay attention to whether the equation involves x, y, or both, to correctly determine the line's orientation on the Cartesian Plane.
Solving Linear Equations
Solving linear equations is a foundational skill in mathematics. Let's delve into how to solve simple equations, similar to \(x + 1 = 0\):
  • Identify what you need to isolate. In the given equation, solve for x.
  • Perform algebraic operations, such as addition, subtraction, multiplication, or division, on both sides of the equation to isolate the variable. Here, subtract 1 from both sides to get \(x = -1\).
Once solved, interpret the solution:
  • The solution \(x = -1\) indicates that for all points on the graph, the x-value must equal -1.
  • This interpretation confirms the vertical nature of the line in the Cartesian Plane.
Understanding the steps in solving such equations aids in accurately graphing them and comprehending their geometrical implications on a graph.

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Most popular questions from this chapter

In Exercises 5-8, an objective function and a system of linear inequalities representing constraints are given. a. Graph the system of inequalities representing the constraints. b. Find the value of the objective function at each corner of the graphed region. c. Use the values in part (b) to determine the maximum value of the objective function and the values of \(x\) and \(y\) for which the maximum occurs. Objective Function $$ z=x+y $$ Constraints $$ \left\\{\begin{array}{l} x \leq 6 \\ y \geq 1 \\ 2 x-y \geq-1 \end{array}\right. $$

Graph the solution set of each system of inequalities. \(\left\\{\begin{array}{l}x+y \leq 4 \\ y \geq 2 x-4\end{array}\right.\)

In Exercises 29-30, find the vertex for the parabola whose equation is given by writing the equation in the form \(y=a x^{2}+b x+c\).\ \(y=(x-3)^{2}+2\)

Graph the solution set of each system of inequalities. \(\left\\{\begin{array}{l}y>2 x-3 \\ y<-x+6\end{array}\right.\)

Use the directions for Exercises 7-8 to graph each logarithmic function. Based on your graph, describe the shape of a scatter plot that can be modeled by \(f(x)=\log _{b} x, 0
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